Question Number 93546 by allizzwell23 last updated on 13/May/20 $$\:\:\mathrm{Which}\:\mathrm{app}\:\mathrm{is}\:\mathrm{the}\:\mathrm{best}\:\mathrm{to}\:\mathrm{evaluate} \\ $$$$\:\:\:\:\frac{\mathrm{W}\left(\mathrm{2}\:\mathrm{ln}\:\mathrm{2}\right)}{\mathrm{ln}\:\mathrm{2}} \\ $$ Commented by IbrahimGR376 last updated on 13/May/20 $$\:\:\:\mathrm{mathematica}\:\mathrm{app}\:\:\:\:\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{GR376} \\…
Question Number 93428 by mhmd last updated on 13/May/20 Answered by john santu last updated on 13/May/20 $$\mathrm{10}−\mathrm{x}=\mathrm{2}\mid\mathrm{x}\mid\:\Rightarrow\mathrm{100}−\mathrm{20x}+\mathrm{x}^{\mathrm{2}} =\mathrm{4x}^{\mathrm{2}} \\ $$$$\mathrm{3x}^{\mathrm{2}} +\mathrm{20x}−\mathrm{100}=\mathrm{0} \\ $$$$\left(\mathrm{3x}−\mathrm{10}\right)\left(\mathrm{x}+\mathrm{10}\right)=\mathrm{0} \\…
Question Number 92987 by i jagooll last updated on 10/May/20 $$\begin{cases}{\sqrt{\mathrm{y}}\:+\:\mathrm{ln}\:\left(\mathrm{x}^{\mathrm{2}} \right)=\mathrm{2}}\\{\mathrm{y}\:+\:\mathrm{4}\:\mathrm{ln}\left(\mathrm{x}\right)\:=\mathrm{28}}\end{cases} \\ $$ Answered by john santu last updated on 10/May/20 $$\mathrm{2ln}\left(\mathrm{x}\right)\:=\:\mathrm{14}−\frac{\mathrm{y}}{\mathrm{2}} \\ $$$$\Rightarrow\mathrm{2ln}\left(\mathrm{x}\right)\:=\:\mathrm{2}−\sqrt{\mathrm{y}}\:…
Question Number 92980 by john santu last updated on 10/May/20 $$\mathrm{log}\:_{\sqrt[{\mathrm{3}\:\:}]{\mathrm{9}{x}}} \:\left(\sqrt{\frac{{x}^{\mathrm{3}} }{\mathrm{3}}}\right)\:+\:\mathrm{log}\:_{\sqrt[{\mathrm{3}\:\:}]{\mathrm{3}{x}^{\mathrm{2}} }} \left(\sqrt{\mathrm{27}{x}}\right)\:\leqslant\:\mathrm{3} \\ $$ Answered by frc2crc last updated on 10/May/20 $$\frac{\mathrm{1}}{\mathrm{9}}<{x}<\frac{\sqrt{\mathrm{3}}}{\mathrm{3}}\:{or}\:\mathrm{3}^{\mathrm{1}/\mathrm{3}}…
Question Number 27321 by 803jaideep@gmail.com last updated on 05/Jan/18 Commented by 803jaideep@gmail.com last updated on 05/Jan/18 $$\mathrm{plz}\:\mathrm{solve}\:\mathrm{it} \\ $$ Answered by mrW1 last updated on…
Question Number 92135 by jagoll last updated on 05/May/20 $${a}^{{x}} \:=\:\mathrm{log}\:_{{a}} \:\left({x}\right) \\ $$$${a}=? \\ $$ Commented by Tony Lin last updated on 05/May/20 $${when}\:\mathrm{0}<{x}<{e}^{−{e}}…
Question Number 91862 by jagoll last updated on 03/May/20 $$\mathrm{log}_{\mathrm{2}} \left({x}\right)+\mathrm{log}_{\mathrm{3}} \left({x}\right)\:=\:\mathrm{1} \\ $$$${x}\:=? \\ $$ Commented by Tony Lin last updated on 03/May/20 $$\frac{{lnx}}{{ln}\mathrm{2}}+\frac{{lnx}}{{ln}\mathrm{3}}=\mathrm{1}…
Question Number 91681 by hmamarques1994@gmail.com last updated on 02/May/20 $$\: \\ $$$$\:\boldsymbol{\mathrm{Se}}\:\:\boldsymbol{\mathrm{f}}\left(\sqrt{\mathrm{3}^{\sqrt[{\mathrm{3}}]{\boldsymbol{\mathrm{x}}}} }\:+\:\mathrm{3}^{\sqrt[{\mathrm{3}}]{\boldsymbol{\mathrm{x}}}} \right)\:=\:\sqrt[{\mathrm{3}}]{\boldsymbol{\mathrm{x}}},\:\:\boldsymbol{\mathrm{calcule}}\:\:\frac{\boldsymbol{\mathrm{f}}\left(\mathrm{2}\right)}{\boldsymbol{\mathrm{f}}\left(\mathrm{1}\right)}\centerdot \\ $$$$\: \\ $$ Commented by john santu last updated on…
Question Number 91608 by mhmd last updated on 01/May/20 Commented by Tony Lin last updated on 01/May/20 $${let}\:{log}_{\mathrm{2}} {x}={t} \\ $$$$\frac{\mathrm{1}}{\mathrm{4}}{t}^{\mathrm{2}} −{t}+\mathrm{4}=\mathrm{0} \\ $$$${t}^{\mathrm{2}} −\mathrm{4}{t}+\mathrm{16}=\mathrm{0}…
Question Number 91177 by jagoll last updated on 28/Apr/20 $$\mathrm{6}^{\left(\mathrm{log}_{\mathrm{2}} \:{x}\right)^{\mathrm{2}} } \:+\:{x}^{\left(\mathrm{log}_{\mathrm{2}} \:{x}\right)} \:=\:\mathrm{12}\: \\ $$ Commented by jagoll last updated on 28/Apr/20 $${i}\:{have}\:{no}\:{idea}\:{to}\:{solve}\:{this}…