Question Number 193596 by Mingma last updated on 17/Jun/23 Answered by cortano12 last updated on 17/Jun/23 $$\left(\mathrm{1}\right)\:\gamma=\mathrm{1} \\ $$$$\left(\mathrm{2}\right)\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\mathrm{e}^{\mathrm{x}} −\mathrm{2}\alpha\mathrm{x}−\beta}{\mathrm{2x}}=\frac{\mathrm{3}}{\mathrm{2}} \\ $$$$\:\:\beta=\mathrm{1}\: \\ $$$$\:\left(\mathrm{3}\right)\:\underset{{x}\rightarrow\mathrm{0}}…
Question Number 193532 by horsebrand11 last updated on 16/Jun/23 $$\:\:\underset{{x}\rightarrow\mathrm{2}} {\mathrm{lim}}\:\frac{\mathrm{1}−\mathrm{cos}\:\pi\mathrm{x}}{\left(\mathrm{2}−\mathrm{x}\right)^{\mathrm{2}} }\:=? \\ $$ Answered by aba last updated on 16/Jun/23 $$\mathrm{let}\:\mathrm{t}=\mathrm{2}−\mathrm{x} \\ $$$$\underset{{x}\rightarrow\mathrm{2}} {\mathrm{lim}}\frac{\mathrm{1}−\mathrm{cos}\pi\mathrm{x}}{\left(\mathrm{2}−\mathrm{x}\right)^{\mathrm{2}}…
Question Number 193563 by SaRahAli last updated on 16/Jun/23 Answered by Gamil last updated on 16/Jun/23 Answered by Subhi last updated on 16/Jun/23 $$ \\…
Question Number 193540 by LowLevelLump last updated on 16/Jun/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 193408 by cortano12 last updated on 13/Jun/23 $$\:\underline{\underbrace{ }} \\ $$ Answered by MM42 last updated on 13/Jun/23 $${lim}_{{n}\rightarrow\infty} \:\frac{\mathrm{1}}{{n}}×\left(\frac{\mathrm{1}−\left({e}^{\frac{{a}}{{n}}} \right)^{{n}} ×\frac{\mathrm{1}}{{e}^{\frac{{a}}{{n}}} }}{\mathrm{1}−{e}^{\frac{{a}}{{n}}}…
Question Number 193328 by mustafazaheen last updated on 10/Jun/23 $$\mathrm{f}\left(\mathrm{x}\right)=\begin{cases}{\frac{\mathrm{x}^{\mathrm{2}} −\mathrm{x}}{\mathrm{x}^{\mathrm{2}} −\mathrm{1}}\:;\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{x}\neq\mathrm{1}}\\{\mathrm{2x}+\mathrm{1};\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{x}=\mathrm{1}}\end{cases} \\ $$$$\mathrm{thene}\:\mathrm{find}\:\underset{{x}\rightarrow\mathrm{1}} {\mathrm{lim}}{f}\left({x}\right)=? \\ $$ Answered by cortano12 last updated on 10/Jun/23 $$\:\:\underset{{x}\rightarrow\mathrm{1}}…
Question Number 193236 by Mingma last updated on 08/Jun/23 Answered by MM42 last updated on 09/Jun/23 $${if}\:\:“{p}''\:{is}\:{prime}\:{number}\:\Rightarrow\:\left({p}−\mathrm{1}\right)!\overset{{p}} {\equiv}−\mathrm{1}\:\:\left({wilson}'{d}\:{theorem}\right) \\ $$$${h}=\mathrm{17}{k}+\mathrm{5}\Rightarrow{h}\overset{\mathrm{17}} {\equiv}\:\mathrm{5}\:\: \\ $$ Answered by…
Question Number 193248 by mnjuly1970 last updated on 08/Jun/23 $$ \\ $$$$\:\mathrm{L}=\:\mathrm{lim}_{\:{x}\rightarrow\mathrm{0}} \:\frac{\:\mathrm{sin}\left({x}\:\right)−\mathrm{arcsin}\left({x}\right)}{\mathrm{tan}\left({x}\right)−\:\mathrm{arctan}\left({x}\right)}=?\:\:\:\:\:\:\: \\ $$$$ \\ $$$$\:\:\:\: \\ $$ Answered by MM42 last updated on…
Question Number 193117 by mustafazaheen last updated on 04/Jun/23 $$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\left(\mathrm{cosx}\right)^{\frac{\mathrm{1}}{\mathrm{x}}} \\ $$ Answered by Subhi last updated on 04/Jun/23 $${y}\:=\:{lim}_{{x}\rightarrow\mathrm{0}} \:\left({cosx}\right)^{\frac{\mathrm{1}}{{x}}} \\ $$$${ln}\left({y}\right)\:=\:{lim}_{{x}\rightarrow\mathrm{0}} \:\frac{{ln}\left({cosx}\right)}{{x}}…
Question Number 131052 by benjo_mathlover last updated on 01/Feb/21 $$\:\underset{{x}\rightarrow{s}} {\mathrm{lim}}\:\frac{{x}^{{s}^{{s}} } −{s}^{{x}^{{s}} } }{{x}^{\mathrm{2}} −{s}^{\mathrm{2}} }\:=? \\ $$ Answered by Ar Brandon last updated…