Category: Limits

Question Number 168009 by mathlove last updated on 31/Mar/22 $$\underset{x\to \mathrm{\infty }}{\lim }\frac{\sqrt{4x^2-4x+1}+3x}{\sqrt{x^2+x-5}+x}=?$$ Answered by nurtani last updated on 31/Mar/22 $$\underset{{x}\rightarrow\infty} {\mathrm{lim}}\:\frac{\sqrt{\mathrm{4}{x}^{\mathrm{2}} −\mathrm{4}{x}+\mathrm{1}}+\mathrm{3}{x}}{\:\sqrt{{x}^{\mathrm{2}}…

Question Number 36928 by maxmathsup by imad last updated on 07/Jun/18 $$find{lim}_{x\to +\mathrm{\infty }}{\{ch\sqrt{x+1}-ch\sqrt{x}\}}^{\frac{1}{\sqrt{x}}}$$ Terms of Service Privacy Policy Contact: info@tinkutara.com

Question Number 167980 by mathlove last updated on 31/Mar/22 $$\underset{x\to \mathrm{\infty }}{\lim }\sqrt{4x^2-16x+1}-2x+3=?$$ Commented by cortano1 last updated on 31/Mar/22 $$=\underset{x\to \mathrm{\infty }}{\lim }2(x-\frac{16}{8})-2x+3$$$$=\:−\mathrm{4}+\mathrm{3}=−\mathrm{1}…

Question Number 167982 by mathlove last updated on 31/Mar/22 $$\underset{x\to \mathrm{\infty }}{\lim }\frac{\sqrt{4x^2-4x+1}+3x}{\sqrt{x^2+x-5}+x}=?$$ Commented by greogoury55 last updated on 31/Mar/22 $$=\frac{5}{2}$$…

Question Number 167964 by mnjuly1970 last updated on 30/Mar/22 Commented by greogoury55 last updated on 30/Mar/22 $$=\underset{x\to 0}{\lim }\frac{1-\cos \left(\frac{\sqrt{x}-\sqrt{\sin x}}{\sqrt{x}}\right)}{x^4}$$$$=\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\mathrm{2sin}^{\mathrm{2}} \:\left(\frac{\sqrt{{x}}−\sqrt{\mathrm{sin}\:{x}}}{\mathrm{2}\sqrt{{x}}}\right)}{{x}^{\mathrm{4}} } \…