Question Number 215951 by alcohol last updated on 22/Jan/25 $${E}_{{n}} \:=\:\mathrm{3}^{{E}_{{n}−\mathrm{1}} } ,\:{n}\geqslant\mathrm{2} \\ $$$${find}\:{the}\:{unit}\:{digit}\:{of}\:{E}_{\mathrm{1000}} \\ $$ Answered by A5T last updated on 22/Jan/25 $$\mathrm{3}^{\mathrm{3}^{\mathrm{3}^{\mathrm{x}}…
Question Number 215840 by golsendro last updated on 19/Jan/25 $$\:\:\:\mathrm{log}\:_{\mathrm{24}} \:\mathrm{3}=\:{a}\:\mathrm{and}\:\mathrm{log}\:_{\mathrm{24}} \:\mathrm{6}\:=\:\frac{{b}}{\mathrm{6}} \\ $$$$\:\:\:\mathrm{log}\:_{\sqrt{\mathrm{8}}} \:\left({b}−\mathrm{4}{a}\right)=\:? \\ $$ Commented by oubiji last updated on 19/Jan/25 $$\:\:\:\:{b}−\mathrm{4}{a}=\mathrm{log}_{\mathrm{24}}…
Question Number 215089 by golsendro last updated on 28/Dec/24 $$\:\:\mathrm{log}\:_{\mathrm{2}} \:\mathrm{x}\:+\:\mathrm{log}\:_{\mathrm{3}} \:\left(\mathrm{x}+\mathrm{1}\right)\:=\:\mathrm{5}\: \\ $$$$\:\mathrm{x}\:=\:? \\ $$ Answered by efronzo1 last updated on 28/Dec/24 $$\:\:\:\mathrm{log}\:_{\mathrm{3}} \left(\mathrm{x}+\mathrm{1}\right)−\mathrm{2}\:=\:\mathrm{3}−\mathrm{log}\:_{\mathrm{2}}…
Question Number 213923 by luj last updated on 21/Nov/24 Answered by MATHEMATICSAM last updated on 21/Nov/24 $${x}^{\mathrm{32}} \:=\:\mathrm{2}^{{x}} \\ $$$${or}\:\mathrm{32ln}\mid{x}\mid\:=\:{x}\mathrm{ln2} \\ $$$$\mathrm{For}\:{x}\:>\:\mathrm{0} \\ $$$${or}\:\frac{\mathrm{ln}{x}}{{x}}\:=\:\frac{\mathrm{ln2}}{\mathrm{32}}\: \\…
Question Number 212645 by efronzo1 last updated on 20/Oct/24 $$\:\:\begin{cases}{\mathrm{x}=\mathrm{2}+\:\mathrm{log}\:_{\mathrm{2}} \mathrm{log}\:_{\mathrm{2}} \mathrm{y}}\\{\mathrm{y}=\mathrm{2}\:\mathrm{log}\:_{\mathrm{2}} \mathrm{z}\:}\\{\mathrm{z}=\mathrm{2}+\:\mathrm{log}\:_{\mathrm{2}} \:\mathrm{log}\:_{\mathrm{2}} \mathrm{x}\:}\end{cases} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 212515 by efronzo1 last updated on 16/Oct/24 $$\:\:\mathrm{The}\:\mathrm{numbers}\:\mathrm{of}\:\mathrm{pairs}\:\mathrm{of}\:\mathrm{natural}\: \\ $$$$\:\:\:\mathrm{numbers}\:\left(\mathrm{x},\mathrm{y}\right)\:\mathrm{with}\:\mathrm{x},\mathrm{y}\:\leqslant\:\mathrm{33}\:\mathrm{that}\: \\ $$$$\:\:\:\mathrm{satisfy}\:\mathrm{5}\:\mid\:\mathrm{3}^{\mathrm{x}^{\mathrm{y}−\mathrm{1}} } \:+\:\mathrm{2}^{\mathrm{y}^{\mathrm{2x}} } \:\mathrm{is}\:…\: \\ $$$$\:\:\left(\mathrm{A}\right)\:\mathrm{295}\:\:\:\:\left(\mathrm{B}\right)\:\mathrm{296}\:\:\:\:\:\:\:\left(\mathrm{C}\right)\:\mathrm{297}\:\:\:\:\:\:\left(\mathrm{D}\right)\:\mathrm{298}\:\:\:\left(\mathrm{E}\right)\:\mathrm{299} \\ $$ Commented by A5T…
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Question Number 211815 by alcohol last updated on 21/Sep/24 $${ax}^{\mathrm{2}} +{bx}+{c}=\mathrm{0}\:{has}\:{roots}\:\alpha\:{and}\:\beta \\ $$$${and}\:\frac{\alpha}{\beta}=\frac{\lambda}{\mu}.\:{show}\:{that}\:\lambda\mu{b}^{\mathrm{2}} \:=\:{ac}\left(\lambda+\mu\right)^{\mathrm{2}} \\ $$ Answered by som(math1967) last updated on 22/Sep/24 $$\:{let}\:\alpha={k}\lambda\:,\:\beta={k}\mu \\…
Question Number 209991 by efronzo1 last updated on 28/Jul/24 $$\:\:\:\:\:\frac{\mathrm{10}^{\mathrm{log}\:_{\mathrm{3}} \left(\mathrm{6}\right)} .\:\mathrm{15}^{\mathrm{log}\:_{\mathrm{3}} \left(\frac{\mathrm{2}}{\mathrm{3}}\right)} }{\mathrm{6}^{\mathrm{log}\:_{\mathrm{3}} \left(\frac{\mathrm{2}}{\mathrm{3}}\right)} .\:\mathrm{5}^{\mathrm{log}\:_{\mathrm{3}} \left(\frac{\mathrm{4}}{\mathrm{3}}\right)} }\:=?\: \\ $$ Answered by Rasheed.Sindhi last updated…
Question Number 208503 by efronzo1 last updated on 17/Jun/24 Terms of Service Privacy Policy Contact: info@tinkutara.com