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Category: Limits

Question-146043

Question Number 146043 by liberty last updated on 10/Jul/21 Answered by iloveisrael last updated on 10/Jul/21 (2)limx0esinx1sinx(tan1(sinx))2$$\:\mathrm{let}\:\mathrm{tan}^{−\mathrm{1}} \left(\mathrm{sin}\:\mathrm{x}\right)\:=\:\mathrm{u}\:\rightarrow\mathrm{sin}\:\mathrm{x}=\mathrm{tan}\:\mathrm{u}\: \

lim-x-0-1-x-1-x-e-x-

Question Number 80417 by jagoll last updated on 03/Feb/20 limx0(1+x)1xex=? Commented by MJS last updated on 03/Feb/20 Itriedtoapproximateandgotsomething$$\mathrm{very}\:\mathrm{close}\:\mathrm{to}\:−\frac{\mathrm{e}}{\mathrm{2}}\:\mathrm{but}\:\mathrm{I}\:\mathrm{cannot}\:\mathrm{prove}\:\mathrm{the} \

n-1-1-n-n-

Question Number 145951 by ArielVyny last updated on 09/Jul/21 n1(1)nn=?? Answered by Olaf_Thorendsen last updated on 09/Jul/21 $$\frac{\mathrm{1}}{\mathrm{1}+{x}}\:=\:\mathrm{1}−{x}+{x}^{\mathrm{2}} −{x}^{\mathrm{3}} +…\:=\:\underset{{n}=\mathrm{0}} {\overset{\infty}…