Question Number 87125 by jagoll last updated on 03/Apr/20 Commented by john santu last updated on 03/Apr/20 $$\mathrm{cooll} \\ $$ Commented by john santu last…
Question Number 86515 by jagoll last updated on 29/Mar/20 $$\mathrm{log}_{\mathrm{2}} \:\left(\mathrm{x}\right)\:+\:\mathrm{log}_{\mathrm{3}} \:\left(\mathrm{x}\right)\:=\:\mathrm{1}\: \\ $$$$\mathrm{x}\:=\: \\ $$ Commented by john santu last updated on 29/Mar/20 $$\Rightarrow\:\:^{\mathrm{2}}…
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Question Number 86339 by frempongfaustina24@gmail.com last updated on 28/Mar/20 $$\mathrm{4}^{{x}} +\mathrm{6}^{{x}} =\mathrm{9}^{{x}} \\ $$$$ \\ $$$$ \\ $$ Answered by jagoll last updated on 28/Mar/20…
Question Number 86337 by frempongfaustina24@gmail.com last updated on 28/Mar/20 $$\left[\mathrm{4}\right. \\ $$ Commented by MJS last updated on 28/Mar/20 $$\mathrm{no}. \\ $$$$\mathrm{7} \\ $$ Terms…
Question Number 20626 by NECx last updated on 29/Aug/17 Answered by $@ty@m last updated on 30/Aug/17 $$\frac{\mathrm{2}}{{log}_{{a}} {x}}+\frac{\mathrm{1}}{{log}_{{a}} {ax}}+\frac{\mathrm{3}}{{log}_{{a}} {a}^{\mathrm{2}} {x}}=\mathrm{0} \\ $$$$\frac{\mathrm{2}}{{log}_{{a}} {x}}+\frac{\mathrm{1}}{{log}_{{a}} {ax}}+\frac{\mathrm{1}}{{log}_{{a}}…
Question Number 85915 by jagoll last updated on 26/Mar/20 $$\mathrm{3}^{\:^{\mid\mathrm{x}\mid} \mathrm{log}\:\mathrm{27}} \:\geqslant\:\frac{\mathrm{81}}{\mathrm{x}} \\ $$ Answered by john santu last updated on 26/Mar/20 Commented by jagoll…
Question Number 85826 by jagoll last updated on 25/Mar/20 $$\:^{\mathrm{x}} \mathrm{log}\:\left(\mathrm{xy}\right).\:^{\mathrm{y}} \mathrm{log}\:\left(\mathrm{xy}\right)\:+\:^{\mathrm{x}} \mathrm{log}\:\left(\mathrm{x}−\mathrm{y}\right).^{\mathrm{y}} \mathrm{log}\:\left(\mathrm{x}−\mathrm{y}\right)=\mathrm{0} \\ $$$$\mathrm{find}\:\mathrm{x}+\mathrm{y}\: \\ $$ Commented by john santu last updated on…
Question Number 20245 by virus last updated on 24/Aug/17 $$\mathrm{y}=\mathrm{2}^{\frac{\mathrm{1}}{{log}_{{x}} \mathrm{8}}} \\ $$$${then}\:{x}=? \\ $$ Answered by Tinkutara last updated on 24/Aug/17 $${y}\:=\:\mathrm{2}^{\mathrm{log}_{\mathrm{8}} \:{x}} \:=\:\mathrm{2}^{\frac{\mathrm{1}}{\mathrm{3}}\:\mathrm{log}_{\mathrm{2}}…
Question Number 85694 by john santu last updated on 24/Mar/20 $$\mathrm{log}_{\left(\frac{{x}}{{x}−\mathrm{3}}\right)} \left(\mathrm{7}\right)\:<\:\mathrm{log}_{\left(\frac{{x}}{\mathrm{3}}\right)} \:\left(\mathrm{7}\right)\: \\ $$ Commented by jagoll last updated on 24/Mar/20 $$\frac{\mathrm{1}}{\mathrm{log}_{\mathrm{7}} \left(\frac{\mathrm{x}}{\mathrm{x}−\mathrm{3}}\right)}\:<\:\frac{\mathrm{1}}{\mathrm{log}_{\mathrm{7}} \left(\frac{\mathrm{x}}{\mathrm{3}}\right)}…