Question Number 105380 by Skabetix last updated on 28/Jul/20 Commented by Skabetix last updated on 28/Jul/20 $${pls}\:{need}\:{help} \\ $$ Answered by 1549442205PVT last updated on…
Question Number 170843 by cortano1 last updated on 01/Jun/22 Answered by floor(10²Eta[1]) last updated on 01/Jun/22 $$\frac{\mathrm{log}\left(\mathrm{x}−\mathrm{40}\right)}{\mathrm{log}\sqrt{\mathrm{x}+\mathrm{1}}+\mathrm{1}}=\mathrm{1}\Leftrightarrow\mathrm{log}\left(\mathrm{x}−\mathrm{40}\right)=\mathrm{log}\left(\sqrt{\mathrm{x}+\mathrm{1}}+\mathrm{1}\right) \\ $$$$\Leftrightarrow\mathrm{x}−\mathrm{40}=\sqrt{\mathrm{x}+\mathrm{1}}+\mathrm{1}\Leftrightarrow\sqrt{\mathrm{x}+\mathrm{1}}=\mathrm{x}−\mathrm{41} \\ $$$$\Leftrightarrow\mathrm{x}+\mathrm{1}=\left(\mathrm{x}−\mathrm{41}\right)^{\mathrm{2}} \wedge\mathrm{x}−\mathrm{41}\geqslant\mathrm{0} \\ $$$$\Leftrightarrow\mathrm{x}^{\mathrm{2}} −\mathrm{83x}+\mathrm{41}^{\mathrm{2}}…
Question Number 105269 by malwaan last updated on 27/Jul/20 $${a};{b};{c}\:{are}\:{real}\:{numbers} \\ $$$$\mathrm{1}<{b}<{c}^{\mathrm{2}} <{a}^{\mathrm{10}} \\ $$$${log}_{{a}} {b}+\mathrm{2}{log}_{{b}} {c}+\mathrm{5}{log}_{{c}} {a}=\mathrm{12} \\ $$$${prove}\:{that} \\ $$$$\mathrm{2}{log}_{{a}} {c}+\mathrm{5}{log}_{{c}} {b}+\mathrm{10}{log}_{{b}} {a}\geqslant\mathrm{21}…
Question Number 170776 by solomonwells last updated on 30/May/22 Commented by mr W last updated on 31/May/22 $${i}\:{think}\:{there}\:{is}\:{no}\:“{nice}''\:{solution}. \\ $$$$\:{you}\:{can}\:{only}\:{approximate}.\:{x}\approx\mathrm{517}.\mathrm{9788}. \\ $$$${this}\:{wouldn}'{t}\:{change}\:{even}\:{when}\:{you}\: \\ $$$${repeat}\:{the}\:{same}\:{question}\:{a}\:{pair}\: \\…
Question Number 105235 by bobhans last updated on 27/Jul/20 $$\left({x}−\mathrm{2}\right)^{\mathrm{log}\:_{\mathrm{2}} \left({x}^{\mathrm{2}} −\mathrm{5}{x}+\mathrm{5}\right)} \:>\:\left({x}−\mathrm{2}\right)^{\mathrm{log}\:_{\mathrm{2}} \left({x}−\mathrm{3}\right)} \\ $$ Answered by bramlex last updated on 27/Jul/20 Commented by…
Question Number 170677 by solomonwells last updated on 29/May/22 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 170669 by solomonwells last updated on 28/May/22 Commented by kaivan.ahmadi last updated on 28/May/22 $${y}={log}_{\mathrm{6}} {x}\Rightarrow{x}=\mathrm{6}^{{y}} \\ $$$$\mathrm{6}^{{y}^{\mathrm{2}} } +\left(\mathrm{6}^{{y}} \right)^{{y}} =\mathrm{12}\Rightarrow\mathrm{2}×\mathrm{6}^{{y}^{\mathrm{2}} }…
Question Number 170661 by solomonwells last updated on 28/May/22 $$\boldsymbol{\mathrm{log}}\:^{\mathrm{3}} \sqrt{}\boldsymbol{\mathrm{x}}\:\:\:=\:\:\:\sqrt{\boldsymbol{\mathrm{logx}}} \\ $$$$\boldsymbol{\mathrm{solve}}\:\:\boldsymbol{\mathrm{for}}\:\:\:\:\:\:\boldsymbol{{X}} \\ $$$$ \\ $$ Commented by kaivan.ahmadi last updated on 28/May/22 $$\frac{\mathrm{1}}{\mathrm{3}}{logx}=\left({logx}\right)^{\frac{\mathrm{1}}{\mathrm{2}}}…
Question Number 104835 by bemath last updated on 24/Jul/20 $$\begin{cases}{\mathrm{log}\:_{{p}} \left({q}\right)\:=\:{x}^{\mathrm{2}} }\\{\mathrm{log}\:_{{q}} \left({p}^{\mathrm{3}} \right)\:=\:{x}\:}\end{cases} \\ $$$${find}\:{x}\: \\ $$ Answered by john santu last updated on…
Question Number 170327 by mathlove last updated on 21/May/22 Answered by greougoury555 last updated on 21/May/22 $$\frac{\mathrm{1}}{\mathrm{log}\:_{{a}} \left({abc}\right)}\:+\:\frac{\mathrm{1}}{\mathrm{log}\:_{{b}} \left({abc}\right)}\:+\frac{\mathrm{1}}{\mathrm{log}\:_{{c}} \left({abc}\right)}\:=\: \\ $$$$\mathrm{log}\:_{{abc}} {a}+\mathrm{log}_{{abc}} {b}+\mathrm{log}\:_{{abc}} {c}\:=\:\mathrm{1}\:…