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Question Number 109068 by n0y0n last updated on 20/Aug/20 Answered by Dwaipayan Shikari last updated on 20/Aug/20 $$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\left({cos}\mathrm{5}{x}^{\mathrm{2}} \right)^{\frac{\mathrm{1}}{{x}^{\mathrm{4}} }} =\left(\mathrm{1}−\frac{\mathrm{25}{x}^{\mathrm{4}} }{\mathrm{2}}\right)^{\frac{−\mathrm{2}}{{x}^{\mathrm{4}} .\mathrm{25}}.\left(\frac{−\mathrm{25}}{\mathrm{2}}\right)} ={e}^{−\frac{\mathrm{25}}{\mathrm{2}}}…
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