Question Number 106175 by john santu last updated on 03/Aug/20 $$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{\sqrt{\mathrm{x}}−\sqrt{\mathrm{sin}\:\mathrm{x}}}{\mathrm{x}^{\mathrm{2}} \sqrt{\mathrm{x}}}\:=\:? \\ $$ Answered by bemath last updated on 03/Aug/20 $$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{\sqrt{\mathrm{x}}−\sqrt{\mathrm{x}−\frac{\mathrm{x}^{\mathrm{3}} }{\mathrm{6}}}}{\mathrm{x}^{\mathrm{2}}…
Question Number 171706 by Haisokheng last updated on 20/Jun/22 Answered by cortano1 last updated on 20/Jun/22 Answered by thfchristopher last updated on 20/Jun/22 $$\underset{{x}\rightarrow\mathrm{1}} {\mathrm{lim}}\frac{\mathrm{1}−{x}^{\mathrm{3}}…
Question Number 171705 by Haisokheng last updated on 20/Jun/22 Answered by puissant last updated on 20/Jun/22 $$=\:\frac{\mathrm{1}}{\pi}\int_{\mathrm{0}} ^{\pi} {cos}^{\mathrm{2}} \left(\mathrm{2}{x}\right){dx} \\ $$$$=\frac{\mathrm{1}}{\mathrm{2}\pi}\int_{\mathrm{0}} ^{\pi} \mathrm{1}+{cos}\left(\mathrm{4}{x}\right){dx} \\…
Question Number 106152 by bemath last updated on 03/Aug/20 $$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\mathrm{1}−\mathrm{cos}\:\mathrm{xcos}\:\mathrm{2xcos}\:\mathrm{3x}…\mathrm{cos}\:\mathrm{nx}}{\mathrm{x}^{\mathrm{n}} } \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 106101 by O Predador last updated on 02/Aug/20 Answered by Dwaipayan Shikari last updated on 02/Aug/20 $$\underset{{x}\rightarrow\infty} {\mathrm{lim}}\frac{\sqrt{\mathrm{2}+\frac{\mathrm{1}}{{x}}}−\frac{\mathrm{3}}{\:\sqrt{{x}}}}{\:\sqrt{\mathrm{1}−\frac{\mathrm{2}}{{x}}}−\frac{\sqrt{\mathrm{2}}}{\:\sqrt{{x}}}}=\frac{\sqrt{\mathrm{2}}}{\:\sqrt{\mathrm{1}}}=\sqrt{\mathrm{2}} \\ $$ Commented by O…
Question Number 106070 by bemath last updated on 02/Aug/20 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 106072 by bemath last updated on 02/Aug/20 Answered by bobhans last updated on 02/Aug/20 $$\underset{{x}\rightarrow\pi/\mathrm{2}} {\mathrm{lim}}\:\frac{\sqrt{\mathrm{2sin}\:^{\mathrm{2}} \mathrm{x}+\mathrm{3sin}\:\mathrm{x}+\mathrm{4}}}{\mathrm{cot}\:^{\mathrm{2}} \mathrm{x}}\:= \\ $$$$\mathrm{set}\:\mathrm{x}\:=\:\frac{\pi}{\mathrm{2}}+\mathrm{h}\:\Rightarrow\underset{\mathrm{h}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\mathrm{3}}{\mathrm{cot}\:^{\mathrm{2}} \left(\mathrm{h}+\frac{\pi}{\mathrm{2}}\right)}\:= \\…
Question Number 40504 by prof Abdo imad last updated on 23/Jul/18 $${let}\:{u}_{{n}} =\sum_{{k}=\mathrm{1}} ^{{n}} \:\:\frac{\mathrm{1}}{{n}^{\mathrm{2}} +{k}} \\ $$$${find}\:{lim}_{{n}\rightarrow+\infty} {n}\left\{\mathrm{1}−{n}\:{u}_{{n}} \right\}\:. \\ $$ Answered by tanmay.chaudhury50@gmail.com…
Question Number 105990 by Muhsang S L last updated on 02/Aug/20 $$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\left(\mathrm{cosec}\:^{\mathrm{2}} \mathrm{2}{x}\:−\:\frac{\mathrm{1}}{\mathrm{4}{x}^{\mathrm{2}} }\right)\:=\:? \\ $$ Answered by bemath last updated on 02/Aug/20 Terms…
Question Number 40426 by Tinkutara last updated on 21/Jul/18 Terms of Service Privacy Policy Contact: info@tinkutara.com