Question Number 45781 by Junaid555 last updated on 16/Oct/18 $$\:\:\:{Plz}\:{solve} \\ $$$$\:\:\:\:\boldsymbol{{log}}\:\left(\mathrm{17}.\mathrm{92}\right)^{−\frac{\mathrm{1}}{\mathrm{9}}} \\ $$ Answered by hassentimol last updated on 19/Oct/18 $$ \\ $$$$\mathrm{The}\:\mathrm{answer}\:\mathrm{is}\:\mathrm{the}\:\mathrm{following}\:: \\…
Question Number 176748 by MASANJAJJ last updated on 26/Sep/22 $${log}_{\mathrm{4}} \sqrt{\mathrm{8}−{x}}=\mathrm{1}−{log}_{\mathrm{4}} {x} \\ $$$${solve}\:{for}\:{x} \\ $$ Answered by mr W last updated on 26/Sep/22 $$\mathrm{0}<{x}<\mathrm{8}…
Question Number 176332 by Linton last updated on 16/Sep/22 $${f}\left(\frac{{x}}{{f}\left({y}\right)}\right)=\:\frac{{x}}{{y}} \\ $$$${solve}\:{for}\:{x}\:{and}\:{y} \\ $$ Commented by mr W last updated on 16/Sep/22 $${you}\:{mean}\:{find}\:{f}\left({x}\right)? \\ $$…
Question Number 176310 by Linton last updated on 16/Sep/22 $${a}^{{lna}} ={b}^{{lnb}} \\ $$$${a}−{b}=\mathrm{1} \\ $$$${solve}\:{for}\:{a}\:{and}\:{b} \\ $$ Answered by mr W last updated on 16/Sep/22…
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Question Number 110183 by bemath last updated on 27/Aug/20 $$\:\:\:\sqrt{\bigstar}\frac{{be}}{{math}}\sqrt{\bigstar} \\ $$$$\:\:\mathrm{log}\:_{\mathrm{2}} \left({x}\right)+\mathrm{log}\:_{\mathrm{3}} \left({x}\right)+\mathrm{log}\:_{\mathrm{4}} \left({x}\right)=\mathrm{1} \\ $$$$\:\:\:{x}=? \\ $$ Answered by Olaf last updated on…
Question Number 109963 by bobhans last updated on 26/Aug/20 Answered by bemath last updated on 26/Aug/20 $$\left(\mathrm{1}\right)\sqrt{{x}^{\mathrm{2}} −\mathrm{2}{x}+\mathrm{2}}\:=\:\sqrt{\left({x}−\mathrm{1}\right)^{\mathrm{2}} +\mathrm{1}}\:\geqslant\:\mathrm{1} \\ $$$$\left(\mathrm{2}\right)\sqrt{{x}^{\mathrm{2}} −\mathrm{2}{x}+\mathrm{10}}\:=\sqrt{\left({x}−\mathrm{1}\right)^{\mathrm{2}} +\mathrm{9}}\:\geqslant\:\mathrm{3} \\ $$$$\Leftrightarrow\:\mathrm{log}\:_{\mathrm{3}}…
Question Number 175104 by blackmamba last updated on 19/Aug/22 $$\:\:\mathrm{log}\:_{\mathrm{3}} \left({a}+\mathrm{1}\right)=\mathrm{log}\:_{\mathrm{4}} \left({a}+\mathrm{8}\right) \\ $$$$\:{a}=? \\ $$ Answered by MJS_new last updated on 19/Aug/22 $${a}+\mathrm{8}=\mathrm{4}^{{x}} \wedge{a}+\mathrm{1}=\mathrm{3}^{{x}}…
Question Number 175040 by andres_chu last updated on 17/Aug/22 $$ \\ $$hello, please, someone help me to correct the equation? It's typed wrong and I…
Question Number 174940 by Nature911 last updated on 14/Aug/22 $${f}\left({x}\right)=\left({log}\mathrm{3}^{{x}} −\mathrm{2}{log}\mathrm{3}\right).\left({x}^{\mathrm{2}} −\mathrm{1}\right) \\ $$$${let} \\ $$ Commented by Rasheed.Sindhi last updated on 15/Aug/22 $${Complete}\:{your}\:{question}\:{please}! \\…