Question Number 130119 by Study last updated on 22/Jan/21 $${li}\underset{{x}\rightarrow\mathrm{15}} {{m}log}\left({x}−\mathrm{15}\right)=??\:{or}\:{limit}\:{has}? \\ $$ Answered by Olaf last updated on 22/Jan/21 $$\underset{{x}\rightarrow\mathrm{15}^{−} } {\mathrm{lim}}\:\mathrm{ln}\left({x}−\mathrm{15}\right)\:\mathrm{is}\:\mathrm{undefined} \\ $$$$\mathrm{because}\:{x}−\mathrm{15}\:\mathrm{canno}'\mathrm{t}\:\mathrm{be}\:\mathrm{negative}…
Question Number 64539 by mmkkmm000m last updated on 19/Jul/19 $${lim}_{{xat}\:\mathrm{0}} \left[{cos}^{\mathrm{2}} \left(\mathrm{4}{x}\right)\right]/{x}^{\mathrm{2}} \:\:−{lim}_{{x}\:{at}\:\mathrm{0}} \left[{cos}^{\mathrm{3}} \left(\mathrm{6}{x}\right)\right]/{x}^{\mathrm{2}} \\ $$ Commented by kaivan.ahmadi last updated on 19/Jul/19 $${lim}_{{x}\rightarrow\mathrm{0}}…
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Question Number 129908 by Adel last updated on 20/Jan/21 Answered by mathmax by abdo last updated on 20/Jan/21 $$\mathrm{f}\left(\mathrm{x}\right)=\frac{\left(\mathrm{1}−\sqrt{\mathrm{sinx}}\right)\left(\mathrm{1}−^{\mathrm{3}} \sqrt{\mathrm{sinx}}\right)….\left(\mathrm{1}−^{\mathrm{2020}} \sqrt{\mathrm{sinx}}\right)}{\left(\mathrm{1}−\mathrm{sinx}\right)^{\mathrm{2019}} }\:\mathrm{we}\:\mathrm{do}\:\mathrm{the}\:\mathrm{changement} \\ $$$$\mathrm{x}=\frac{\pi}{\mathrm{2}}+\mathrm{t}\:\:\left(\mathrm{so}\:\mathrm{t}\rightarrow\mathrm{0}^{+} \right)\:\Rightarrow\mathrm{f}\left(\mathrm{x}\right)=\frac{\left(\mathrm{1}−\left(\mathrm{cost}\right)^{\frac{\mathrm{1}}{\mathrm{2}}}…
Question Number 129819 by Adel last updated on 19/Jan/21 $$\underset{{x}\rightarrow\mathrm{100}} {\mathrm{lim}}\left[\left(\mathrm{x}^{\mathrm{100}} −\mathrm{100}^{\mathrm{x}} \right)\frac{\mathrm{1}}{\mathrm{x}−\mathrm{100}}\right]=? \\ $$$$\mathrm{whit}\:\mathrm{out}\:\mathrm{Hopital}\:\mathrm{Rols} \\ $$$$\mathrm{pleas}\:\mathrm{answer} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 64253 by Jameel Ahmad last updated on 16/Jul/19 Commented by ajfour last updated on 16/Jul/19 $${Nobel}\:{laurettes},\:{i}\:{think}! \\ $$ Terms of Service Privacy Policy…
Question Number 129731 by Adel last updated on 18/Jan/21 $$\underset{{x}\rightarrow\infty} {\mathrm{lim}cos}\:\frac{\mathrm{x}}{\mathrm{2}}×\mathrm{cos}\:\frac{\mathrm{x}}{\mathrm{4}}…….\mathrm{cos}\:\frac{\mathrm{x}}{\mathrm{2}^{\mathrm{n}} }=? \\ $$ Answered by Dwaipayan Shikari last updated on 18/Jan/21 $${cos}\frac{{x}}{\mathrm{2}}=\frac{{sinx}}{\mathrm{2}{sin}\frac{{x}}{\mathrm{2}}} \\ $$$$\underset{{n}=\mathrm{1}}…
Question Number 129723 by Adel last updated on 18/Jan/21 $$\underset{{x}\rightarrow\mathrm{100}} {\mathrm{lim}}\left[\left(\mathrm{x}^{\mathrm{100}} −\mathrm{100}^{\mathrm{x}} \right)\frac{\mathrm{1}}{\mathrm{100}−\mathrm{x}}\right]=? \\ $$$$\mathcal{DANISH} \\ $$ Answered by bramlexs22 last updated on 18/Jan/21 $$\:\underset{{x}\rightarrow\mathrm{100}}…
Question Number 129683 by Adel last updated on 17/Jan/21 Commented by Adel last updated on 17/Jan/21 $$ \\ $$When we use antigral in the limit…
Question Number 129655 by liberty last updated on 17/Jan/21 $$\:\:\underset{{x}\rightarrow\infty} {\mathrm{lim}}\left(\mathrm{log}\:_{{x}} \left(\mathrm{2021}{x}\right)\right)^{\mathrm{log}\:{x}} \:=? \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\lceil\ast\rceil\left(\sqrt{\pi^{\ell\mathrm{iberty}} }\:\right) \\ $$ Answered by bemath last updated on 17/Jan/21…