Question Number 169514 by Giantyusuf last updated on 01/May/22 $$\boldsymbol{{evaluate}}\:\boldsymbol{{the}}\:\boldsymbol{{following}}\:\boldsymbol{{limit}} \\ $$$$\left(\boldsymbol{{if}}\:\boldsymbol{{it}}\:\boldsymbol{{exists}}\right) \\ $$$$\boldsymbol{{lim}}_{\boldsymbol{{n}}\rightarrow\infty} \frac{\boldsymbol{{ln}}^{\mathrm{2}} \left(\boldsymbol{{n}}+\mathrm{1}\right)}{\left(\boldsymbol{{n}}−\mathrm{1}\right)^{\mathrm{2}} } \\ $$ Commented by Giantyusuf last updated on…
Question Number 169508 by Giantyusuf last updated on 01/May/22 $${Evaluate}\:{if}\:{the}\:{limit}\:{exist} \\ $$$${lim}_{\boldsymbol{{n}}\rightarrow\infty} \left(\frac{\mathrm{3}^{\boldsymbol{{n}}} +\left(−\mathrm{2}\right)^{\boldsymbol{{n}}+\mathrm{1}} }{\mathrm{3}^{\boldsymbol{{n}}−\mathrm{2}} −\mathrm{2}^{\mathrm{2}\boldsymbol{{n}}−\mathrm{1}} }\right) \\ $$ Answered by qaz last updated on…
Question Number 169501 by Giantyusuf last updated on 01/May/22 Answered by qaz last updated on 01/May/22 $$\underset{\mathrm{n}\rightarrow\infty} {\mathrm{lim}n}\left(\frac{\pi}{\mathrm{2}}−\mathrm{arctan}\:\mathrm{n}\right)=\underset{\mathrm{n}\rightarrow\infty} {\mathrm{lim}narctan}\:\frac{\mathrm{1}}{\mathrm{n}}=\mathrm{1} \\ $$ Terms of Service Privacy…
Question Number 169498 by bagjagugum123 last updated on 01/May/22 Commented by infinityaction last updated on 01/May/22 $$\frac{\mathrm{8}}{\mathrm{3}} \\ $$ Commented by bagjagugum123 last updated on…
Question Number 169481 by TOTTI last updated on 01/May/22 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 169480 by TOTTI last updated on 01/May/22 Answered by MikeH last updated on 01/May/22 $$\left(\mathrm{a}\right)\:\underset{{x}\rightarrow\mathrm{1}^{−} } {\mathrm{lim}}\:\mathrm{g}\left({x}\right)\:=\:\underset{{x}\rightarrow\mathrm{1}} {\mathrm{lim}}\:{x}\:=\:\mathrm{1} \\ $$$$\left(\mathrm{b}\right)\:\underset{{x}\rightarrow\mathrm{1}^{+} } {\mathrm{lim}}\:\mathrm{g}\left({x}\right)\:=\:\underset{{x}\rightarrow\mathrm{1}} {\mathrm{lim}}\left(\mathrm{2}−{x}^{\mathrm{2}}…
Question Number 169479 by cortano1 last updated on 01/May/22 $$\:\:\:\underset{{x}\rightarrow\mathrm{4}} {\mathrm{lim}}\:\frac{\left(\mathrm{cos}\:{a}\right)^{{x}} −\left(\mathrm{sin}\:{a}\right)^{{x}} −\mathrm{cos}\:\mathrm{2}{a}}{{x}−\mathrm{4}}\:=? \\ $$ Commented by infinityaction last updated on 01/May/22 $${use}\:{l}\:{hospital}\:{rule} \\ $$$$\:\:\:\:\:{p}\left({let}\right)\:\:=\:\underset{{x}\rightarrow\mathrm{0}}…
Question Number 169412 by mathlove last updated on 29/Apr/22 Commented by mathlove last updated on 30/Apr/22 $${any}\:{one}\:{is}\:{answer}\:{for}\:{this} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 169294 by cortano1 last updated on 28/Apr/22 Commented by qaz last updated on 28/Apr/22 $$\mathrm{Same}\:\mathrm{as}\::\:\underset{\mathrm{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{\mathrm{sin}\:\mathrm{tan}\:\mathrm{x}−\mathrm{tan}\:\mathrm{sin}\:\mathrm{x}}{\mathrm{x}^{\mathrm{7}} }=−\frac{\mathrm{1}}{\mathrm{14}} \\ $$ Commented by cortano1 last…
Question Number 103749 by bobhans last updated on 17/Jul/20 $$\underset{{n}\rightarrow\infty} {\mathrm{lim}}\:\mathrm{2}^{{n}} \:\mathrm{sin}\:\left(\frac{\pi}{\mathrm{2}^{{n}} }\right)\:=\:? \\ $$ Answered by bramlex last updated on 17/Jul/20 $${set}\:{x}\:=\:\frac{\pi}{\mathrm{2}^{{n}} }\:\Rightarrow\mathrm{2}^{{n}} \:=\:\frac{\pi}{{x}}\:;{x}\rightarrow\mathrm{0}…