Question Number 62220 by maxmathsup by imad last updated on 17/Jun/19 $${let}\:{f}\left({x}\right)\:=\int_{\mathrm{0}} ^{\infty} \:\:\:\:\:\:\:\frac{{t}^{\mathrm{2}} }{{x}^{\mathrm{6}} \:\:+{t}^{\mathrm{6}} }\:{dt}\:\:\:\:\:\:{with}\:{x}>\mathrm{0} \\ $$$$\left.\mathrm{1}\right)\:{calculate}\:{f}\left({x}\right) \\ $$$$\left.\mathrm{2}\right)\:{calculate}\:{g}\left({x}\right)\:=\int_{\mathrm{0}} ^{\infty} \:\:\:\:\frac{{t}^{\mathrm{2}} }{\left({x}^{\mathrm{6}} \:+{t}^{\mathrm{6}}…
Question Number 62213 by maxmathsup by imad last updated on 17/Jun/19 $${calculate}\:\int\int\int_{{D}} \:{e}^{−{x}^{\mathrm{2}} −{y}^{\mathrm{2}} } \sqrt{{x}^{\mathrm{2}} \:+{y}^{\mathrm{2}} \:+{z}^{\mathrm{2}} }{dxdydz}\:{with} \\ $$$${D}\:=\left\{\left({x},{y},{z}\right)\in{R}^{\mathrm{3}} \:/\:\:\:\mathrm{0}\leqslant{x}\leqslant\mathrm{1}\:,\:\mathrm{1}\leqslant{y}\leqslant\mathrm{2}\:\:{and}\:\:\:\mathrm{2}\leqslant{z}\leqslant\mathrm{3}\:\right\} \\ $$ Commented…
Question Number 62208 by maxmathsup by imad last updated on 17/Jun/19 $${find}\:{f}\left({a}\right)\:=\int\:\:\left({x}−{a}\right)\sqrt{{x}^{\mathrm{2}} \:+{a}^{\mathrm{2}} }{dx} \\ $$ Commented by maxmathsup by imad last updated on 18/Jun/19…
Question Number 62209 by maxmathsup by imad last updated on 17/Jun/19 $${find}\:{g}\left({a}\right)\:=\int\left({x}+{a}\right)\sqrt{{x}^{\mathrm{2}} −{a}^{\mathrm{2}} }{dx}\: \\ $$ Commented by maxmathsup by imad last updated on 18/Jun/19…
Question Number 62207 by maxmathsup by imad last updated on 17/Jun/19 $${calculate}\:\int\:\:\:\:\:\:\frac{{x}+\mathrm{3}}{\left({x}−\mathrm{2}\right)\sqrt{{x}^{\mathrm{2}} +{x}+\mathrm{1}}}\:{dx} \\ $$ Commented by maxmathsup by imad last updated on 18/Jun/19 $${I}\:=\int\:\frac{{x}−\mathrm{2}\:+\mathrm{5}}{\left({x}−\mathrm{2}\right)\sqrt{{x}^{\mathrm{2}}…
Question Number 62203 by maxmathsup by imad last updated on 17/Jun/19 $${calculate}\:\int\int_{\left[\mathrm{0},\mathrm{2}\right]^{\mathrm{2}} } \:\:\:\:\frac{{arctan}\left(\sqrt{{x}^{\mathrm{2}} +{y}^{\mathrm{2}} }\right)}{\mathrm{3}−\sqrt{{x}^{\mathrm{2}} +{y}^{\mathrm{2}} }}{dxdy} \\ $$ Commented by maxmathsup by imad…
Question Number 62201 by maxmathsup by imad last updated on 17/Jun/19 $${calculate}\:\int\int_{{W}} \:\:{e}^{{x}−\mathrm{2}{y}} {sin}\left({x}+\mathrm{2}{y}\right)\:{dxdy} \\ $$$${W}\:=\left\{\left({x},{y}\right)^{\mathrm{2}} /\:\:\mathrm{0}\leqslant{x}\leqslant\mathrm{1}\:\:{and}\:\:\mathrm{2}\leqslant{y}\leqslant\sqrt{\mathrm{5}}\right\} \\ $$ Commented by mathmax by abdo last…
Question Number 62198 by maxmathsup by imad last updated on 17/Jun/19 $${find}\:\int\int_{\left[\mathrm{0},\mathrm{1}\right]} \:\:\:\:\frac{{x}^{\mathrm{2}} −{y}^{\mathrm{2}} }{\mathrm{3}−\sqrt{{x}^{\mathrm{2}} +{y}^{\mathrm{2}} }}\:{dxdy}\:. \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 127732 by aseer imad last updated on 01/Jan/21 $${z}={x}+{iy} \\ $$$${why}\:\frac{{f}\left({z}\right)}{{z}−{a}}\:{not}\:{analytical}?\:/\:{not}\:{analytical}\:{at}\:{z}={a}? \\ $$$$ \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 62196 by maxmathsup by imad last updated on 17/Jun/19 $${calculate}\:\int_{\mathrm{0}} ^{\infty} \:\frac{{ln}\left(\mathrm{2}+{e}^{−{t}^{\mathrm{2}} } \right)}{{t}^{\mathrm{2}} \:+\mathrm{3}}{dt} \\ $$ Commented by mathmax by abdo last…