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Category: Limits

Question-174276

Question Number 174276 by cortano1 last updated on 28/Jul/22 Answered by blackmamba last updated on 28/Jul/22 limx01cos(2021x)2022x2=$$\:\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\mathrm{1}−\sqrt[{\mathrm{2022}}]{\mathrm{1}−\mathrm{2sin}\:^{\mathrm{2}} \left(\frac{\mathrm{2021}{x}}{\mathrm{2}}\right)}}{{x}^{\mathrm{2}} } \

lim-x-0-1-sin-pi-2-cos-x-2x-5x-2-

Question Number 174152 by cortano1 last updated on 26/Jul/22 limx01sin(π2cosx+2x)5x2=? Answered by CElcedricjunior last updated on 26/Jul/22 $$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{\mathrm{1}−{sin}\left(\frac{\boldsymbol{\pi}}{\mathrm{2}}{cosx}+\mathrm{2}{x}\right)}{\mathrm{5}\boldsymbol{{x}}^{\mathrm{2}} }=\frac{\mathrm{0}}{\mathrm{0}}=\boldsymbol{{F}\mathrm{I}} \