Category: Logarithms

Question Number 170843 by cortano1 last updated on 01/Jun/22 Answered by floor(10²Eta[1]) last updated on 01/Jun/22 $$\frac{\log (\mathrm{x}-40)}{\log \sqrt{\mathrm{x}+1}+1}=1\iff \log (\mathrm{x}-40)=\log (\sqrt{\mathrm{x}+1}+1)$$$$\iff \mathrm{x}-40=\sqrt{\mathrm{x}+1}+1\iff \sqrt{\mathrm{x}+1}=\mathrm{x}-41$$$$\iff \mathrm{x}+1={(\mathrm{x}-41)}^2\wedge \mathrm{x}-41⩾0$$$$\Leftrightarrow\mathrm{x}^{\mathrm{2}} −\mathrm{83x}+\mathrm{41}^{\mathrm{2}}…

Question Number 170776 by solomonwells last updated on 30/May/22 Commented by mr W last updated on 31/May/22 $$ithinkthereisno“{nice}^{″}solution.$$$$youcanonlyapproximate.x\approx 517.9788.$$$$this{wouldn}^{\prime }tchangeevenwhenyou$$$${repeat}\:{the}\:{same}\:{question}\:{a}\:{pair}\: \…

Question Number 170677 by solomonwells last updated on 29/May/22 Terms of Service Privacy Policy Contact: info@tinkutara.com

Question Number 170661 by solomonwells last updated on 28/May/22 $$\mathbf{log}{}^3\sqrt{}\mathbf{x}=\sqrt{\mathbf{logx}}$$$$\mathbf{solve}\mathbf{for}\mathit{X}$$$$$$ Commented by kaivan.ahmadi last updated on 28/May/22 $$\frac{\mathrm{1}}{\mathrm{3}}{logx}=\left({logx}\right)^{\frac{\mathrm{1}}{\mathrm{2}}}…

Question Number 170327 by mathlove last updated on 21/May/22 Answered by greougoury555 last updated on 21/May/22 $$\frac{1}{\log {}_a\left(abc\right)}+\frac{1}{\log {}_b\left(abc\right)}+\frac{1}{\log {}_c\left(abc\right)}=$$$$\mathrm{log}\:_{{abc}} {a}+\mathrm{log}_{{abc}} {b}+\mathrm{log}\:_{{abc}} {c}\:=\:\mathrm{1}\:…