Question Number 160508 by qaz last updated on 30/Nov/21 $$\mathrm{f}\left(\mathrm{x}\right)=\mathrm{27x}^{\mathrm{3}} +\mathrm{5x}^{\mathrm{2}} −\mathrm{2} \\ $$$$\underset{\mathrm{x}\rightarrow\infty} {\mathrm{lim}}\frac{\mathrm{f}^{−\mathrm{1}} \left(\mathrm{27x}\right)−\mathrm{f}^{−\mathrm{1}} \left(\mathrm{x}\right)}{\:\sqrt[{\mathrm{3}}]{\mathrm{x}}}=? \\ $$ Terms of Service Privacy Policy Contact:…
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Question Number 160491 by Ar Brandon last updated on 30/Nov/21 Commented by Ar Brandon last updated on 30/Nov/21 $$\mathrm{Determine}\:\mathrm{the}\:\mathrm{limits}\:\mathrm{of}\:\mathrm{the}\:\mathrm{following}\:\mathrm{sums}; \\ $$$${u}_{{n}} =\underset{{k}=\mathrm{1}} {\overset{{n}} {\sum}}\frac{{n}}{{nk}^{\mathrm{2}} +{k}+\mathrm{1}}…
Question Number 160440 by qaz last updated on 29/Nov/21 $$\underset{\mathrm{n}\rightarrow\infty} {\mathrm{lim}}\left(\sqrt{\mathrm{n}^{\mathrm{2}} +\mathrm{n}}+\mathrm{n}\underset{\mathrm{k}=\mathrm{1}} {\overset{\mathrm{n}} {\sum}}\mathrm{cos}\:\frac{\mathrm{k}\pi}{\mathrm{n}}\right)=? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 160439 by qaz last updated on 29/Nov/21 $$\underset{\mathrm{n}\rightarrow\infty} {\mathrm{lim}}\left(\frac{\mathrm{1}}{\mathrm{3}\pi}\int_{\pi} ^{\mathrm{2}\pi} \frac{\mathrm{x}}{\mathrm{arctan}\:\left(\mathrm{nx}\right)}\mathrm{dx}\right)^{\mathrm{n}} =? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 160438 by qaz last updated on 29/Nov/21 $$\underset{\mathrm{n}\rightarrow\infty} {\mathrm{lim}}\frac{\left(\mathrm{2}\sqrt[{\mathrm{n}}]{\mathrm{n}}−\sqrt[{\mathrm{n}}]{\mathrm{2}}\right)^{\mathrm{n}} }{\mathrm{n}^{\mathrm{2}} }=? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 29363 by puneet1789 last updated on 08/Feb/18 Commented by puneet1789 last updated on 08/Feb/18 plzzz try this.. Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 160427 by qaz last updated on 29/Nov/21 $$\underset{\mathrm{n}\rightarrow\infty} {\mathrm{lim}}\int_{\mathrm{0}} ^{\mathrm{1}} \underset{\mathrm{i}=\mathrm{1}} {\overset{\mathrm{n}} {\sum}}\frac{\underset{\mathrm{j}=\mathrm{1}} {\overset{\mathrm{n}} {\prod}}\left(\mathrm{x}+\frac{\mathrm{j}}{\mathrm{n}^{\mathrm{2}} }\right)}{\mathrm{x}+\frac{\mathrm{i}}{\mathrm{n}^{\mathrm{2}} }}\mathrm{dx}=? \\ $$ Answered by Kamel last…
Question Number 160395 by qaz last updated on 29/Nov/21 $$\mathrm{I}_{\mathrm{n}} =\int_{\mathrm{0}} ^{\pi/\mathrm{2}} \frac{\mathrm{sin}\:^{\mathrm{2}} \left(\mathrm{nt}\right)}{\mathrm{sin}\:\mathrm{t}}\mathrm{dt} \\ $$$$\mathrm{Find}::\:\:\:\:\underset{\mathrm{n}\rightarrow\infty} {\mathrm{lim}}\left(\mathrm{2I}_{\mathrm{n}} −\mathrm{lnn}\right)=? \\ $$ Answered by Kamel last updated…
Question Number 160394 by qaz last updated on 29/Nov/21 $$\underset{\mathrm{n}\rightarrow\infty} {\mathrm{lim}}\left(\frac{\mathrm{2}}{\mathrm{2}^{\mathrm{2}} −\mathrm{1}}\right)^{\frac{\mathrm{1}}{\mathrm{2}^{\mathrm{n}−\mathrm{1}} }} \left(\frac{\mathrm{2}^{\mathrm{2}} }{\mathrm{2}^{\mathrm{3}} −\mathrm{1}}\right)^{\mathrm{2}^{\frac{\mathrm{1}}{\mathrm{n}−\mathrm{2}}} } \centerdot…\centerdot\left(\frac{\mathrm{2}^{\mathrm{n}−\mathrm{1}} }{\mathrm{2}^{\mathrm{n}} −\mathrm{1}}\right)^{\frac{\mathrm{1}}{\mathrm{2}}} =? \\ $$ Terms of…