Question Number 170182 by mathlove last updated on 18/May/22 $$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\left[{x}\centerdot{sin}\frac{\mathrm{1}}{{x}}\right]=? \\ $$ Commented by mr W last updated on 18/May/22 $${has}\:\left[\:\:\right]\:{special}\:{meaning}?\:{or}\:{you}\:{just}\:{mean} \\ $$$$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\left({x}\centerdot{sin}\frac{\mathrm{1}}{{x}}\right)=?…
Question Number 170166 by sciencestudent last updated on 17/May/22 $${li}\underset{{x}\rightarrow\mathrm{0}} {{m}}\left(\frac{\mathrm{1}}{{sin}^{\mathrm{2}} {x}}−\frac{\mathrm{1}}{{x}^{\mathrm{2}} }\right)=? \\ $$$${please}\:{solve}\:{it}\:{describely}. \\ $$ Commented by mr W last updated on 17/May/22…
Question Number 170159 by mathlove last updated on 17/May/22 $$\underset{{x}\rightarrow\mathrm{4}} {\mathrm{lim}}\:\frac{{e}\:!{x}−\mathrm{24}}{\:\sqrt{{x}}−\mathrm{2}}=? \\ $$ Answered by Mathspace last updated on 18/May/22 $${hosital}\:\:{lim}={lim}_{{x}\rightarrow\mathrm{4}} \:\:\:\frac{{e}!}{\frac{\mathrm{1}}{\mathrm{2}\sqrt{{x}}}} \\ $$$$={lim}_{{x}\rightarrow\mathrm{4}} \:\mathrm{2}\left({e}\right)!\sqrt{{x}}…
Question Number 39078 by Cheyboy last updated on 02/Jul/18 $$\boldsymbol{{Without}}\:\boldsymbol{{using}}\:\boldsymbol{{l}}'\boldsymbol{{hopital}} \\ $$$$\boldsymbol{{find}}\:\:\:\:\underset{{x}\rightarrow\mathrm{3}} {\mathrm{lim}}\:\frac{\sqrt{\mathrm{9}−\boldsymbol{{x}}^{\mathrm{2}} }}{\boldsymbol{{x}}−\mathrm{3}} \\ $$$$ \\ $$ Commented by math khazana by abdo last…
Question Number 170141 by sciencestudent last updated on 17/May/22 $${li}\underset{{x}\rightarrow\mathrm{0}} {{m}}\left(\frac{\mathrm{1}}{{sin}^{\mathrm{2}} {x}}−\frac{\mathrm{1}}{{x}^{\mathrm{2}} }\right)=? \\ $$ Commented by mr W last updated on 17/May/22 $$=\left(\frac{\mathrm{1}}{\mathrm{sin}\:{x}}+\frac{\mathrm{1}}{{x}}\right)\left(\frac{\mathrm{1}}{\mathrm{sin}\:{x}}−\frac{\mathrm{1}}{{x}}\right) \\…
Question Number 104606 by john santu last updated on 22/Jul/20 $$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\left\{\frac{{x}−\mathrm{1}}{\mid{x}−\mathrm{1}\mid}\:+\:\mid{x}\mid\right\}=? \\ $$ Answered by bobhans last updated on 22/Jul/20 $$\left(\mathrm{1}\right)\underset{{x}\rightarrow\mathrm{0}^{+} } {\mathrm{lim}}\left\{\frac{{x}−\mathrm{1}}{\mid{x}−\mathrm{1}\mid}\:+\:\mid{x}\mid\:\right\}\:=\:\underset{{x}\rightarrow\mathrm{0}^{+} }…
Question Number 104607 by ~blr237~ last updated on 22/Jul/20 $$\:{if}\:\:\:{a}_{\mathrm{0}} =\mathrm{1}\:\:\:,\:\forall\:{n}\geqslant\mathrm{1}\:\:\:\:\:\underset{{p}=\mathrm{0}} {\overset{{n}} {\sum}}\:\frac{{a}_{{n}−{p}} }{\left({p}+\mathrm{1}\right)!}=\mathrm{0}\: \\ $$$${explicit}\:\:{a}_{{n}} \:\:{in}\:{terms}\:{of}\:{n}\: \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 39067 by bshahid010@gmail.com last updated on 02/Jul/18 Commented by math khazana by abdo last updated on 03/Jul/18 $$={lim}_{{h}\rightarrow\mathrm{0}} \:\:\frac{\mathrm{2}{h}\:−{h}^{\mathrm{3}} \sqrt{\mathrm{8}+{h}}}{\mathrm{2}{h}^{\mathrm{4}} \sqrt{\mathrm{8}+{h}}} \\ $$$$={lim}_{{h}\rightarrow\mathrm{0}}…
Question Number 170129 by mathlove last updated on 17/May/22 $$\underset{{x}\rightarrow\mathrm{4}} {\mathrm{lim}}\:\frac{{e}\:!{x}−\mathrm{24}}{\:\sqrt{{x}}−\mathrm{2}}=? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 104603 by john santu last updated on 22/Jul/20 $$\underset{{x}\rightarrow−\mathrm{2}} {\mathrm{lim}}\:{x}\mid{x}−\mathrm{2}\mid\: \\ $$ Answered by bobhans last updated on 22/Jul/20 $$\underset{{x}\rightarrow−\mathrm{2}^{−} } {\mathrm{lim}}{x}\mid{x}−\mathrm{2}\mid\:=\:\underset{{x}\rightarrow−\mathrm{2}^{−} }…