Question Number 89124 by pete last updated on 15/Apr/20 Commented by pete last updated on 15/Apr/20 $$\mathrm{I}\:\mathrm{need}\:\mathrm{help}\:\mathrm{on}\:\mathrm{this}\:\mathrm{question}\:\mathrm{please} \\ $$ Commented by john santu last updated…
Question Number 154573 by liberty last updated on 19/Sep/21 Commented by ARUNG_Brandon_MBU last updated on 19/Sep/21 $$−\frac{\mathrm{1}}{\mathrm{6}}<{x}<\frac{\mathrm{1}}{\mathrm{3}} \\ $$ Answered by ARUNG_Brandon_MBU last updated on…
Question Number 154334 by alcohol last updated on 17/Sep/21 $${the}\:{n}^{{th}} \:{term}\:{of} \\ $$$$\mathrm{1}\:,\:\mathrm{2},\:\mathrm{6},\:\mathrm{24},\:\mathrm{120}\:……..\:{is}? \\ $$ Commented by talminator2856791 last updated on 17/Sep/21 $$\:\mathrm{joke}\:\mathrm{question}. \\ $$…
Question Number 153958 by DELETED last updated on 12/Sep/21 Answered by DELETED last updated on 12/Sep/21 $$\left.\mathrm{jawaban}\:\mathrm{no}\:\mathrm{2}\right). \\ $$$$\mathrm{F}_{\mathrm{1},\mathrm{2}} =\mathrm{k}×\frac{\mathrm{q}_{\mathrm{1}} ×\mathrm{q}_{\mathrm{2}} }{\mathrm{r}^{\mathrm{2}} }\:\: \\ $$$$\mathrm{r}^{\mathrm{2}}…
Question Number 153959 by DELETED last updated on 12/Sep/21 Answered by DELETED last updated on 12/Sep/21 $$\mathrm{F}_{\mathrm{AC}} =\mathrm{k}.\frac{\mathrm{q}_{\mathrm{a}} .\mathrm{q}_{\mathrm{c}} }{\mathrm{r}_{\mathrm{AC}} ^{\mathrm{2}} }\: \\ $$$$\:\:\:\:\:\:\:\:=\mathrm{9}.\mathrm{10}^{\mathrm{9}} .\frac{\mathrm{2}.\mathrm{10}^{−\mathrm{6}}…
Question Number 153950 by liberty last updated on 12/Sep/21 Answered by EDWIN88 last updated on 13/Sep/21 $$\:\:\mathrm{log}\:_{\mid{x}−\frac{\mathrm{7}}{\mathrm{4}}\mid} \left(\mathrm{log}\:_{\frac{\mathrm{1}}{\mathrm{2}}} {x}\right)\leqslant\:\mathrm{0} \\ $$$$\Rightarrow\mathrm{log}\:_{\mid{x}−\frac{\mathrm{7}}{\mathrm{4}}\mid} \left(\mathrm{log}\:_{\frac{\mathrm{1}}{\mathrm{2}}} {x}\right)\:\leqslant\:\mathrm{log}\:_{\mid{x}−\frac{\mathrm{7}}{\mathrm{4}}\mid} \left(\mathrm{1}\right) \\…
Question Number 153840 by liberty last updated on 11/Sep/21 $$\:\:\:\:\mathrm{log}\:_{{e}} \left({x}\right)+\mathrm{log}\:_{{x}} \left({e}\right)+\mathrm{log}\:_{\left(\frac{{e}}{{x}}\right)} \left({x}\right)=\frac{\mathrm{5}}{\mathrm{2}} \\ $$$$\:{x}=? \\ $$ Answered by Rasheed.Sindhi last updated on 11/Sep/21 $$\:\mathrm{log}\:_{{e}}…
Question Number 153681 by EDWIN88 last updated on 09/Sep/21 $$\:\:\mathrm{24}^{\mathrm{log}\:_{\mathrm{10}} \left({x}\right)} −\mathrm{26}^{\mathrm{log}\:_{\mathrm{10}} \left({x}\right)} =\mathrm{1} \\ $$$$\:{x}=? \\ $$ Answered by MJS_new last updated on 09/Sep/21…
Question Number 88068 by student work last updated on 08/Apr/20 Commented by john santu last updated on 08/Apr/20 $${do}\:{you}\:{mean}\:\mathrm{ln}\:{x}^{\mathrm{2}} \:.\mathrm{2log}_{\mathrm{2}{x}} \:\left({x}\right)\:=\:\mathrm{log}_{\mathrm{4}{x}} \left(\mathrm{2}\right)?? \\ $$ Commented…
Question Number 87773 by john santu last updated on 06/Apr/20 $$\:^{\mathrm{3}} \mathrm{log}\:\left(\:^{\mathrm{x}^{\mathrm{2}} } \mathrm{log}\:\left(\:^{\mathrm{x}^{\mathrm{2}} } \mathrm{log}\:\mathrm{x}^{\mathrm{4}} \right)\right)>\:\mathrm{0} \\ $$ Commented by john santu last updated…