Question Number 143064 by EDWIN88 last updated on 09/Jun/21 $$\:\:\:\:\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\sqrt[{\mathrm{3}}]{\mathrm{1}+\mathrm{x}^{\mathrm{2}} }\:−\sqrt[{\mathrm{4}}]{\mathrm{1}−\mathrm{2x}}}{\mathrm{x}+\mathrm{x}^{\mathrm{2}} }\:=? \\ $$$$\:\:\:\:\underset{{x}\rightarrow\mathrm{1}} {\mathrm{lim}}\:\frac{\sqrt[{\mathrm{3}}]{\mathrm{7}+\mathrm{x}^{\mathrm{2}} }−\sqrt{\mathrm{3}+\mathrm{x}^{\mathrm{2}} }}{\mathrm{x}−\mathrm{1}}\:=? \\ $$ Answered by bramlexs22 last updated…
Question Number 77528 by Mohamed Amine Bouguezzoul last updated on 07/Jan/20 $$\underset{{k}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{{k}^{\alpha} }{\mathrm{2}^{{k}} }=? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 143013 by Study last updated on 08/Jun/21 $${li}\underset{{x}\rightarrow\infty} {{m}}\frac{\sqrt[{\mathrm{3}}]{{x}+\mathrm{1}}}{{x}+\mathrm{1}}=? \\ $$ Commented by Study last updated on 08/Jun/21 $${what}\:{is}\:{the}\:{practice}? \\ $$ Commented by…
Question Number 143012 by Study last updated on 08/Jun/21 $${li}\underset{\alpha\rightarrow\infty} {{m}}\frac{{e}^{{x}} }{\alpha^{\mathrm{60}!} }=? \\ $$ Commented by Study last updated on 08/Jun/21 $${is}\:{the}\:{e}^{{x}} \:{number}? \\…
Question Number 77442 by aliesam last updated on 06/Jan/20 $${prove}\:{that} \\ $$$$\underset{{x}\rightarrow\infty} {{lim}}\:\left(\mid\frac{{x}^{{x}^{\mathrm{2}} } \left({x}+\mathrm{2}\right)^{\left({x}+\mathrm{1}\right)^{\mathrm{2}} } }{\left({x}+\mathrm{1}\right)^{\mathrm{2}{x}^{\mathrm{2}} +\mathrm{2}{x}+\mathrm{1}} }\mid\right)={e} \\ $$ Answered by aliesam last…
Question Number 142922 by mathlove last updated on 07/Jun/21 $$\underset{{x}\rightarrow\mathrm{1}} {\mathrm{lim}}\frac{\mathrm{sin}\left({x}+\mathrm{1}\right)}{\mathrm{2}{x}−\sqrt{{x}^{\mathrm{2}} +\mathrm{3}}}=? \\ $$ Answered by Olaf_Thorendsen last updated on 07/Jun/21 $$\frac{\mathrm{sin}\left({x}+\mathrm{1}\right)}{\mathrm{2}{x}−\sqrt{{x}^{\mathrm{2}} +\mathrm{3}}}\:=\:\frac{\mathrm{sin}\left({x}+\mathrm{1}\right).\left(\mathrm{2}{x}+\sqrt{{x}^{\mathrm{2}} +\mathrm{3}}\right)}{\mathrm{4}{x}^{\mathrm{2}} −\left({x}^{\mathrm{2}}…
Question Number 77309 by TawaTawa last updated on 05/Jan/20 Commented by mr W last updated on 05/Jan/20 $$=\infty \\ $$ Commented by mathmax by abdo…
Question Number 77234 by TawaTawa last updated on 04/Jan/20 Answered by mr W last updated on 04/Jan/20 $$=\int_{\mathrm{0}} ^{\mathrm{1}} {x}^{\frac{\mathrm{1}}{\mathrm{2}}} {x}^{\frac{\mathrm{1}}{\mathrm{2}}×\frac{\mathrm{1}}{\mathrm{3}}} {x}^{\frac{\mathrm{1}}{\mathrm{2}}×\frac{\mathrm{1}}{\mathrm{3}}×\frac{\mathrm{1}}{\mathrm{4}}} {x}^{\frac{\mathrm{1}}{\mathrm{2}}×\frac{\mathrm{1}}{\mathrm{3}}×\frac{\mathrm{1}}{\mathrm{4}}×\frac{\mathrm{1}}{\mathrm{5}}} …{dx} \\…
Question Number 142745 by iloveisrael last updated on 05/Jun/21 Commented by MJS_new last updated on 05/Jun/21 $$\mathrm{vr}×\mathrm{th7gr}\:\mathrm{bl}\theta\mathrm{p}\:\mathrm{njk}\Pi\mathrm{y}\notin\mathrm{m}\:\mathrm{trf}\digamma\mathrm{sh5jk}\:\left[\spadesuit>{bkl}\right. \\ $$ Commented by iloveisrael last updated on…
Question Number 142721 by mathlove last updated on 04/Jun/21 $$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{{x}}{\:\sqrt{\mathrm{1}−\mathrm{cos}\:{x}}}=? \\ $$ Answered by Ar Brandon last updated on 04/Jun/21 $$\underset{\mathrm{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{\mathrm{x}}{\:\sqrt{\mathrm{1}−\mathrm{cosx}}}=\underset{\mathrm{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{\mathrm{x}}{\:\sqrt{\mathrm{1}−\left(\mathrm{1}−\frac{\mathrm{x}^{\mathrm{2}} }{\mathrm{2}}\right)}}=\underset{\mathrm{x}\rightarrow\mathrm{0}}…