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Question Number 61363 by bhanukumarb2@gmail.com last updated on 01/Jun/19 Answered by tanmay last updated on 02/Jun/19 $${N}_{{r}} =\mathrm{2}^{\mathrm{2}{b}_{{n}} } −\mathrm{2}^{\mathrm{1}+{b}_{{n}} } .\mathrm{3}^{{b}_{{n}} } +\mathrm{3}^{\mathrm{2}{b}_{{n}} }…
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