Category: Limits

Question Number 109068 by n0y0n last updated on 20/Aug/20 Answered by Dwaipayan Shikari last updated on 20/Aug/20 $$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\left({cos}\mathrm{5}{x}^{\mathrm{2}} \right)^{\frac{\mathrm{1}}{{x}^{\mathrm{4}} }} =\left(\mathrm{1}−\frac{\mathrm{25}{x}^{\mathrm{4}} }{\mathrm{2}}\right)^{\frac{−\mathrm{2}}{{x}^{\mathrm{4}} .\mathrm{25}}.\left(\frac{−\mathrm{25}}{\mathrm{2}}\right)} ={e}^{−\frac{\mathrm{25}}{\mathrm{2}}}…

Question Number 109001 by 150505R last updated on 20/Aug/20 Terms of Service Privacy Policy Contact: info@tinkutara.com

Question Number 108997 by 150505R last updated on 20/Aug/20 Answered by Dwaipayan Shikari last updated on 20/Aug/20 $$\underset{n\to \mathrm{\infty }}{\lim }sin\left(n^2\pi \sqrt[3]{1+\frac{3}{n}+\frac{4}{n^2}-\frac{5}{n^3}}\right)$$$$\underset{{n}\rightarrow\infty} {\mathrm{lim}}{sin}\left({n}^{\mathrm{2}}…

Question Number 174407 by infinityaction last updated on 31/Jul/22 $$evaluate$$$$\underset{x\to -\mathrm{\infty }}{\lim }\frac{3^{\sin x}+2x+1}{\sin x-\sqrt{x^2+1}}$$ Answered by CElcedricjunior last updated on 31/Jul/22 $$\underset{{x}\rightarrow−\infty}…

Question Number 108842 by Study last updated on 19/Aug/20 Commented by Study last updated on 19/Aug/20 $$ineeduhelp$$ Commented by 150505R last updated on…