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Category: Limits

lim-x-pi-4-sin-x-cos-x-tan-pi-8-x-2-

Question Number 175362 by cortano1 last updated on 28/Aug/22 limxπ4sinxcosxtan(π8x2)=? Commented by infinityaction last updated on 28/Aug/22 limxπ42sin(π/4x)sin(π8x2)sec(π8x2)$$\:\:\underset{{x}\rightarrow\frac{\pi}{\mathrm{4}}} {\mathrm{lim}}\:\frac{−\mathrm{2}\sqrt{\mathrm{2}}\cancel{\mathrm{sin}\left(\frac{\pi}{\mathrm{8}}−\frac{{x}}{\mathrm{2}}\right)}\mathrm{cos}\left(\frac{\pi}{\mathrm{8}}−\frac{{x}}{\mathrm{2}}\right)\:\:}{\cancel{\mathrm{sin}\left(\frac{\pi}{\mathrm{8}}−\frac{{x}}{\mathrm{2}}\right)}}…

lim-x-1-cos-xcos-2xcos-3x-1-cos-x-

Question Number 109769 by Karani last updated on 25/Aug/20 limxΠ1cosxcos2xcos3x1cosx=? Answered by bemath last updated on 25/Aug/20 ϵmath$$\underset{{x}\rightarrow\pi} {\mathrm{lim}}\:\frac{\mathrm{1}−\mathrm{cos}\:\pi.\mathrm{cos}\:\mathrm{2}\pi.\mathrm{cos}\:\mathrm{3}\pi}{\mathrm{1}−\mathrm{cos}\:\pi}\:=\:\frac{\mathrm{1}−\left(−\mathrm{1}\right)\left(\mathrm{1}\right)\left(−\mathrm{1}\right)}{\mathrm{2}}=\mathrm{0} \

lim-x-0-x-tan-x-sin-x-x-

Question Number 109733 by bobhans last updated on 25/Aug/20 limx0xtanxsinxx? Answered by Dwaipayan Shikari last updated on 25/Aug/20 $$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{{x}−{x}−\frac{{x}^{\mathrm{3}} }{\mathrm{3}}}{{x}−\frac{{x}^{\mathrm{3}} }{\mathrm{6}}−{x}}=\mathrm{2}…