Question Number 20626 by NECx last updated on 29/Aug/17 Answered by $@ty@m last updated on 30/Aug/17 $$\frac{\mathrm{2}}{{log}_{{a}} {x}}+\frac{\mathrm{1}}{{log}_{{a}} {ax}}+\frac{\mathrm{3}}{{log}_{{a}} {a}^{\mathrm{2}} {x}}=\mathrm{0} \\ $$$$\frac{\mathrm{2}}{{log}_{{a}} {x}}+\frac{\mathrm{1}}{{log}_{{a}} {ax}}+\frac{\mathrm{1}}{{log}_{{a}}…
Question Number 85915 by jagoll last updated on 26/Mar/20 $$\mathrm{3}^{\:^{\mid\mathrm{x}\mid} \mathrm{log}\:\mathrm{27}} \:\geqslant\:\frac{\mathrm{81}}{\mathrm{x}} \\ $$ Answered by john santu last updated on 26/Mar/20 Commented by jagoll…
Question Number 85826 by jagoll last updated on 25/Mar/20 $$\:^{\mathrm{x}} \mathrm{log}\:\left(\mathrm{xy}\right).\:^{\mathrm{y}} \mathrm{log}\:\left(\mathrm{xy}\right)\:+\:^{\mathrm{x}} \mathrm{log}\:\left(\mathrm{x}−\mathrm{y}\right).^{\mathrm{y}} \mathrm{log}\:\left(\mathrm{x}−\mathrm{y}\right)=\mathrm{0} \\ $$$$\mathrm{find}\:\mathrm{x}+\mathrm{y}\: \\ $$ Commented by john santu last updated on…
Question Number 20245 by virus last updated on 24/Aug/17 $$\mathrm{y}=\mathrm{2}^{\frac{\mathrm{1}}{{log}_{{x}} \mathrm{8}}} \\ $$$${then}\:{x}=? \\ $$ Answered by Tinkutara last updated on 24/Aug/17 $${y}\:=\:\mathrm{2}^{\mathrm{log}_{\mathrm{8}} \:{x}} \:=\:\mathrm{2}^{\frac{\mathrm{1}}{\mathrm{3}}\:\mathrm{log}_{\mathrm{2}}…
Question Number 85694 by john santu last updated on 24/Mar/20 $$\mathrm{log}_{\left(\frac{{x}}{{x}−\mathrm{3}}\right)} \left(\mathrm{7}\right)\:<\:\mathrm{log}_{\left(\frac{{x}}{\mathrm{3}}\right)} \:\left(\mathrm{7}\right)\: \\ $$ Commented by jagoll last updated on 24/Mar/20 $$\frac{\mathrm{1}}{\mathrm{log}_{\mathrm{7}} \left(\frac{\mathrm{x}}{\mathrm{x}−\mathrm{3}}\right)}\:<\:\frac{\mathrm{1}}{\mathrm{log}_{\mathrm{7}} \left(\frac{\mathrm{x}}{\mathrm{3}}\right)}…
Question Number 20102 by ajfour last updated on 21/Aug/17 $${Solve}\:{the}\:{equation}: \\ $$$$\left(\mathrm{log}\:_{\mathrm{sin}\:{x}} \mathrm{cos}\:{x}\right)^{\mathrm{2}} =\mathrm{1} \\ $$ Answered by allizzwell23 last updated on 21/Aug/17 $$\:\:\mathrm{log}_{\mathrm{sin}\:{x}} \mathrm{cos}\:{x}\:=\:\mathrm{1}…
Question Number 85433 by jagoll last updated on 22/Mar/20 $$−\mathrm{log}_{\left(\frac{\mathrm{x}}{\mathrm{6}}\right)} \left(\frac{\mathrm{log}_{\mathrm{10}} \sqrt{\mathrm{6}−\mathrm{x}}}{\mathrm{log}_{\mathrm{10}} \mathrm{x}}\right)\:>\:\mathrm{log}_{\mathrm{10}} \left(\frac{\mid\mathrm{x}\mid}{\mathrm{x}}\right) \\ $$ Answered by jagoll last updated on 22/Mar/20 Terms of…
Question Number 85347 by jagoll last updated on 21/Mar/20 $$\mathrm{log}_{\mathrm{0}.\mathrm{5}} ^{\mathrm{2}} \left(\mathrm{8}+\mathrm{2x}−\mathrm{x}^{\mathrm{2}} \right)−\mathrm{7log}_{\mathrm{2}} \left(\mathrm{8}+\mathrm{2x}−\mathrm{x}^{\mathrm{2}} \right)<−\mathrm{12} \\ $$ Commented by john santu last updated on 21/Mar/20…
Question Number 150641 by maged last updated on 14/Aug/21 $$\mathrm{1}+\sqrt{\mathrm{3}^{\mathrm{x}} }=\mathrm{2}^{\mathrm{x}} \\ $$$$\mathrm{x}=? \\ $$ Commented by amin96 last updated on 14/Aug/21 $$\sqrt{\mathrm{3}^{{x}} }=\mathrm{3}^{{m}} \:\:\:\:\mathrm{3}^{{x}}…
Question Number 84986 by jagoll last updated on 18/Mar/20 $$\mathrm{5}^{\left(\mathrm{x}+\mathrm{1}\right)^{\mathrm{2}} } \:+\:\mathrm{625}\:\leqslant\:\mathrm{5}^{\mathrm{x}^{\mathrm{2}} +\mathrm{2}} \:+\:\mathrm{5}^{\mathrm{2x}+\mathrm{3}} \: \\ $$ Commented by mr W last updated on 18/Mar/20…