Question Number 86655 by jagoll last updated on 30/Mar/20 $$\underset{{x}\rightarrow−\mathrm{1}^{+} } {\mathrm{lim}}\:\frac{\sqrt{\pi}\:−\sqrt{\mathrm{arc}\:\mathrm{cos}\:\mathrm{x}}}{\:\sqrt{\mathrm{x}+\mathrm{1}}} \\ $$ Answered by john santu last updated on 30/Mar/20 $$\mathrm{L}'\mathrm{hopital}\:\mathrm{rule} \\ $$$$\underset{{x}\rightarrow−\mathrm{1}^{+}…
Question Number 86603 by Ar Brandon last updated on 29/Mar/20 $$\underset{{x}\rightarrow−\mathrm{1}} {\mathrm{lim}}\frac{{e}^{{x}} }{\left(\mathrm{1}+{x}\right)^{{n}} } \\ $$ Commented by abdomathmax last updated on 29/Mar/20 $${let}\:{f}\left({x}\right)=\frac{{e}^{{x}} }{\left(\mathrm{1}+{x}\right)^{{n}}…
Question Number 152061 by mnjuly1970 last updated on 25/Aug/21 $$ \\ $$$$\:\:\:{solve} \\ $$$$\:\:\:\: \\ $$$$\:\Omega=\:\int_{\mathrm{0}} ^{\:\infty} \frac{\:{sin}^{\:\mathrm{3}} \left({x}\right).{cos}^{\:\mathrm{2}} \left({x}\right)}{{x}^{\:\mathrm{3}} }{dx}\overset{?} {=}\frac{\mathrm{7}\pi}{\mathrm{32}}…\blacksquare \\ $$ Answered…
Question Number 152026 by alcohol last updated on 25/Aug/21 Commented by mr W last updated on 25/Aug/21 $${one} \\ $$ Terms of Service Privacy Policy…
Question Number 86416 by spdmp last updated on 28/Mar/20 $$\sqrt{\mathrm{8}=} \\ $$$$\left.\mathrm{68}\right] \\ $$$$ \\ $$ Commented by john santu last updated on 28/Mar/20 $$??\%\%…
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Question Number 86204 by jagoll last updated on 27/Mar/20 $$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\mathrm{x}^{\mathrm{2}} \:\mathrm{sin}\:\left(\frac{\mathrm{1}}{\mathrm{x}}\right)\:+\:\mathrm{x}}{\:\sqrt[{\mathrm{x}\:\:}]{\mathrm{1}+\mathrm{e}}\:−\mathrm{e}\:}\:? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 86193 by john santu last updated on 27/Mar/20 $$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\mathrm{4}{x}^{\mathrm{2}} +\frac{\mathrm{6}{x}^{\mathrm{2}} }{\:\sqrt{\mathrm{9}{x}^{\mathrm{4}} +\mathrm{9sin}\:^{\mathrm{2}} {x}}}}{\mathrm{3}{x}−\frac{\mathrm{4}{x}^{\mathrm{3}} −{x}}{\mathrm{2}{x}+\mathrm{1}}}\:=\:? \\ $$ Commented by jagoll last updated on…
Question Number 86031 by arcana last updated on 26/Mar/20 $$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\sqrt{\mathrm{2}}−\sqrt{\mathrm{1}+\mathrm{cos}\:{x}}}{\mathrm{sin}\:^{\mathrm{2}} {x}}= \\ $$ Commented by arcana last updated on 26/Mar/20 $${the}\:{answer}\:{is}\:\frac{\mathrm{1}}{\mathrm{4}\sqrt{\mathrm{2}}} \\ $$ Commented…
Question Number 151559 by peter frank last updated on 21/Aug/21 $$\mathrm{prove}\:\mathrm{that} \\ $$$$\left(\mathrm{1}+\mathrm{cos}\:\theta+\mathrm{isin}\:\theta\right)^{\mathrm{n}} \\ $$$$+\:\left(\mathrm{1}+\mathrm{cos}\:\theta−\mathrm{isin}\:\theta\right)^{\mathrm{n}} =\mathrm{2}^{\mathrm{n}+\mathrm{1}} \mathrm{cos}\:\frac{\theta}{\mathrm{2}}\mathrm{cos}\:\frac{\mathrm{n}\theta}{\mathrm{2}} \\ $$ Answered by Olaf_Thorendsen last updated on…