Question Number 96636 by O Predador last updated on 03/Jun/20 Commented by hknkrc46 last updated on 03/Jun/20 $$\mathrm{5}^{{x}} −\left(\mathrm{9},\mathrm{8}\right)^{{x}} =\mathrm{7}^{{x}} \:\Rightarrow\:\mathrm{5}^{{x}} −\left(\frac{\mathrm{49}}{\mathrm{5}}\right)^{{x}} =\mathrm{7}^{{x}} \\ $$$$\Rightarrow\:\mathrm{5}^{{x}}…
Question Number 96508 by bemath last updated on 02/Jun/20 Answered by 1549442205 last updated on 02/Jun/20 $$\boldsymbol{\mathrm{F}}\mathrm{rom}\:\mathrm{the}\:\mathrm{hypothesis}\:\mathrm{we}\:\mathrm{have}\:\mathrm{b}=\mathrm{a}^{\frac{\mathrm{3}}{\mathrm{2}}} =\sqrt{\mathrm{a}^{\mathrm{3}} }=\mathrm{a}\sqrt{\mathrm{a}} \\ $$$$\mathrm{d}=\mathrm{c}^{\frac{\mathrm{5}}{\mathrm{4}}} =^{\mathrm{4}} \sqrt{\mathrm{c}^{\mathrm{5}} }=\mathrm{c}^{\mathrm{4}} \sqrt{\mathrm{c}}\Rightarrow\mathrm{b}−\mathrm{d}=\mathrm{a}\sqrt{\mathrm{a}}−\mathrm{c}^{\mathrm{4}}…
Question Number 161786 by mathlove last updated on 22/Dec/21 $${log}\underset{\mathrm{4}{x}} {{x}}+{log}\underset{\frac{{x}}{\mathrm{2}}} {{x}}=\mathrm{2} \\ $$$${solve}\:\:\:{for}\:\:\:{x}=? \\ $$ Answered by mr W last updated on 22/Dec/21 $$\frac{\mathrm{ln}\:{x}}{\mathrm{ln}\:\left(\mathrm{4}{x}\right)}+\frac{\mathrm{ln}\:{x}}{\mathrm{ln}\:\left(\frac{{x}}{\mathrm{2}}\right)}=\mathrm{2}…
Question Number 95968 by i jagooll last updated on 29/May/20 $$\mathrm{3}^{\frac{\mathrm{log}\:_{\mathrm{3}} \left(\mathrm{2}\right)+\mathrm{log}\:_{\mathrm{3}} \left(\mathrm{3log}\:_{\frac{\mathrm{1}}{\mathrm{3}}} \left(\mathrm{cot}\:\frac{\pi}{\mathrm{3}}\right)\right)}{\mathrm{log}\:_{\pi} \left(\mathrm{3}\right).\left(\mathrm{log}\:_{\mathrm{2}} \left(\pi\right)\right)}\:?\:} \\ $$ Answered by john santu last updated on…
Question Number 161444 by cortano last updated on 18/Dec/21 Commented by blackmamba last updated on 18/Dec/21 $${f}\left({x}\right)=\mathrm{3}{x}−\mathrm{4}\Rightarrow{f}\left(\mathrm{2016}\right)=\mathrm{6044} \\ $$ Commented by blackmamba last updated on…
Question Number 161362 by cortano last updated on 17/Dec/21 $$\:\mathrm{log}\:_{\sqrt{\frac{{x}}{\mathrm{3}}}} \left(\mathrm{3}{x}−\mathrm{54}\right)^{\mathrm{log}\:_{\mathrm{3}} \left({x}\right)} \:=\:\mathrm{18}−\mathrm{3log}\:_{\frac{{x}}{\mathrm{3}}} \left({x}^{\mathrm{2}} \right) \\ $$$$\:{x}=? \\ $$ Commented by bobhans last updated on…
Question Number 161342 by bobhans last updated on 16/Dec/21 $$\:\:\mathrm{2log}\:_{\mathrm{x}} \left(\mathrm{3}\right)\:\mathrm{log}\:_{\mathrm{3x}} \left(\mathrm{3}\right)=\mathrm{log}\:_{\mathrm{9}\sqrt{\mathrm{x}}} \left(\mathrm{3}\right) \\ $$$$\:\mathrm{x}=? \\ $$ Answered by 1549442205PVT last updated on 16/Dec/21 $${the}\:{given}\:{equation}\:{is}\:{equivalent}\:{to}…
Question Number 95485 by O Predador last updated on 25/May/20 Commented by PRITHWISH SEN 2 last updated on 25/May/20 $$\mathrm{2llog}_{\mathrm{ln}\left(\pi\right)} \frac{\mathrm{1}}{\:\sqrt{\mathrm{x}}+\sqrt{\mathrm{ln}\left(\pi\right)}}\:−\mathrm{2log}_{\mathrm{ln}\left(\pi\right)} \frac{\mathrm{1}}{\mathrm{x}−\mathrm{lnx}}\:=\:\mathrm{1} \\ $$$$\mathrm{2log}_{\mathrm{ln}\left(\pi\right)} \frac{\mathrm{x}−\mathrm{ln}\pi}{\:\sqrt{\mathrm{x}}+\sqrt{\mathrm{ln}\left(\pi\right)}}\:=\:\mathrm{1}…
Question Number 160987 by cortano last updated on 10/Dec/21 $$\:\mathrm{Solve}\:\mathrm{for}\:\mathrm{x}\: \\ $$$$\:\:\:\:\:\:\mathrm{log}\:_{\mathrm{log}\:_{\mathrm{6}} \left(\mathrm{x}−\mathrm{1}\right)} \left(\mathrm{64}\right)\:=\:\mathrm{6}\: \\ $$ Answered by bobhans last updated on 10/Dec/21 $$\:\:\mathrm{log}\:_{\mathrm{log}\:_{\mathrm{6}} \left(\mathrm{x}−\mathrm{1}\right)}…
Question Number 160931 by blackmamba last updated on 09/Dec/21 $$\:\:{x}\:=\:\mathrm{2}^{\mathrm{log}\:_{\mathrm{5}} \left({x}+\mathrm{3}\right)} \:;\:{x}=? \\ $$ Answered by cortano last updated on 09/Dec/21 Terms of Service Privacy…