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Category: Limits

Reposting-question-181462-lim-n-2-3-1-3-4-1-4-n-1-n-1-n-2n-1-1-n-1-1-2e-

Question Number 181553 by Frix last updated on 26/Nov/22 Repostingquestion181462limn2!×3!3×4!4××n!nn(2n+1)!!n+1=?12e Answered by aleks041103 last updated on 26/Nov/22 $${b}_{{n}} =\frac{\sqrt[{{n}}]{\sqrt{\mathrm{2}!}×\sqrt[{\mathrm{3}}]{\mathrm{3}!}×\sqrt[{\mathrm{4}}]{\mathrm{4}!}×…×\sqrt[{{n}}]{{n}!}}}{\:\sqrt[{{n}+\mathrm{1}}]{\left(\mathrm{2}{n}+\mathrm{1}\right)!!}}=\sqrt[{{n}}]{\frac{\sqrt{\mathrm{2}!}×\sqrt[{\mathrm{3}}]{\mathrm{3}!}×\sqrt[{\mathrm{4}}]{\mathrm{4}!}×…×\sqrt[{{n}}]{{n}!}}{\left(\left(\mathrm{2}{n}+\mathrm{1}\right)!!\right)^{\frac{{n}}{{n}+\mathrm{1}}}…

lim-x-0-1-cos-x-cos-2x-cos-3x-1-3-cos-4x-1-4-x-2-

Question Number 115999 by bemath last updated on 30/Sep/20 limx01cosxcos2xcos3x3cos4x4x2 Answered by bobhans last updated on 30/Sep/20 shortcutmrjohnsantu$$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\mathrm{1}−\mathrm{cos}\:{x}\:\sqrt{\mathrm{cos}\:\mathrm{2}{x}}\:\sqrt[{\mathrm{3}\:}]{\mathrm{cos}\:\mathrm{3}{x}}\:\sqrt[{\mathrm{4}\:}]{\mathrm{cos}\:\mathrm{4}{x}}}{{x}^{\mathrm{2}}…