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Category: Integration

consider-the-space-Pn-with-H-f-f-Pn-and-0-1-f-x-x-0-Show-that-H-is-a-SUBSPACE-of-Pn-

Question Number 61842 by psyche last updated on 10/Jun/19 $$\boldsymbol{{consider}}\:\boldsymbol{{the}}\:\boldsymbol{{space}}\:\boldsymbol{{P}}{n}\:\boldsymbol{{with}}\:\boldsymbol{{H}}=\left\{{f}:{f}\subset{Pn}\:\boldsymbol{{and}}\:\int_{\mathrm{0}} ^{\mathrm{1}} {f}\left({x}\right)\partial{x}=\mathrm{0}\right\}\:.\:{S}\boldsymbol{{how}}\:\boldsymbol{{that}}\:\boldsymbol{{H}}\:\boldsymbol{{is}}\:\boldsymbol{{a}}\:\boldsymbol{{S}}{UBSPACE}\:{of}\:{Pn}. \\ $$ Commented by arcana last updated on 10/Jun/19 $$\mathrm{define}\:\mathrm{P}_{{n}} \\ $$ Terms…

advanced-calculus-prove-1023-134-0-x-2-5-x-2-5-1-x-2-1-1024x-2-dx-pi-golden-ratio-

Question Number 127370 by mnjuly1970 last updated on 29/Dec/20 $$\:\:\:\:\:\:\:\:\:…\:\:{advanced}\:\:{calculus}\:\:.. \\ $$$$\:\:{prove}:: \\ $$$$\:\:\:\frac{\mathrm{1023}}{\mathrm{134}}\int_{\mathrm{0}} ^{\:\infty} \frac{{x}^{\frac{\mathrm{2}}{\mathrm{5}}} +{x}^{\frac{−\mathrm{2}}{\mathrm{5}}} }{\left(\mathrm{1}+{x}^{\mathrm{2}} \right)\left(\mathrm{1}+\mathrm{1024}{x}^{\mathrm{2}} \right)}{dx}=\frac{\pi}{\varphi} \\ $$$$\:\:\:\varphi:\:{golden}\:\:{ratio}… \\ $$$$ \\…

tan-x-tan-2-x-1-dx-

Question Number 127368 by I want to learn more last updated on 29/Dec/20 $$\int\:\frac{\sqrt{\mathrm{tan}\:\mathrm{x}}}{\:\sqrt{\mathrm{tan}^{\mathrm{2}} \mathrm{x}\:\:−\:\:\mathrm{1}}}\:\:\mathrm{dx} \\ $$ Answered by liberty last updated on 29/Dec/20 $$\:{let}\:\rightarrow\begin{cases}{\mathrm{tan}\:{x}\:\geqslant\mathrm{0}}\\{\mathrm{tan}^{\mathrm{2}}…

dx-1-x-2-1-x-2-

Question Number 127355 by bemath last updated on 29/Dec/20 $$\:\int\:\frac{{dx}}{\left(\mathrm{1}+{x}^{\mathrm{2}} \right)\sqrt{\mathrm{1}−{x}^{\mathrm{2}} }}\:=?\: \\ $$ Answered by liberty last updated on 29/Dec/20 $$\:{I}=\int\:\frac{{dx}}{\left(\mathrm{1}+{x}^{\mathrm{2}} \right)\sqrt{\mathrm{1}−{x}^{\mathrm{2}} }}\:;\:\left[\:{x}\:=\:\mathrm{sin}\:{h}\:\right]\: \\…

Question-61809

Question Number 61809 by aliesam last updated on 09/Jun/19 Commented by maxmathsup by imad last updated on 10/Jun/19 $${let}\:{A}\:=\int_{\mathrm{0}} ^{\mathrm{1}} \:\:\:\frac{{x}^{{n}} }{\:\sqrt{{ln}\left({x}\right)}}\:{dx}\:\Rightarrow\:{A}\:=\:\int_{\mathrm{0}} ^{\mathrm{1}} \:\frac{{x}^{{n}} }{\:\sqrt{−\left(−{lnx}\right)}}\:{dx}\:=\frac{\mathrm{1}}{\:\sqrt{−\mathrm{1}}}\:\int_{\mathrm{0}}…