Question Number 117816 by snipers237 last updated on 13/Oct/20 $$\:\:{find}\:{out}\:\:\:{for}\:{n}\geqslant\mathrm{1} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\underset{{k}=\mathrm{0}} {\overset{{n}−\mathrm{1}} {\prod}}\Gamma\left(\mathrm{1}+\frac{{k}}{{n}}\right) \\ $$$$ \\ $$ Answered by mnjuly1970 last updated on 14/Oct/20…
Question Number 52030 by Water last updated on 02/Jan/19 $${given}\:{that}\:{log}\mathrm{2}=\mathrm{0}.\mathrm{3010}\:{log}\mathrm{3}=\mathrm{0}.\mathrm{477}\:{log}\mathrm{5}=\mathrm{0}.\mathrm{699} \\ $$$${find}\:{the}\:{values}\:{of}\:{log}\sqrt{\left(\mathrm{0}.\mathrm{2}\right)} \\ $$$$ \\ $$ Answered by afachri last updated on 02/Jan/19 $$\mathrm{log}\:\left(\frac{\mathrm{2}}{\mathrm{10}}\right)^{\mathrm{0}.\mathrm{5}} =\:\mathrm{0}.\mathrm{5}\:\mathrm{log}\:\left(\frac{\mathrm{2}}{\mathrm{10}}\right)…
Question Number 182904 by mathlove last updated on 16/Dec/22 Answered by balliu last updated on 16/Dec/22 $$\sqrt{\mathrm{3}}\left({cosx}+{sinx}\right)−\left({cosx}−{sinx}\right)=\sqrt{\mathrm{2}} \\ $$$$\left(\sqrt{\mathrm{3}}−\mathrm{1}\right){cosx}+\left(\sqrt{\mathrm{3}}+\mathrm{1}\right){sinx}=\sqrt{\mathrm{2}} \\ $$$$ \\ $$ Terms of…
Question Number 182737 by cortano1 last updated on 13/Dec/22 Answered by dre23 last updated on 14/Dec/22 $${d}=\frac{{ln}\left({y}\right)}{{ln}\left({z}\right)}−\frac{{ln}\left({x}\right)}{{ln}\left({y}\right)}=−\mathrm{15}\frac{{ln}\left({z}\right)}{{ln}\left({x}\right)}−\frac{{ln}\left({y}\right)}{{ln}\left({z}\right)}=\frac{{ln}\left({x}\right)}{{ln}\left({y}\right)}−\mathrm{1}={d} \\ $$$${d}+\mathrm{1}=\frac{{ln}\left({x}\right)}{{ln}\left({y}\right)} \\ $$$$\frac{{ln}\left({y}\right)}{{ln}\left({z}\right)}=\mathrm{2}{d}+\mathrm{1} \\ $$$$−\mathrm{15}\frac{{ln}\left({z}\right)}{{ln}\left({x}\right).}=\mathrm{3}{d}+\mathrm{1} \\ $$$$\frac{{ln}\left({x}\right)}{{ln}\left({z}\right)}=−\frac{\mathrm{15}}{\left(\mathrm{1}+\mathrm{3}{d}\right)}=\left({d}+\mathrm{1}\right)\left(\mathrm{2}{d}+\mathrm{1}\right)…
Question Number 182632 by cortano1 last updated on 12/Dec/22 $$\:\:\mathrm{If}\:\mathrm{log}\:_{\mathrm{11}} \left(\mathrm{3p}\right)=\mathrm{log}\:_{\mathrm{13}} \left(\mathrm{q}+\mathrm{6p}\right)\:=\:\mathrm{log}\:_{\mathrm{143}} \left(\mathrm{q}^{\mathrm{2}} \right) \\ $$$$\:\mathrm{find}\:\frac{\mathrm{p}}{\mathrm{q}}. \\ $$ Answered by manxsol last updated on 12/Dec/22…
Question Number 116976 by bobhans last updated on 08/Oct/20 $$\mathrm{use}\:\mathrm{the}\:\mathrm{formula}\:\mathrm{P}=\mathrm{Ie}^{\mathrm{kt}} \:,\mathrm{where}\:\mathrm{P}\:\mathrm{is}\:\mathrm{resulting} \\ $$$$\mathrm{population}\:,\mathrm{I}\:\mathrm{is}\:\mathrm{the}\:\mathrm{initial}\:\mathrm{population}\:\mathrm{and}\:\mathrm{t}\:\mathrm{is} \\ $$$$\mathrm{measured}\:\mathrm{in}\:\mathrm{hours}.\:\mathrm{A}\:\mathrm{bacterial}\:\mathrm{culture} \\ $$$$\mathrm{has}\:\mathrm{an}\:\mathrm{initial}\:\mathrm{population}\:\mathrm{of}\:\mathrm{10},\mathrm{000}.\:\mathrm{If} \\ $$$$\mathrm{its}\:\mathrm{declines}\:\mathrm{to}\:\mathrm{5000}\:\mathrm{in}\:\mathrm{6}\:\mathrm{hours}\:,\:\mathrm{what}\: \\ $$$$\mathrm{will}\:\mathrm{it}\:\mathrm{be}\:\mathrm{at}\:\mathrm{the}\:\mathrm{end}\:\mathrm{of}\:\mathrm{8}\:\mathrm{hours}? \\ $$$$\left(\mathrm{a}\right)\:\mathrm{1985}\:\:\:\:\:\left(\mathrm{b}\right)\:\mathrm{3969}\:\:\:\:\:\left(\mathrm{c}\right)\:\mathrm{2500}\:\:\:\:\left(\mathrm{d}\right)\:\mathrm{4353} \\ $$…
Question Number 116491 by bemath last updated on 04/Oct/20 $$\left(\mathrm{0}.\mathrm{16}\right)^{\mathrm{log}\:_{\mathrm{2}.\mathrm{5}} \left(\frac{\mathrm{1}}{\mathrm{3}}+\frac{\mathrm{1}}{\mathrm{3}^{\mathrm{2}} }+\frac{\mathrm{1}}{\mathrm{3}^{\mathrm{3}} }+…\right)} \:=? \\ $$ Answered by bobhans last updated on 04/Oct/20 $$\mathrm{Only}\:\mathrm{applying}\:\mathrm{property}\:\mathrm{of}\:\mathrm{logarithm} \\…
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Question Number 116085 by Ar Brandon last updated on 30/Sep/20 $$\mathrm{6}+\mathrm{log}_{\frac{\mathrm{3}}{\mathrm{2}}} \left\{\frac{\mathrm{1}}{\mathrm{3}\sqrt{\mathrm{2}}}\sqrt{\mathrm{4}−\frac{\mathrm{1}}{\mathrm{3}\sqrt{\mathrm{2}}}\sqrt{\mathrm{4}−\frac{\mathrm{1}}{\mathrm{3}\sqrt{\mathrm{2}}}\sqrt{\mathrm{4}−\frac{\mathrm{1}}{\mathrm{3}\sqrt{\mathrm{2}}}\centerdot\centerdot\centerdot}}}\right\}=\:? \\ $$ Commented by Dwaipayan Shikari last updated on 30/Sep/20 $$\sqrt{\mathrm{4}−\frac{\mathrm{1}}{\mathrm{3}\sqrt{\mathrm{2}}}\sqrt{\mathrm{4}−\frac{\mathrm{1}}{\mathrm{3}\sqrt{\mathrm{2}}}….}}=\mathrm{a} \\ $$$$\mathrm{4}−\frac{\mathrm{1}}{\mathrm{3}\sqrt{\mathrm{2}}}\mathrm{a}=\mathrm{a}^{\mathrm{2}}…
Question Number 181579 by mathlove last updated on 27/Nov/22 $$\left(\sqrt[{\mathrm{3}}]{{x}}\right)^{−\mathrm{2}+{log}_{{x}} \mathrm{11}} =\mathrm{11} \\ $$$${x}=? \\ $$ Commented by Socracious last updated on 27/Nov/22 $$\boldsymbol{\mathrm{x}}=\frac{\mathrm{1}}{\mathrm{11}} \\…