Question Number 153959 by DELETED last updated on 12/Sep/21 Answered by DELETED last updated on 12/Sep/21 $$\mathrm{F}_{\mathrm{AC}} =\mathrm{k}.\frac{\mathrm{q}_{\mathrm{a}} .\mathrm{q}_{\mathrm{c}} }{\mathrm{r}_{\mathrm{AC}} ^{\mathrm{2}} }\: \\ $$$$\:\:\:\:\:\:\:\:=\mathrm{9}.\mathrm{10}^{\mathrm{9}} .\frac{\mathrm{2}.\mathrm{10}^{−\mathrm{6}}…
Question Number 153950 by liberty last updated on 12/Sep/21 Answered by EDWIN88 last updated on 13/Sep/21 $$\:\:\mathrm{log}\:_{\mid{x}−\frac{\mathrm{7}}{\mathrm{4}}\mid} \left(\mathrm{log}\:_{\frac{\mathrm{1}}{\mathrm{2}}} {x}\right)\leqslant\:\mathrm{0} \\ $$$$\Rightarrow\mathrm{log}\:_{\mid{x}−\frac{\mathrm{7}}{\mathrm{4}}\mid} \left(\mathrm{log}\:_{\frac{\mathrm{1}}{\mathrm{2}}} {x}\right)\:\leqslant\:\mathrm{log}\:_{\mid{x}−\frac{\mathrm{7}}{\mathrm{4}}\mid} \left(\mathrm{1}\right) \\…
Question Number 153840 by liberty last updated on 11/Sep/21 $$\:\:\:\:\mathrm{log}\:_{{e}} \left({x}\right)+\mathrm{log}\:_{{x}} \left({e}\right)+\mathrm{log}\:_{\left(\frac{{e}}{{x}}\right)} \left({x}\right)=\frac{\mathrm{5}}{\mathrm{2}} \\ $$$$\:{x}=? \\ $$ Answered by Rasheed.Sindhi last updated on 11/Sep/21 $$\:\mathrm{log}\:_{{e}}…
Question Number 153681 by EDWIN88 last updated on 09/Sep/21 $$\:\:\mathrm{24}^{\mathrm{log}\:_{\mathrm{10}} \left({x}\right)} −\mathrm{26}^{\mathrm{log}\:_{\mathrm{10}} \left({x}\right)} =\mathrm{1} \\ $$$$\:{x}=? \\ $$ Answered by MJS_new last updated on 09/Sep/21…
Question Number 88068 by student work last updated on 08/Apr/20 Commented by john santu last updated on 08/Apr/20 $${do}\:{you}\:{mean}\:\mathrm{ln}\:{x}^{\mathrm{2}} \:.\mathrm{2log}_{\mathrm{2}{x}} \:\left({x}\right)\:=\:\mathrm{log}_{\mathrm{4}{x}} \left(\mathrm{2}\right)?? \\ $$ Commented…
Question Number 87773 by john santu last updated on 06/Apr/20 $$\:^{\mathrm{3}} \mathrm{log}\:\left(\:^{\mathrm{x}^{\mathrm{2}} } \mathrm{log}\:\left(\:^{\mathrm{x}^{\mathrm{2}} } \mathrm{log}\:\mathrm{x}^{\mathrm{4}} \right)\right)>\:\mathrm{0} \\ $$ Commented by john santu last updated…
Question Number 87637 by john santu last updated on 05/Apr/20 $$\sqrt[{\mathrm{4}\:\:}]{\mid\mathrm{x}−\mathrm{3}\mid^{\mathrm{x}+\mathrm{1}} }\:=\:\sqrt[{\mathrm{3}\:\:}]{\mid\mathrm{x}−\mathrm{3}\mid^{\mathrm{x}−\mathrm{2}} } \\ $$ Answered by TANMAY PANACEA. last updated on 05/Apr/20 $$\mid{x}−\mathrm{3}\mid^{\frac{{x}+\mathrm{1}}{\mathrm{4}}} =\mid{x}−\mathrm{3}\mid^{\frac{{x}−\mathrm{2}}{\mathrm{3}}}…
Question Number 153109 by peter frank last updated on 04/Sep/21 $$\int\frac{\mathrm{dx}}{\mathrm{x}^{\mathrm{2}} +\mathrm{2x}+\mathrm{2}\sqrt{\mathrm{x}^{\mathrm{2}} +\mathrm{2x}−\mathrm{4}}} \\ $$ Commented by MJS_new last updated on 05/Sep/21 $$\mathrm{the}\:\mathrm{path}\:\mathrm{is}\:\mathrm{clear}\:\mathrm{but}\:\mathrm{the}\:\mathrm{constants}\:\mathrm{are}\:\mathrm{weird} \\ $$$${t}=\frac{{x}+\mathrm{1}+\sqrt{{x}^{\mathrm{2}}…
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Question Number 87194 by john santu last updated on 03/Apr/20 $$\mathrm{find}\:\mathrm{the}\:\mathrm{solution}\:\mathrm{of}\: \\ $$$$\frac{\mid\:\mathrm{log}_{\mathrm{2}} \left(\mathrm{x}\right)+\mathrm{2}\mid}{\mathrm{x}−\mathrm{3}}\:<\:\mathrm{2}\: \\ $$ Commented by TANMAY PANACEA. last updated on 03/Apr/20 $${is}\:{it}\:\left(\mathrm{2}+{log}_{\mathrm{2}}…