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Category: Integration

Show-that-d-dy-g-1-y-g-2-y-f-x-y-dx-g-1-y-g-2-y-f-y-x-y-dx-g-2-y-f-g-2-y-y-g-1-y-f-g-1-y-y-using-Leibniz-s-rule-and-the-chain-rule-where-g-1-and-g-2-are-dif

Question Number 1602 by 112358 last updated on 25/Aug/15 $${Show}\:{that}\: \\ $$$$\frac{{d}}{{dy}}\int_{{g}_{\mathrm{1}} \left({y}\right)} ^{{g}_{\mathrm{2}} \left({y}\right)} {f}\left({x},{y}\right){dx}=\int_{{g}_{\mathrm{1}} \left({y}\right)} ^{{g}_{\mathrm{2}} \left({y}\right)} \frac{\partial{f}}{\partial{y}}\left({x},{y}\right){dx}+{g}_{\mathrm{2}} ^{'} \left({y}\right){f}\left({g}_{\mathrm{2}} \left({y}\right),{y}\right)−{g}_{\mathrm{1}} ^{'} \left({y}\right){f}\left({g}_{\mathrm{1}}…

Let-and-denote-functions-of-x-where-is-odd-and-is-even-x-R-Is-it-generally-true-that-integrating-an-odd-function-gives-an-even-function-and-vice-versa-1-x-dx-1-x-C-and-2-x-d

Question Number 1582 by 112358 last updated on 21/Aug/15 $${Let}\:\phi\:{and}\:\varepsilon\:{denote}\:{functions}\:{of}\:{x} \\ $$$${where}\:\phi\:{is}\:{odd}\:{and}\:\varepsilon\:{is}\:{even}\:\forall{x}\in\mathbb{R}. \\ $$$${Is}\:{it}\:{generally}\:{true}\:{that}\:{integrating} \\ $$$${an}\:{odd}\:{function}\:{gives}\:{an}\:{even} \\ $$$${function}\:{and}\:{vice}\:{versa}?\: \\ $$$$\int\phi_{\mathrm{1}} \left({x}\right)\:{dx}=\varepsilon_{\mathrm{1}} \left({x}\right)+{C}\:? \\ $$$${and}\:\int\phi_{\mathrm{2}} \left({x}\right){dx}=\varepsilon_{\mathrm{2}}…

find-the-area-abounded-y-x-afind-y-x-2-

Question Number 67106 by mhmd last updated on 22/Aug/19 $${find}\:{the}\:{area}\:{abounded}\:{y}=\sqrt{{x}} \\ $$$${afind}\:{y}={x}−\mathrm{2}? \\ $$ Commented by kaivan.ahmadi last updated on 24/Aug/19 $${x}−\mathrm{2}=\sqrt{{x}}\Rightarrow{x}^{\mathrm{2}} −\mathrm{5}{x}+\mathrm{4}=\mathrm{0}\Rightarrow\left({x}−\mathrm{1}\right)\left({x}−\mathrm{4}\right)=\mathrm{0}\Rightarrow \\ $$$$\begin{cases}{{x}=\mathrm{1}}\\{{x}=\mathrm{2}}\end{cases}…

sin-2-x-1-sin-2-x-dx-

Question Number 132610 by liberty last updated on 15/Feb/21 $$\Omega=\int\:\frac{\mathrm{sin}\:^{\mathrm{2}} \left(\mathrm{x}\right)}{\mathrm{1}+\mathrm{sin}\:^{\mathrm{2}} \left(\mathrm{x}\right)}\:\mathrm{dx}\: \\ $$ Answered by Dwaipayan Shikari last updated on 15/Feb/21 $$\int\frac{{sin}^{\mathrm{2}} {x}}{\mathrm{1}+{sin}^{\mathrm{2}} {x}}{dx}={x}−\int\frac{\mathrm{1}}{\mathrm{1}+{sin}^{\mathrm{2}}…

Question-67070

Question Number 67070 by mRDv143 last updated on 22/Aug/19 Commented by Prithwish sen last updated on 23/Aug/19 $$\int\frac{\mathrm{x}^{\mathrm{2}} −\mathrm{1}}{\left(\mathrm{x}+\mathrm{1}\right)^{\mathrm{2}} \:\sqrt{\mathrm{x}^{\mathrm{3}} +\mathrm{x}^{\mathrm{2}} +\mathrm{x}}}\:\mathrm{dx}=\int\frac{\mathrm{x}^{\mathrm{2}} −\mathrm{1}}{\left(\mathrm{x}+\mathrm{1}\right)^{\mathrm{2}} .\mathrm{x}\:\sqrt{\mathrm{x}+\frac{\mathrm{1}}{\mathrm{x}}+\mathrm{1}}}\:\mathrm{dx} \\…