Question Number 93955 by i jagooll last updated on 16/May/20 $$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{{x}^{\mathrm{3}} −\mathrm{sin}\:^{\mathrm{3}} {x}}{{x}^{\mathrm{5}} } \\ $$ Answered by john santu last updated on 16/May/20…
Question Number 28408 by Rasheed.Sindhi last updated on 25/Jan/18 $$\mathrm{Determine}\:\left(\mathrm{i}\right)\:\frac{\infty}{{a}}\:\:\left(\mathrm{ii}\right)\:\frac{−\infty}{{a}}\:\mathrm{in}\:\mathrm{case}\: \\ $$$$\left({a}\right)\:{a}\in\mathbb{R}^{−} \:\:\:\:\left({b}\right)\:\:{a}\in\mathbb{R}^{+} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 93892 by frc2crc last updated on 15/May/20 $${let} \\ $$$${a}_{{n}+\mathrm{1}} =\sqrt{\mathrm{2}+\sqrt{{a}_{{n}} }}\:\:\:\:\:\:{a}_{\mathrm{0}} =\sqrt{\mathrm{2}} \\ $$$${find}\:\underset{{n}\rightarrow\infty} {\mathrm{lim}}\:{a}_{{n}+\mathrm{1}} \\ $$ Commented by Tony Lin last…
Question Number 159405 by qaz last updated on 16/Nov/21 $$\underset{\mathrm{x}\rightarrow+\mathrm{0}} {\mathrm{lim}}\left(\frac{\underset{\mathrm{k}=\mathrm{1}} {\overset{\mathrm{2021}} {\sum}}\mathrm{k}^{\mathrm{x}} }{\mathrm{2021}}\right)^{\frac{\mathrm{1}}{\mathrm{x}}} =? \\ $$ Answered by mindispower last updated on 16/Nov/21 $$=\underset{{x}\rightarrow\mathrm{0}}…
Question Number 159395 by cortano last updated on 16/Nov/21 $$\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\mathrm{1}−\sqrt[{{n}}]{\mathrm{cos}\:\mathrm{2}{x}}}{{x}^{\mathrm{2}} }\:=\:\frac{\mathrm{1}}{\mathrm{3}} \\ $$$$\:{n}=? \\ $$ Answered by qaz last updated on 16/Nov/21 $$\underset{\mathrm{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{\mathrm{1}−\sqrt[{\mathrm{n}}]{\mathrm{cos}\:\mathrm{2x}}}{\mathrm{x}^{\mathrm{2}}…
Question Number 159388 by amin96 last updated on 16/Nov/21 $$\underset{{x}\rightarrow\infty} {\mathrm{lim}}\left(\frac{\mathrm{1}}{\boldsymbol{\mathrm{x}}^{\mathrm{2}} +\mathrm{1}}+\frac{\mathrm{2}}{\boldsymbol{\mathrm{x}}^{\mathrm{2}} +\mathrm{4}}+\frac{\mathrm{3}}{\boldsymbol{\mathrm{x}}^{\mathrm{2}} +\mathrm{9}}+\ldots\right)=? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 93824 by student work last updated on 15/May/20 Answered by john santu last updated on 15/May/20 $$\underset{\mathrm{t}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\mathrm{lny}\:=\:\underset{\mathrm{t}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\mathrm{tan}\:\left(\mathrm{3t}+\frac{\pi}{\mathrm{2}}\right)\mathrm{ln}\left(\mathrm{tan}\:\left(\frac{\mathrm{3t}}{\mathrm{2}}+\frac{\pi}{\mathrm{4}}\right)\right) \\ $$$$=\:\underset{\mathrm{t}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\mathrm{ln}\left(\mathrm{tan}\:\left(\frac{\mathrm{3t}}{\mathrm{2}}+\frac{\pi}{\mathrm{4}}\right)\right)}{\mathrm{cot}\:\left(\mathrm{3t}+\frac{\pi}{\mathrm{2}}\right)} \\…
Question Number 93821 by john santu last updated on 15/May/20 $$\underset{{x}\rightarrow+\infty} {\mathrm{lim}}\:\mathrm{ln}\left(\mathrm{e}^{{x}} +\mathrm{1}\right)−{x}\:=\: \\ $$ Commented by JDamian last updated on 15/May/20 $$\mathrm{0} \\ $$…
Question Number 159349 by cortano last updated on 15/Nov/21 $$\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\mathrm{8sec}\:{x}−\mathrm{8}+\mathrm{tan}\:^{\mathrm{4}} {x}−\mathrm{4tan}\:^{\mathrm{2}} {x}}{{x}^{\mathrm{6}} }\:=? \\ $$ Commented by bobhans last updated on 16/Nov/21 $$\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\mathrm{8}\left(\sqrt{\mathrm{1}+\mathrm{tan}\:^{\mathrm{2}}…
Question Number 159318 by tounghoungko last updated on 15/Nov/21 $$\:\:\underset{{x}\rightarrow\mathrm{1}} {\mathrm{lim}}\:\frac{\sqrt{{x}+\mathrm{1}}+\sqrt{{x}^{\mathrm{2}} −\mathrm{1}}−\sqrt{{x}^{\mathrm{3}} +\mathrm{1}}}{\:\sqrt{{x}−\mathrm{1}}+\sqrt{{x}^{\mathrm{2}} +\mathrm{1}}\:−\sqrt{{x}^{\mathrm{4}} +\mathrm{1}}}\:=? \\ $$ Commented by bobhans last updated on 16/Nov/21 $$\:\mathrm{lim}_{\mathrm{x}\rightarrow\mathrm{1}^{+}…