Question Number 163650 by mathlove last updated on 09/Jan/22 $$\underset{{x}\rightarrow\pi} {\mathrm{lim}}\frac{{x}^{\pi^{{x}} } −\pi^{{x}^{\pi} } }{{x}−\pi}=? \\ $$ Commented by Zaynal last updated on 09/Jan/22 $$\mathrm{is}'\mathrm{t}\:\mathrm{not}\:\mathrm{value}\:\mathrm{of}\:\mathrm{limit}…
Question Number 163642 by cortano1 last updated on 09/Jan/22 $$\:\:\:\:\:\:\underset{{x}\rightarrow\frac{\mathrm{2}}{\mathrm{3}}} {\mathrm{lim}}\:\frac{\lfloor\mathrm{3}{x}\rfloor−\mathrm{3}{x}}{\mathrm{9}{x}^{\mathrm{2}} −\mathrm{4}}\:=? \\ $$ Answered by mehdiAz last updated on 09/Jan/22 $$\: \\ $$$$\:\:\:\:\:\:\underset{{x}\rightarrow\frac{\mathrm{2}}{\mathrm{3}}} {\mathrm{lim}}\:\frac{\lfloor\mathrm{3}{x}\rfloor−\mathrm{3}{x}}{\mathrm{9}{x}^{\mathrm{2}}…
Question Number 163609 by qaz last updated on 08/Jan/22 $$\underset{\mathrm{n}\rightarrow\infty} {\mathrm{lim}n}\left[\mathrm{A}−\mathrm{n}\left(\mathrm{H}_{\mathrm{n}} −\mathrm{lnn}−\gamma\right)\right]=\mathrm{B} \\ $$$$\mathrm{Find}\:\frac{\mathrm{A}}{\mathrm{B}}=? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 163608 by qaz last updated on 08/Jan/22 $$\mathrm{A}_{\mathrm{n}} =\frac{\mathrm{n}}{\mathrm{n}^{\mathrm{2}} +\mathrm{1}^{\mathrm{2}} }+\frac{\mathrm{n}}{\mathrm{n}^{\mathrm{2}} +\mathrm{2}^{\mathrm{2}} }+…+\frac{\mathrm{n}}{\mathrm{n}^{\mathrm{2}} +\mathrm{n}^{\mathrm{2}} } \\ $$$$\mathrm{Prove}::\:\underset{\mathrm{n}\rightarrow\infty} {\mathrm{lim}}\frac{\mathrm{1}}{\mathrm{n}^{\mathrm{4}} \left\{\frac{\mathrm{1}}{\mathrm{24}}−\mathrm{n}\left[\mathrm{n}\left(\frac{\pi}{\mathrm{4}}−\mathrm{A}_{\mathrm{n}} \right)−\frac{\mathrm{1}}{\mathrm{4}}\right]\right\}}=\mathrm{2016} \\ $$ Terms…
Question Number 32517 by abdo imad last updated on 26/Mar/18 $${calculatelim}_{{x}\rightarrow\mathrm{0}^{+} } \:\:\frac{{x}^{{sinx}} \:\:−\left({sinx}\right)^{{x}} }{{x}}\:. \\ $$ Commented by abdo imad last updated on 27/Mar/18…
Question Number 163582 by mathlove last updated on 08/Jan/22 $$\underset{{x}\rightarrow\infty} {\mathrm{lim}}\frac{\mathrm{7}^{{x}+\mathrm{2}} +\mathrm{6}^{{x}} }{\mathrm{3}^{\mathrm{2}{x}} −\mathrm{5}^{{x}} }=? \\ $$ Answered by cortano1 last updated on 08/Jan/22 $$\:\underset{{x}\rightarrow\infty}…
Question Number 98004 by Ar Brandon last updated on 11/Jun/20 $$\underset{\mathrm{n}\rightarrow\infty} {\mathrm{lim}}\left[\mathrm{sin}\left(\mathrm{n}\right)+\mathrm{4}^{\mathrm{n}} ×\frac{\mathrm{3}}{\mathrm{n}^{\mathrm{2}} }×\frac{\mathrm{n}+\mathrm{1}}{\mathrm{n}^{\mathrm{2}} −\mathrm{4}}\right] \\ $$ Commented by bobhans last updated on 11/Jun/20 $$\underset{\mathrm{n}\rightarrow\infty}…
Question Number 32470 by daffa123 last updated on 25/Mar/18 $$\underset{{x}\rightarrow\infty} {{lim}}\:{x}\left({sec}\left(\frac{\mathrm{1}}{\:\sqrt{{x}}}\right)\:−\:\mathrm{1}\right)=… \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 32409 by saru53424@gmail.com last updated on 24/Mar/18 Answered by rahul 19 last updated on 24/Mar/18 $${option}\:\mathrm{2}−\mathrm{3}. \\ $$$${x}^{\mathrm{3}} −\mathrm{4}{x}^{\mathrm{2}} −{x}+\mathrm{4}=\:\left({x}−\mathrm{1}\right)\left({x}^{\mathrm{2}} −\mathrm{3}{x}−\mathrm{4}\right) \\ $$$$\Rightarrow\:\underset{{x}\rightarrow\mathrm{4}}…
Question Number 32407 by saru53424@gmail.com last updated on 24/Mar/18 $$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{\mathrm{1}−\mathrm{cos}\:\left(\mathrm{1}−\mathrm{cos}\:\boldsymbol{\mathrm{x}}\right)}{\boldsymbol{\mathrm{x}}×\boldsymbol{\mathrm{x}}×\boldsymbol{\mathrm{x}}×\boldsymbol{\mathrm{x}}} \\ $$ Commented by abdo imad last updated on 24/Mar/18 $${if}\:{you}\:{mean}\:{lim}_{{x}\rightarrow\mathrm{0}} \:\frac{\mathrm{1}−{cos}\left(\mathrm{1}−{cosx}\right)}{{x}^{\mathrm{4}} }\:{in}\:{this}\:{case}\:{its} \\…