Question Number 127237 by bramlexs22 last updated on 28/Dec/20 $$\:{Nice}…\int\:\frac{\sqrt{\mathrm{1}−\mathrm{ln}\:^{\mathrm{2}} \left({x}\right)}}{{x}\:\mathrm{ln}\:\left({x}\right)}\:{dx}\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\int\:\sqrt{\frac{{x}}{\mathrm{1}−{x}^{\mathrm{3}} }}\:{dx}\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\int\:\sqrt{\frac{\mathrm{4}−{x}}{{x}}}\:{dx}\: \\ $$ Commented by bramlexs22 last updated on 28/Dec/20…
Question Number 192770 by ajfour last updated on 26/May/23 Commented by a.lgnaoui last updated on 26/May/23 $$\mathrm{question}\:\mathrm{not}\:\mathrm{clear}\: \\ $$ Commented by a.lgnaoui last updated on…
Question Number 127224 by mnjuly1970 last updated on 28/Dec/20 $$\:\:…\:{calculus}\:\:\left({I}\right)\:−{complex}\:{analysis}… \\ $$$$\:\:\:\:{calculate}\:::\: \\ $$$$\:\:\Phi\:=\:\int_{\mathrm{0}} ^{\:\infty} \frac{{ln}\left({x}\right)}{{x}^{\mathrm{2}} +\mathrm{3}{x}+\mathrm{2}}\:{dx}=\frac{{ln}^{\mathrm{2}} \left(\mathrm{2}\right)}{\mathrm{2}} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\: \\ $$ Answered by mindispower…
Question Number 61674 by behi83417@gmail.com last updated on 06/Jun/19 $$\mathrm{a}.\underset{\:\:\:\mathrm{0}} {\overset{\:\:\:\:\:\:\:\frac{\boldsymbol{\pi}}{\mathrm{4}}} {\int}}\sqrt{\mathrm{1}+\boldsymbol{\mathrm{tgx}}}\:\boldsymbol{\mathrm{dx}}=? \\ $$$$\mathrm{b}.\underset{\:\:\mathrm{0}} {\overset{\:\:\:\:\:\:\:\:\mathrm{1}} {\int}}\sqrt{\mathrm{1}+\boldsymbol{\mathrm{lnx}}}\:\boldsymbol{\mathrm{dx}}=? \\ $$ Commented by maxmathsup by imad last updated…
Question Number 61667 by aliesam last updated on 06/Jun/19 $$\int\sqrt{{tan}\left({x}\right)}\:{dx}\: \\ $$ Answered by MJS last updated on 06/Jun/19 $$\int\sqrt{\mathrm{tan}\:{x}}{dx}= \\ $$$$\:\:\:\:\:\left[{t}=\sqrt{\mathrm{tan}\:{x}}\:\rightarrow\:{dx}=\mathrm{2cos}^{\mathrm{2}} \:{x}\:\sqrt{\mathrm{tan}\:{x}}{dt}\right] \\ $$$$=\mathrm{2}\int\frac{{t}^{\mathrm{2}}…
Question Number 61662 by maxmathsup by imad last updated on 06/Jun/19 $${calculate}\:\int_{−\frac{\pi}{\mathrm{4}}} ^{\frac{\pi}{\mathrm{4}}} \:\:\frac{{cosx}}{{e}^{\frac{\mathrm{1}}{{x}}} \:+\mathrm{1}}\:{dx}\: \\ $$ Commented by maxmathsup by imad last updated on…
Question Number 61661 by maxmathsup by imad last updated on 05/Jun/19 $$\left.\mathrm{1}\right)\:{calculate}\:\int\int_{{R}^{+^{\mathrm{2}} } } \:\:\:\:\:\frac{{dxdy}}{\left(\mathrm{1}+{x}^{\mathrm{2}} \right)\left(\mathrm{1}+{y}^{\mathrm{2}} \right)} \\ $$$$\left.\mathrm{2}\right)\:{find}\:{the}\:{value}\:{of}\:\int_{\mathrm{0}} ^{\infty} \:\frac{{ln}\left({x}\right)}{{x}^{\mathrm{2}} −\mathrm{1}}\:{dx}\:. \\ $$ Commented…
Question Number 61660 by maxmathsup by imad last updated on 05/Jun/19 $${let}\:{U}_{{n}} =\:\int_{\mathrm{0}} ^{\infty} \:\:\:\:\frac{{dt}}{\left(\mathrm{1}+{t}^{\mathrm{3}} \right)^{{n}} }\:{dt}\:\:\:\:\left({n}\geqslant\mathrm{1}\right) \\ $$$$\left.\mathrm{1}\right)\:{calculate}\:\frac{{U}_{{n}+\mathrm{1}} }{{U}_{{n}} } \\ $$$$\left.\mathrm{2}\right)\:{study}\:{the}\:{serie}\:\Sigma{ln}\left(\frac{{U}_{{n}+\mathrm{1}} }{{U}_{{n}} }\right)\:\:{and}\:{prove}\:\:{that}\:{lim}_{{n}\rightarrow+\infty}…
Question Number 127190 by bramlexs22 last updated on 27/Dec/20 $$\:\int\:\frac{\sqrt{{a}}−\sqrt{{x}}}{\mathrm{1}−\sqrt{{ax}}}\:{dx}\:=?\:;\:{a}>\mathrm{0} \\ $$ Answered by Dwaipayan Shikari last updated on 27/Dec/20 $$\Rightarrow{ax}={u}^{\mathrm{2}} \Rightarrow{a}=\mathrm{2}{u}\frac{{du}}{{dx}} \\ $$$$\mathrm{2}\int\frac{\sqrt{{a}}−\frac{{u}}{\:\sqrt{{a}}}}{\mathrm{1}−{u}}.\frac{{u}}{{a}}{du}\:=\:\frac{\mathrm{2}}{\:\sqrt{{a}^{\mathrm{3}} }}\int\frac{{a}−{u}}{\mathrm{1}−{u}}{du}=\frac{\mathrm{2}}{\:\sqrt{{a}^{\mathrm{3}}…
Question Number 61654 by aliesam last updated on 05/Jun/19 $$\int_{\mathrm{0}} ^{\infty} {e}^{−{e}^{{x}} } {ln}\left({x}\right)\:{dx}\:=\:\mathrm{0}.\mathrm{27634} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com