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Category: Logarithms

Question-153958

Question Number 153958 by DELETED last updated on 12/Sep/21 Answered by DELETED last updated on 12/Sep/21 $$\left.\mathrm{jawaban}\:\mathrm{no}\:\mathrm{2}\right). \\ $$$$\mathrm{F}_{\mathrm{1},\mathrm{2}} =\mathrm{k}×\frac{\mathrm{q}_{\mathrm{1}} ×\mathrm{q}_{\mathrm{2}} }{\mathrm{r}^{\mathrm{2}} }\:\: \\ $$$$\mathrm{r}^{\mathrm{2}}…

Question-153959

Question Number 153959 by DELETED last updated on 12/Sep/21 Answered by DELETED last updated on 12/Sep/21 $$\mathrm{F}_{\mathrm{AC}} =\mathrm{k}.\frac{\mathrm{q}_{\mathrm{a}} .\mathrm{q}_{\mathrm{c}} }{\mathrm{r}_{\mathrm{AC}} ^{\mathrm{2}} }\: \\ $$$$\:\:\:\:\:\:\:\:=\mathrm{9}.\mathrm{10}^{\mathrm{9}} .\frac{\mathrm{2}.\mathrm{10}^{−\mathrm{6}}…

Question-153950

Question Number 153950 by liberty last updated on 12/Sep/21 Answered by EDWIN88 last updated on 13/Sep/21 $$\:\:\mathrm{log}\:_{\mid{x}−\frac{\mathrm{7}}{\mathrm{4}}\mid} \left(\mathrm{log}\:_{\frac{\mathrm{1}}{\mathrm{2}}} {x}\right)\leqslant\:\mathrm{0} \\ $$$$\Rightarrow\mathrm{log}\:_{\mid{x}−\frac{\mathrm{7}}{\mathrm{4}}\mid} \left(\mathrm{log}\:_{\frac{\mathrm{1}}{\mathrm{2}}} {x}\right)\:\leqslant\:\mathrm{log}\:_{\mid{x}−\frac{\mathrm{7}}{\mathrm{4}}\mid} \left(\mathrm{1}\right) \\…

Question-88068

Question Number 88068 by student work last updated on 08/Apr/20 Commented by john santu last updated on 08/Apr/20 $${do}\:{you}\:{mean}\:\mathrm{ln}\:{x}^{\mathrm{2}} \:.\mathrm{2log}_{\mathrm{2}{x}} \:\left({x}\right)\:=\:\mathrm{log}_{\mathrm{4}{x}} \left(\mathrm{2}\right)?? \\ $$ Commented…