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Category: Limits

lim-x-ln-1-4-x-pi-arctan-2x-

Question Number 181104 by cortano1 last updated on 21/Nov/22 limxln(1+4x)πarctan(2x)=? Commented by Frix last updated on 21/Nov/22 wrong.$$\underset{{x}\rightarrow\infty} {\mathrm{lim}}\:\frac{\mathrm{ln}\:\left(\mathrm{1}+\frac{\mathrm{4}}{{x}}\right)}{\pi−\mathrm{arctan}\:\mathrm{2}{x}}\:=\frac{\mathrm{0}}{\frac{\pi}{\mathrm{2}}}=\mathrm{0} \