Question Number 167243 by greogoury55 last updated on 10/Mar/22 $$\:\:\:\:\:\:\mathrm{log}\:_{\mathrm{3}} \left({x}^{\mathrm{2}} −\mathrm{2}\right)<\:\mathrm{log}\:_{\mathrm{3}} \left(\frac{\mathrm{3}}{\mathrm{2}}\mid{x}\mid−\mathrm{1}\right)\: \\ $$ Answered by MJS_new last updated on 10/Mar/22 $$\mathrm{lhs}=\mathrm{rhs}\:\Rightarrow\:{x}=\pm\mathrm{2};\:\mathrm{lhs}\:\mathrm{defined}\:\mathrm{for}\:\mid{x}\mid>\sqrt{\mathrm{2}} \\ $$$$\Rightarrow…
Question Number 167215 by Avijit007 last updated on 09/Mar/22 Answered by MikeH last updated on 09/Mar/22 $$\mathrm{log}_{{b}} {a}\:×\:\mathrm{log}_{{c}} {b}\:×\:\mathrm{log}_{{a}} {c}\:= \\ $$$$\:\frac{\mathrm{1}}{\cancel{\mathrm{log}_{{a}} {b}}}\:×\:\frac{\cancel{\mathrm{log}_{{a}} {b}}}{\mathrm{log}_{{a}} {c}}×\:\mathrm{log}_{{a}}…
Question Number 167176 by NUR23 last updated on 08/Mar/22 Commented by NUR23 last updated on 08/Mar/22 $${plz}\:{can}\:{some}\:{one}\:{slove}\:{this}\:{question}.\:{he}\:{asking}\:{for}\:{the}\:{value}\:{of}\:{x}? \\ $$$$ \\ $$ Terms of Service Privacy…
Question Number 101553 by bobhans last updated on 03/Jul/20 $$\mathrm{solve}\:\mathrm{the}\:\mathrm{inequality} \\ $$$$\left(\:^{\mathrm{3}} \mathrm{log}\:{x}+\mathrm{2}\right)^{\mathrm{5}{x}+\mathrm{1}} \:\geqslant\:\left(\:^{\mathrm{3}} \mathrm{log}\:{x}\:+\mathrm{2}\right)^{\mathrm{3}−\mathrm{3}{x}} \\ $$ Answered by bramlex last updated on 03/Jul/20 $$\rightarrow\left(\mathrm{log}\:_{\mathrm{3}}…
Question Number 101447 by Rio Michael last updated on 02/Jul/20 $$\mathrm{To}\:\mathrm{sir}\:\mathrm{Tinkutara}:\:\mathrm{please}\:\mathrm{sir}\:\mathrm{can}\:\mathrm{you}\:\mathrm{help}\:\mathrm{us} \\ $$$$\mathrm{with}\:\mathrm{a}\:\mathrm{development}\:\mathrm{which}\:\mathrm{allows}\:\mathrm{our}\:\mathrm{maths}\:\mathrm{work} \\ $$$$\mathrm{which}\:\mathrm{is}\:\mathrm{saved}\:\mathrm{to}\:\mathrm{be}\:\mathrm{converted}\:\mathrm{directly}\:\mathrm{to}\:\mathrm{a}\: \\ $$$$\mathrm{portable}\:\mathrm{document}\:\mathrm{format}\left(\mathrm{PDF}\right)?\: \\ $$ Commented by Tinku Tara last updated…
Question Number 35899 by imamu222 last updated on 25/May/18 $${Evaluate}\:{log}_{\sqrt{\mathrm{2}}} \mathrm{4}+{log}_{\mathrm{1}/\mathrm{2}} \mathrm{16}−{log}_{\mathrm{4}} \mathrm{32} \\ $$ Commented by Cheyboy last updated on 26/May/18 $${log}_{\sqrt{\mathrm{2}}} \mathrm{4}+{log}_{\mathrm{1}/\mathrm{2}} \mathrm{16}−{log}_{\mathrm{4}}…
Question Number 35897 by imamu222 last updated on 25/May/18 $${log}_{{x}^{\mathrm{1}/\mathrm{2}\:} } \mathrm{64}=\mathrm{3}.\:{What}\:{is}\:{x}? \\ $$ Commented by Cheyboy last updated on 25/May/18 $${log}_{{x}^{\mathrm{1}/\mathrm{2}} } \mathrm{64}=\mathrm{3} \\…
Question Number 166687 by cortano1 last updated on 25/Feb/22 $$\:\:\:\mathrm{log}\:_{\left(\mathrm{2x}−\mathrm{1}\right)} \left(\mathrm{x}+\mathrm{1}\right)\:>\:\mathrm{log}\:_{\left(\mathrm{4}−\mathrm{2x}\right)} \left(\mathrm{x}+\mathrm{1}\right) \\ $$$$\:\:\mathrm{x}=? \\ $$ Commented by Nimatullah last updated on 25/Feb/22 $${p} \\…
Question Number 100832 by student work last updated on 28/Jun/20 $$\mathrm{log}\sqrt{\mathrm{125}}\:\centerdot\mathrm{ln10}\:\centerdot\mathrm{log}_{\mathrm{5}} \mathrm{e}=? \\ $$$$\mathrm{help}\:\mathrm{me} \\ $$ Commented by student work last updated on 28/Jun/20 $$\mathrm{what}\:\mathrm{is}\:\mathrm{the}\:\mathrm{practice}\:\mathrm{sir}?…
Question Number 100720 by bemath last updated on 28/Jun/20 Commented by 1549442205 last updated on 28/Jun/20 $$ \\ $$$$\mathrm{one}\:\mathrm{other}\:\mathrm{way}:\mathrm{the}\:\mathrm{conditions}\:\mathrm{for}\:\mathrm{the} \\ $$$$\mathrm{inequality}\:\mathrm{is}\:\mathrm{defined}\:\mathrm{as}:\frac{\mathrm{x}−\mathrm{5}}{\mathrm{5}}>\mathrm{0}\Leftrightarrow\mathrm{x}>\mathrm{5} \\ $$$$\mathrm{Since}\:\mathrm{log}_{\mathrm{8}} \frac{\mathrm{x}−\mathrm{5}}{\mathrm{5}}=\mathrm{log}_{\mathrm{2}} \left(\frac{\mathrm{x}−\mathrm{5}}{\mathrm{5}}\right)^{\frac{\mathrm{1}}{\mathrm{3}}}…