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Category: Limits

lim-x-0-5sin-x-7sin-2x-3sin-3x-tan-x-x-

Question Number 148323 by liberty last updated on 27/Jul/21 $$\:\:\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\mathrm{5sin}\:\mathrm{x}−\mathrm{7sin}\:\mathrm{2x}+\mathrm{3sin}\:\mathrm{3x}}{\mathrm{tan}\:\mathrm{x}−\mathrm{x}}\:=? \\ $$ Answered by EDWIN88 last updated on 27/Jul/21 $$\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\mathrm{5cos}\:{x}−\mathrm{14cos}\:\mathrm{2}{x}+\mathrm{9cos}\:\mathrm{3}{x}}{\mathrm{sec}\:^{\mathrm{2}} {x}−\mathrm{1}} \\ $$$$\underset{{x}\rightarrow\mathrm{0}}…

lim-x-1-ax-a-b-3-x-1-3-2-find-a-and-b-without-L-hopital-rule-

Question Number 82699 by jagoll last updated on 23/Feb/20 $$\underset{{x}\rightarrow\mathrm{1}} {\mathrm{lim}}\:\frac{\sqrt{{ax}−{a}+{b}}−\mathrm{3}}{{x}−\mathrm{1}}\:=\:−\frac{\mathrm{3}}{\mathrm{2}} \\ $$$${find}\:{a}\:{and}\:{b}\:{without}\:{L}'{hopital}\:{rule} \\ $$ Commented by john santu last updated on 23/Feb/20 $$\left(\mathrm{1}\right)\:{limit}\:{must}\:{be}\:\frac{\mathrm{0}}{\mathrm{0}} \\…

Question-82607

Question Number 82607 by arthur.kangdani@gmail.com last updated on 23/Feb/20 Commented by jagoll last updated on 23/Feb/20 $$\underset{{x}\rightarrow\mathrm{2}} {\mathrm{lim}}\:\frac{\mathrm{4}−{x}^{\mathrm{2}} }{\mathrm{4}−{x}^{\mathrm{2}} }\:×\:\underset{{x}\rightarrow\mathrm{2}} {\mathrm{lim}}\:\mathrm{3}+\sqrt{{x}^{\mathrm{2}} +\mathrm{5}}\:=\:\mathrm{1}×\mathrm{6}\:=\:\mathrm{6} \\ $$ Commented…

Lim-x-4x-2-8x-3-2x-4-

Question Number 82541 by zainal tanjung last updated on 22/Feb/20 $$\:\underset{\mathrm{x}\rightarrow\infty} {\mathrm{Lim}}\:\sqrt{\mathrm{4x}^{\mathrm{2}} −\mathrm{8x}+\mathrm{3}}\:−\mathrm{2x}−\mathrm{4} \\ $$ Commented by john santu last updated on 22/Feb/20 $$\underset{{x}\rightarrow\infty} {\mathrm{lim}}\:\sqrt{\mathrm{4}{x}^{\mathrm{2}}…

Find-the-limit-x-0-lim-tan-x-x-1-x-2-

Question Number 82494 by niroj last updated on 21/Feb/20 $$\:\: \\ $$$$\:\:\boldsymbol{\mathrm{Find}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{limit}} \\ $$$$\:\underset{\boldsymbol{\mathrm{x}}\rightarrow\mathrm{0}} {\overset{\boldsymbol{\mathrm{lim}}} {\:}}\:\left(\frac{\boldsymbol{\mathrm{tan}}\:\boldsymbol{\mathrm{x}}}{\boldsymbol{\mathrm{x}}}\right)^{\frac{\mathrm{1}}{\boldsymbol{\mathrm{x}}^{\:\mathrm{2}} }} \\ $$ Commented by abdomathmax last updated on…