Category: Limits

Question Number 157055 by cortano last updated on 19/Oct/21 Commented by MathSh last updated on 20/Oct/21 $$=\:\underset{\boldsymbol{\mathrm{x}}\rightarrow\boldsymbol{\pi}} {\mathrm{lim}}\frac{\pi^{\boldsymbol{\mathrm{x}}^{\boldsymbol{\pi}} } \centerdot\pi\mathrm{x}^{\boldsymbol{\mathrm{x}}-\mathrm{1}} \centerdot\mathrm{ln}\left(\pi\right)-\mathrm{x}^{\boldsymbol{\pi}^{\boldsymbol{\mathrm{x}}} } \left(\pi^{\boldsymbol{\mathrm{x}}} \centerdot\mathrm{ln}\left(\pi\right)\centerdot\mathrm{ln}\left(\mathrm{x}\right)+\pi^{\boldsymbol{\mathrm{x}}} \centerdot\frac{\mathrm{1}}{\mathrm{x}}\right)}{\mathrm{1}}…

Question Number 156993 by amin96 last updated on 18/Oct/21 $$\text{Extra left or missing right}$$$$0<x<\pi$$ Commented by MathSh last updated on 18/Oct/21 $$\mathrm{0}<{x}<\pi\:\:\mathrm{or}\:\:\mathrm{0}\leqslant{x}\leqslant\pi.? \…

Question Number 25852 by abdo imad last updated on 15/Dec/17 $$letsput{H}_n=1+2^{-1}+3^{-1}+\dots .+n^{-1}and{U}_n=H_n-ln\left(n\right)$$$$provethat{U}_{n}isconvergenttoanumberswishverify$$$$0<s<1\left(sisnamednumberofEuler\right)$$ Commented…

Question Number 91274 by  M±th+et+s last updated on 29/Apr/20 $${\underset{n\to \mathrm{\infty }}{limn}}^{-n^2}{[(n+1)(n+\frac{1}{2})\dots .(n+\frac{1}{2^{n-1}})]}^n$$ Terms of Service Privacy Policy Contact: info@tinkutara.com

Question Number 91182 by jagoll last updated on 28/Apr/20 $$\underset{x\to 0}{\lim }\frac{2x^6+3x^2-3\tan {}^{2}x}{3x^6}$$ Answered by john santu last updated on 28/Apr/20…