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Category: Integration

dx-csc-x-sec-x-

Question Number 132192 by benjo_mathlover last updated on 12/Feb/21 dxcscx+secx Answered by Dwaipayan Shikari last updated on 12/Feb/21 sinxcosxsinx+cosxdx=12sinx+cosx1sinx+cosxdx$$=\frac{\mathrm{1}}{\mathrm{2}}\left({sinx}−{cosx}\right)−\int\frac{{dt}}{\mathrm{1}−{t}^{\mathrm{2}}…