Category: Limits

Question Number 92577 by jagoll last updated on 08/May/20 $$\underset{x\to \mathrm{\infty }}{\lim }\frac{\ln \mathrm{x}}{\mathrm{x}}$$ Commented by Tony Lin last updated on 08/May/20 $$\underset{x\to \mathrm{\infty }}{\lim }\frac{lnx}{x}$$$$=\underset{{x}\rightarrow\infty}…

Question Number 92511 by Ar Brandon last updated on 07/May/20 $$\underset{\mathrm{x}\to 0}{\lim }\frac{\sqrt[3]{\mathrm{x}}-\sqrt[5]{\mathrm{x}}}{\sqrt[3]{\mathrm{x}}-\sqrt[4]{\mathrm{x}}}$$ Commented by john santu last updated on 07/May/20 $$\mathrm{x}={\mathrm{t}}^{60}$$$$\underset{\mathrm{t}\rightarrow\mathrm{0}}…

Question Number 158037 by Tawa11 last updated on 30/Oct/21 $$\left(1\right)\underset{\mathrm{z}\to -\mathrm{i}}{\lim }\frac{\mathrm{z}-\mathrm{i}}{{\mathrm{z}}^2+1}$$$$\left(2\right)\underset{\mathrm{z}\to -\mathrm{i}}{\lim }\frac{\mathrm{z}+\mathrm{i}}{{\mathrm{z}}^2+1}$$$$\left(3\right)\underset{\mathrm{z}\to \mathrm{i}}{\lim }\frac{{2\mathrm{z}}^2-\mathrm{zi}+1}{\mathrm{z}-\mathrm{i}}$$ Terms of Service…

Question Number 158017 by cortano last updated on 30/Oct/21 Commented by tounghoungko last updated on 31/Oct/21 $$\underset{x\to 0^{-}}{\lim }f\left(x\right)=\underset{x\to 0^{+}}{\lim }f\left(x\right)$$$$\Rightarrow\underset{{x}\rightarrow\mathrm{0}^{\:+} } {\mathrm{lim}}\left({x}^{\frac{\mathrm{7}}{\mathrm{9}}}…

Question Number 92423 by mhmd last updated on 06/May/20 $${lim}_{x\Rightarrow \mathrm{\infty }}\frac{4(x+3)!-x!}{x[(x+2)!-(x-1)!]}$$ Answered by john santu last updated on 07/May/20 $$\underset{x\to \mathrm{\infty }}{\lim }\frac{4(\mathrm{x}+3)(\mathrm{x}+2)(\mathrm{x}+1)\mathrm{x}!-\mathrm{x}!}{\mathrm{x}(\mathrm{x}+2)(\mathrm{x}+1)\mathrm{x}!-\mathrm{x}(\mathrm{x}-1)!}$$$$\underset{{x}\rightarrow\infty}…