Question Number 65472 by Masumsiddiqui399@gmail.com last updated on 30/Jul/19
Question Number 65473 by Tawa1 last updated on 30/Jul/19 Commented by mathmax by abdo last updated on 30/Jul/19
Question Number 65464 by aliesam last updated on 30/Jul/19 Commented by mathmax by abdo last updated on 30/Jul/19
Question Number 130965 by Hilolaxon last updated on 31/Jan/21 Answered by bramlexs22 last updated on 31/Jan/21 $$\left(\mathrm{2}\right)\:\underset{{x}\rightarrow−\infty} {\mathrm{lim}}\frac{−{x}^{\mathrm{5}} \left(−\mathrm{8}+\frac{\mathrm{4}}{{x}^{\mathrm{2}} }−\frac{\mathrm{4}}{{x}^{\mathrm{5}} }\right)}{−{x}^{\mathrm{5}} \left(−\frac{\mathrm{2}}{{x}^{\mathrm{2}} }−\frac{\mathrm{1}}{{x}^{\mathrm{4}} }+\frac{\mathrm{7}}{{x}^{\mathrm{5}} }\right)}\:=−\infty\:…
Question Number 65356 by aliesam last updated on 28/Jul/19 Commented by mathmax by abdo last updated on 29/Jul/19
Question Number 130869 by EDWIN88 last updated on 30/Jan/21
Question Number 65324 by hovea cw last updated on 28/Jul/19 Commented by mathmax by abdo last updated on 28/Jul/19 $${we}\:{have}\:\mathrm{1}\leqslant{k}\leqslant{n}^{\mathrm{2}} \:\Rightarrow\mathrm{1}+{n}^{\mathrm{2}} \leqslant{k}+{n}^{\mathrm{2}} \leqslant\mathrm{2}{n}^{\mathrm{2}} \:\Rightarrow\sqrt{\mathrm{1}+{n}^{\mathrm{2}} }\leqslant\sqrt{{k}+{n}^{\mathrm{2}}…
Question Number 130854 by mathlove last updated on 29/Jan/21
Question Number 130852 by Algoritm last updated on 29/Jan/21 Answered by Dwaipayan Shikari last updated on 29/Jan/21
Question Number 130843 by EDWIN88 last updated on 29/Jan/21