Question Number 36953 by rahul 19 last updated on 07/Jun/18 $$\underset{\mathrm{n}\rightarrow\infty} {\mathrm{lim}}\:\mathrm{nsin}\:\left(\mathrm{2}\pi\sqrt{\mathrm{1}+\mathrm{n}^{\mathrm{2}} }\:\right)\:,\left(\:\mathrm{n}\in\mathbb{N}\right). \\ $$ Commented by rahul 19 last updated on 07/Jun/18 Thank you Prof ���� Commented…
Question Number 168014 by mathlove last updated on 31/Mar/22 $$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{\mathrm{5}{e}^{{x}} +\mathrm{5}{e}^{−{x}} −\mathrm{10}}{\mathrm{4}{x}^{\mathrm{2}} }=? \\ $$ Answered by som(math1967) last updated on 01/Apr/22 $$\:\:\frac{\mathrm{5}{e}^{{x}} +\frac{\mathrm{5}}{{e}^{{x}}…
Question Number 168009 by mathlove last updated on 31/Mar/22 $$\underset{{x}\rightarrow\infty} {\mathrm{lim}}\frac{\sqrt{\mathrm{4}{x}^{\mathrm{2}} −\mathrm{4}{x}+\mathrm{1}}+\mathrm{3}{x}}{\:\sqrt{{x}^{\mathrm{2}} +{x}−\mathrm{5}}+{x}}=? \\ $$ Answered by nurtani last updated on 31/Mar/22 $$\underset{{x}\rightarrow\infty} {\mathrm{lim}}\:\frac{\sqrt{\mathrm{4}{x}^{\mathrm{2}} −\mathrm{4}{x}+\mathrm{1}}+\mathrm{3}{x}}{\:\sqrt{{x}^{\mathrm{2}}…
Question Number 168004 by mathlove last updated on 31/Mar/22 $$\underset{{x}\rightarrow\infty} {\mathrm{lim}}\sqrt{\mathrm{4}{x}^{\mathrm{2}} −\mathrm{16}{x}+\mathrm{1}}−\mathrm{2}{x}+\mathrm{3}=? \\ $$ Answered by nurtani last updated on 31/Mar/22 $$\underset{{x}\rightarrow\infty} {\mathrm{lim}}\:\sqrt{\mathrm{4}{x}^{\mathrm{2}} −\mathrm{16}{x}+\mathrm{1}}−\mathrm{2}{x}+\mathrm{3}\:=\underset{{x}\rightarrow\infty} {\mathrm{lim}}\:\sqrt{\mathrm{4}{x}^{\mathrm{2}}…
Question Number 36928 by maxmathsup by imad last updated on 07/Jun/18 $${find}\:{lim}_{{x}\rightarrow+\infty} \left\{\:{ch}\sqrt{{x}+\mathrm{1}}\:\:−{ch}\sqrt{{x}}\:\right\}^{\frac{\mathrm{1}}{\:\sqrt{{x}}}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 167981 by mathlove last updated on 31/Mar/22 $$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{\mathrm{4}^{{x}} −\mathrm{2}^{{x}} }{\mathrm{8}^{{x}} −\mathrm{4}^{{x}} }=? \\ $$ Answered by mathlove last updated on 31/Mar/22 $$\underset{{x}\rightarrow\mathrm{0}}…
Question Number 167980 by mathlove last updated on 31/Mar/22 $$\underset{{x}\rightarrow\infty} {\mathrm{lim}}\sqrt{\mathrm{4}{x}^{\mathrm{2}} −\mathrm{16}{x}+\mathrm{1}}−\mathrm{2}{x}+\mathrm{3}=? \\ $$ Commented by cortano1 last updated on 31/Mar/22 $$=\:\underset{{x}\rightarrow\infty} {\mathrm{lim}}\:\mathrm{2}\left({x}−\frac{\mathrm{16}}{\mathrm{8}}\right)−\mathrm{2}{x}+\mathrm{3} \\ $$$$=\:−\mathrm{4}+\mathrm{3}=−\mathrm{1}…
Question Number 167983 by mathlove last updated on 31/Mar/22 $$\underset{{x}\rightarrow\mathrm{2}^{{x}} } {\mathrm{lim}}\left(\frac{{x}+\mathrm{2}}{\mathrm{2}−{x}}\right)=? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 167982 by mathlove last updated on 31/Mar/22 $$\underset{{x}\rightarrow\infty} {\mathrm{lim}}\frac{\sqrt{\mathrm{4}{x}^{\mathrm{2}} −\mathrm{4}{x}+\mathrm{1}}+\mathrm{3}{x}}{\:\sqrt{{x}^{\mathrm{2}} +{x}−\mathrm{5}}+{x}}=? \\ $$ Commented by greogoury55 last updated on 31/Mar/22 $$=\:\frac{\mathrm{5}}{\mathrm{2}} \\ $$…
Question Number 167970 by qaz last updated on 30/Mar/22 $$\mathrm{Calculate}:\:\:\:\underset{\mathrm{n}\rightarrow\infty} {\mathrm{lim}}\underset{\mathrm{k}=\mathrm{1}} {\overset{\mathrm{n}} {\sum}}\frac{\mathrm{k}^{\mathrm{2}} }{\mathrm{n}^{\mathrm{3}} }\centerdot\sqrt[{\mathrm{k}}]{\mathrm{k}}=? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com