Question Number 84000 by byaw last updated on 08/Mar/20 Commented by Kunal12588 last updated on 08/Mar/20 $${log}\:\sqrt[{\mathrm{3}}]{\mathrm{0}.\mathrm{0005957}}\:{should}\:{be}\:−{ve}\:? \\ $$ Answered by MJS last updated on…
Question Number 18365 by aplus last updated on 19/Jul/17 Answered by mrW1 last updated on 19/Jul/17 $$\mathrm{x}=\mathrm{6} \\ $$$$\mathrm{y}=\mathrm{2} \\ $$ Commented by mrW1 last…
Question Number 83786 by jagoll last updated on 06/Mar/20 $$\frac{{x}^{\mathrm{2}} }{\mathrm{log}_{\left(\mathrm{5}−{x}\right)} \:\left({x}\right)}\:\leqslant\:\left(\mathrm{5}{x}−\mathrm{4}\right)\:\mathrm{log}_{{x}} \:\left(\mathrm{5}−{x}\right)\: \\ $$ Answered by john santu last updated on 06/Mar/20 $${x}^{\mathrm{2}} \:\mathrm{log}_{{x}}…
Question Number 83774 by jagoll last updated on 06/Mar/20 $$\mathrm{Given}\:\mathrm{2}\sqrt{\mathrm{log}_{\mathrm{3}} \:{x}−\mathrm{1}}\:−\:\mathrm{log}_{\mathrm{3}} \:{x}^{\mathrm{3}} \:+\mathrm{8}\:>\:\mathrm{0} \\ $$$${have}\:\mathrm{the}\:\mathrm{solution}\:\mathrm{a}\:\leqslant\:{x}\:<\:{b}.\: \\ $$$${what}\:{is}\:{b}\:?\: \\ $$ Answered by john santu last updated…
Question Number 83706 by jagoll last updated on 05/Mar/20 $$\mathrm{4}^{\mathrm{x}} \:+\:\mathrm{10}^{\mathrm{x}} \:=\:\mathrm{25}^{\mathrm{x}} \\ $$$$\mathrm{x}\:=\:? \\ $$ Answered by john santu last updated on 05/Mar/20 Terms…
Question Number 18153 by aplus last updated on 16/Jul/17 Commented by prakash jain last updated on 16/Jul/17 $$\mathrm{4}^{\mathrm{2}{x}} =\mathrm{2}×\mathrm{500}^{\mathrm{500}} \\ $$$$\mathrm{2}{x}\mathrm{log}\:\mathrm{4}=\mathrm{log}\:\mathrm{2}+\mathrm{500log}\:\mathrm{500} \\ $$$$\mathrm{3}=\frac{\mathrm{log}\:\mathrm{2}+\mathrm{500log}\:\mathrm{500}}{\mathrm{2log}\:\mathrm{4}}\approx\mathrm{1120}.\mathrm{973} \\ $$…
Question Number 18034 by chux last updated on 14/Jul/17 $$\mathrm{solve}\:\mathrm{for}\:\mathrm{a} \\ $$$$ \\ $$$$\mathrm{5log}\:_{\mathrm{4}} \mathrm{a}+\mathrm{48log}\:_{\mathrm{a}} \mathrm{4}=\frac{\mathrm{a}}{\mathrm{8}} \\ $$ Answered by 433 last updated on 14/Jul/17…
Question Number 18022 by ibraheem160 last updated on 13/Jul/17 $${The}\:{first}\:{term}\:{of}\:{an}\:{A}.{P}\:\:{is}\:{log}^{{a}} \:{and}\:{second}\:{term}\:{is}\: \\ $$$${log}^{{b}} .{show}\:{that}\:{the}\:{sum}\:{of}\:{first}\:{n}\:{terms}\:{in}\: \\ $$$$\frac{\mathrm{1}}{\mathrm{2}}{log}\left[\frac{{b}^{{n}\left({n}−\mathrm{1}\right)} }{{a}^{{n}\left(−\mathrm{3}\right)} }\right] \\ $$ Answered by prakash jain last…
Question Number 17748 by ibraheem160 last updated on 10/Jul/17 $${f}\:{p}^{\mathrm{2}} ={qr},\:\:{prove}\:{thathat}\:{log}_{{r}} ^{{p}} +{log}_{{q}=} ^{{p}} \\ $$$$\mathrm{2}{log}_{{q}} ^{{p}} {log}_{{r}} ^{{p}} \\ $$ Commented by tawa tawa…
Question Number 148494 by liberty last updated on 28/Jul/21 $$\:\:\:\frac{\left(\mathrm{3}+\mathrm{2}\sqrt{\mathrm{2}}\right)^{\mathrm{2008}} }{\left(\mathrm{7}+\mathrm{5}\sqrt{\mathrm{2}}\right)^{\mathrm{1338}} }\:+\:\left(\mathrm{3}−\mathrm{2}\sqrt{\mathrm{2}}\right)\:=\:\mathrm{log}\:_{\mathrm{2}} \left(\mathrm{x}\right) \\ $$$$\:\mathrm{x}=?\: \\ $$ Answered by EDWIN88 last updated on 28/Jul/21 $$\:\mathrm{log}\:_{\mathrm{2}}…