Question Number 44411 by Meritguide1234 last updated on 28/Sep/18 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 109929 by bemath last updated on 26/Aug/20 $$\:\:\:\bigtriangleup\frac{\flat{e}}{\mathcal{M}{ath}}\bigtriangledown \\ $$$$\:\underset{{x}\rightarrow\infty} {\mathrm{lim}}\sqrt{\mathrm{81}{x}^{\mathrm{2}} −\mathrm{10}{x}+\mathrm{1}}−\mathrm{4}{x}+\mathrm{3}−\sqrt{\mathrm{25}{x}^{\mathrm{2}} −\mathrm{10}{x}+\mathrm{1}}\:=? \\ $$ Commented by bemath last updated on 26/Aug/20 Terms…
Question Number 175450 by infinityaction last updated on 30/Aug/22 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 109861 by john santu last updated on 26/Aug/20 $$\:\:\frac{{JS}}{\blacksquare\bigstar\bigstar\blacksquare} \\ $$$$\underset{{x}\rightarrow\mathrm{3}} {\mathrm{lim}}\:\frac{\mathrm{5}−\mathrm{2}{x}+\sqrt{{x}−\mathrm{2}}}{{x}−\mathrm{4}+\sqrt{{x}−\mathrm{2}}}\:? \\ $$ Answered by bemath last updated on 26/Aug/20 Commented by…
Question Number 175362 by cortano1 last updated on 28/Aug/22 $$\:\:\underset{{x}\rightarrow\frac{\pi}{\mathrm{4}}} {\mathrm{lim}}\:\frac{\mathrm{sin}\:{x}−\mathrm{cos}\:{x}}{\mathrm{tan}\:\left(\frac{\pi}{\mathrm{8}}−\frac{{x}}{\mathrm{2}}\right)}\:=? \\ $$ Commented by infinityaction last updated on 28/Aug/22 $$\:\:\underset{{x}\rightarrow\frac{\pi}{\mathrm{4}}} {\mathrm{lim}}\:\frac{−\sqrt{\mathrm{2}}\mathrm{sin}\left(\pi/\mathrm{4}−{x}\right)}{\mathrm{sin}\left(\frac{\pi}{\mathrm{8}}−\frac{{x}}{\mathrm{2}}\right)\mathrm{sec}\:\left(\frac{\pi}{\mathrm{8}}−\frac{{x}}{\mathrm{2}}\right)\:\:} \\ $$$$\:\:\underset{{x}\rightarrow\frac{\pi}{\mathrm{4}}} {\mathrm{lim}}\:\frac{−\mathrm{2}\sqrt{\mathrm{2}}\cancel{\mathrm{sin}\left(\frac{\pi}{\mathrm{8}}−\frac{{x}}{\mathrm{2}}\right)}\mathrm{cos}\left(\frac{\pi}{\mathrm{8}}−\frac{{x}}{\mathrm{2}}\right)\:\:}{\cancel{\mathrm{sin}\left(\frac{\pi}{\mathrm{8}}−\frac{{x}}{\mathrm{2}}\right)}}…
Question Number 109769 by Karani last updated on 25/Aug/20 $$\underset{{x}\rightarrow\Pi} {\mathrm{lim}}\frac{\mathrm{1}−\mathrm{cos}\:{x}\mathrm{cos}\:\mathrm{2}{x}\mathrm{cos}\:\mathrm{3}{x}}{\mathrm{1}−\mathrm{cos}\:{x}}=? \\ $$ Answered by bemath last updated on 25/Aug/20 $$\:\:\:\bigtriangleup\frac{\flat\epsilon}{{math}}\bigtriangledown \\ $$$$\underset{{x}\rightarrow\pi} {\mathrm{lim}}\:\frac{\mathrm{1}−\mathrm{cos}\:\pi.\mathrm{cos}\:\mathrm{2}\pi.\mathrm{cos}\:\mathrm{3}\pi}{\mathrm{1}−\mathrm{cos}\:\pi}\:=\:\frac{\mathrm{1}−\left(−\mathrm{1}\right)\left(\mathrm{1}\right)\left(−\mathrm{1}\right)}{\mathrm{2}}=\mathrm{0} \\…
Question Number 109766 by Karani last updated on 25/Aug/20 $$\underset{{n}\rightarrow\infty} {\mathrm{lim}}\frac{\mathrm{2}^{\frac{{n}}{\mathrm{2}}} +\left({n}+\mathrm{1}\right)!}{{n}\left(\mathrm{3}^{{n}} +{n}!\right)}=? \\ $$ Answered by mathmax by abdo last updated on 25/Aug/20 $$\mathrm{U}_{\mathrm{n}}…
Question Number 109765 by Karani last updated on 25/Aug/20 $$\left({x}_{{n}} \right)=\frac{\left(−\mathrm{1}\right)^{{n}} {n}+\mathrm{10}}{\:\sqrt{{n}^{\mathrm{2}} +\mathrm{1}}},{n}\in{N}\:\mathrm{show}\:\mathrm{if}\:\mathrm{the}\:\mathrm{sequence}\:\mathrm{is}\:\mathrm{limited}. \\ $$ Answered by mathmax by abdo last updated on 25/Aug/20 $$\mid\mathrm{x}_{\mathrm{n}}…
Question Number 109763 by Karani last updated on 25/Aug/20 $$\underset{{n}\rightarrow\infty} {\mathrm{lim}}\left(\frac{\mathrm{3}}{\mathrm{1}−^{{n}} \sqrt{\mathrm{8}}}−\frac{\mathrm{5}}{\mathrm{1}−^{{n}} \sqrt{\mathrm{32}}}\right)=? \\ $$ Answered by bemath last updated on 25/Aug/20 $$\:\:\:\bigtriangledown\frac{\flat{e}}{{math}}\Delta \\ $$$$\underset{{n}\rightarrow\infty}…
Question Number 109733 by bobhans last updated on 25/Aug/20 $$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{{x}−\mathrm{tan}\:{x}}{\mathrm{sin}\:{x}−{x}}\:? \\ $$ Answered by Dwaipayan Shikari last updated on 25/Aug/20 $$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{{x}−{x}−\frac{{x}^{\mathrm{3}} }{\mathrm{3}}}{{x}−\frac{{x}^{\mathrm{3}} }{\mathrm{6}}−{x}}=\mathrm{2}…