Question Number 57404 by turbo msup by abdo last updated on 03/Apr/19 $${find}\:{lim}_{{x}\rightarrow\mathrm{0}} \:\frac{{sin}\left(\pi\sqrt{{cosx}}\right)}{{x}^{\mathrm{2}} } \\ $$ Commented by Smail last updated on 04/Apr/19 $$\underset{{x}\rightarrow\mathrm{0}}…
Question Number 57387 by mustakim420 last updated on 03/Apr/19 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 188449 by mnjuly1970 last updated on 01/Mar/23 $$ \\ $$$$\:\:\:\:\:\:\:\:\:\mathrm{calculate} \\ $$$$\:\: \\ $$$$\:\:\:\:\:\:\mathrm{lim}_{\:\:{x}\rightarrow\:\frac{\pi}{\mathrm{4}}} \:\:\left(\:\:\mathrm{tan}\:\left({x}\:\right)\right)^{\:\mathrm{tan}\left(\mathrm{2}{x}\:\right)} \:\:=\:?\:\:\: \\ $$$$\:\: \\ $$ Answered by cortano12…
Question Number 122866 by bemath last updated on 20/Nov/20 $$\:\:\underset{{n}\rightarrow\infty} {\mathrm{lim}}\:{n}^{\frac{\mathrm{1}}{\mathrm{3}}} \:\sqrt[{\mathrm{3}}]{{n}^{\mathrm{2}} +\mathrm{1}}\:\left(\mathrm{2}{n}^{\mathrm{2}} +\mathrm{3}{n}−\mathrm{1}\right)^{−\frac{\mathrm{1}}{\mathrm{2}}} .\: \\ $$ Answered by liberty last updated on 20/Nov/20 $$\:\:\underset{{x}\rightarrow\infty}…
Question Number 122859 by mnjuly1970 last updated on 20/Nov/20 $$\:\:\:\:\:\:\:\:\:\:\:\:…\:{calculus}\left({II}\right)−\:\:{analysis}\left({I}\right)… \\ $$$$\:\:\::::\:\:{consider}\:{the}\:{sequence}\:\left\{{c}_{{n}} \right\}_{{n}=\mathrm{1}} ^{\infty} \\ $$$$\:\:{in}\:{which}\:::\:{c}_{{n}} =\mathrm{1}+\frac{\mathrm{1}}{\mathrm{2}}+\frac{\mathrm{1}}{\mathrm{3}}+…+\frac{\mathrm{1}}{{n}}\:−{ln}\left({n}\right) \\ $$$$\:\:\:{prove}\:{that}\:{the}\:{above}\:{sequence}\:{is} \\ $$$$\:\:\:{convergent}\:\:{and}\:{then}\: \\ $$$$\:\:\:{find}\:{its}\:{limit}. \\ $$…
Question Number 57302 by rajesh4661kumar@gamil.com last updated on 02/Apr/19 Answered by tanmay.chaudhury50@gmail.com last updated on 03/Apr/19 $${profit}={sp}−{cp} \\ $$$$\%{profit}=\frac{{sp}−{cp}}{{cp}}×\mathrm{100} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\frac{\mathrm{100}{sp}}{{cp}}−\mathrm{100} \\ $$$${as}\:{per}\:{question}\:{cp}=\%{profit} \\ $$$${cp}=\frac{\mathrm{100}{sp}}{{cp}}−\mathrm{100}…
Question Number 122835 by liberty last updated on 20/Nov/20 $$\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{\mathrm{1}}{{x}}\:\left(\frac{\mathrm{1}}{\mathrm{sin}\:{x}}\:−\:\frac{\mathrm{3}}{\mathrm{sin}\:\mathrm{3}{x}}\:\right)\:=? \\ $$ Answered by $@y@m last updated on 20/Nov/20 $$\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{\mathrm{1}}{{x}}\:\left(\frac{\mathrm{sin}\:\mathrm{3}{x}−\mathrm{3sin}\:{x}}{\mathrm{sin}\:{x}.\mathrm{sin}\:\mathrm{3}{x}}\:\right)\: \\ $$$$\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{\mathrm{1}}{{x}}\:\left(\frac{−\mathrm{4sin}\:^{\mathrm{3}}…
Question Number 122834 by liberty last updated on 20/Nov/20 $${If}\:{ax}^{\mathrm{2}} +{bx}+{c}\:=\:\mathrm{0}\:{has}\:{the}\:{roots}\:{are}\: \\ $$$${p}\:{and}\:{q}\:{then}\:{the}\:{value}\:{of}\:\underset{{x}\rightarrow{p}} {\mathrm{lim}}\:\frac{\mathrm{1}−\mathrm{cos}\:\left({ax}^{\mathrm{2}} +{bx}+{c}\right)}{\left({x}−{p}\right)^{\mathrm{2}} }\: \\ $$$${is}\:\_\_\_ \\ $$ Commented by bemath last updated…
Question Number 122824 by bemath last updated on 19/Nov/20 $$\:\:\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{\mathrm{sin}\:\left(\mathrm{1}−\mathrm{cos}\:{x}\right)}{\mathrm{2}{x}^{\mathrm{2}} }\:=? \\ $$ Commented by bobhans last updated on 20/Nov/20 $$\:=\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\mathrm{sin}\:\left(\mathrm{2sin}\:^{\mathrm{2}} \left(\frac{\mathrm{1}}{\mathrm{2}}{x}\right)\right)}{\mathrm{2}{x}^{\mathrm{2}} }…
Question Number 57253 by Tawa1 last updated on 01/Apr/19 $$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\:\:\:\:\:\frac{\mathrm{e}^{\mathrm{x}} \:+\:\mathrm{e}^{−\mathrm{x}} }{\mathrm{x}}\:\:\:\:\:\: \\ $$ Commented by mr W last updated on 01/Apr/19 $$=\frac{\mathrm{2}}{\mathrm{0}}=\infty \\…