Menu Close

Category: Logarithms

Question-145108

Question Number 145108 by imjagoll last updated on 02/Jul/21 Answered by liberty last updated on 02/Jul/21 $$\:\sqrt[{\mathrm{1}/\mathrm{4}}]{\:\sqrt[{\mathrm{1}/\mathrm{5}}]{\frac{\mathrm{2}^{{x}+\mathrm{1}} }{\mathrm{32}^{\mathrm{2}{x}−\mathrm{2}} }}}=\:\mathrm{64} \\ $$$$\Rightarrow\:\sqrt[{\mathrm{1}/\mathrm{4}}]{\:\left(\frac{\mathrm{2}^{{x}+\mathrm{1}} }{\mathrm{2}^{\mathrm{10}{x}−\mathrm{10}} }\right)^{\mathrm{5}} }=\:\mathrm{2}^{\mathrm{6}} \\…

log-x-2-x-2-1-log-x-4-x-x-

Question Number 145071 by imjagoll last updated on 02/Jul/21 $$\mathrm{log}\:_{\left(\frac{\mathrm{x}}{\mathrm{2}}\right)} \left(\mathrm{x}+\mathrm{2}\right)\:=\:\mathrm{1}+\:\mathrm{log}\:_{\mathrm{x}} \left(\mathrm{4}−\mathrm{x}\right) \\ $$$$\:\mathrm{x}=? \\ $$ Answered by MJS_new last updated on 02/Jul/21 $$\mathrm{we}\:\mathrm{can}\:\mathrm{only}\:\mathrm{approximate} \\…

log-3-x-1-log-4-x-8-x-

Question Number 145067 by imjagoll last updated on 02/Jul/21 $$\:\mathrm{log}\:_{\mathrm{3}} \left({x}+\mathrm{1}\right)\:=\mathrm{log}\:_{\mathrm{4}} \left({x}+\mathrm{8}\right) \\ $$$$\:{x}=? \\ $$ Answered by bobhans last updated on 02/Jul/21 $$\:\mathrm{x}=\mathrm{8}\:\Rightarrow\mathrm{log}\:_{\mathrm{3}} \left(\mathrm{8}+\mathrm{1}\right)=\mathrm{log}\:_{\mathrm{4}}…

4-2x-1-1-4-2-log-2-2x-gt-2-log-x-2-log-1-x-2-2x-

Question Number 79263 by jagoll last updated on 23/Jan/20 $$\mathrm{4}^{\mathrm{2x}−\mathrm{1}} +\frac{\mathrm{1}}{\mathrm{4}}\:^{\mathrm{2}} \mathrm{log}^{\mathrm{2}} \left(\mathrm{2x}\right)>\:^{\mathrm{2}} \mathrm{log}\left(\mathrm{x}\right) \\ $$$$\left\{^{\mathrm{2}} \mathrm{log}\left(\frac{\mathrm{1}}{\mathrm{x}}\right)−\mathrm{2}^{\mathrm{2x}} \right\} \\ $$ Commented by john santu last…

Question-13151

Question Number 13151 by Tinkutara last updated on 15/May/17 Answered by mrW1 last updated on 16/May/17 $${x}>\mathrm{9} \\ $$$$\mathrm{log}\:\left(\mathrm{2}{x}−\mathrm{1}\right)\left({x}−\mathrm{9}\right)>\mathrm{2} \\ $$$$\left(\mathrm{2}{x}−\mathrm{1}\right)\left({x}−\mathrm{9}\right)>\mathrm{100} \\ $$$$\mathrm{2}{x}^{\mathrm{2}} −\mathrm{19}{x}−\mathrm{91}>\mathrm{0} \\…

If-t-x-2-3-3x-7-then-log-1-t-can-to-find-for-a-2-lt-x-lt-6-b-2-lt-x-lt-5-c-2-x-6-d-x-2-or-x-gt-6-e-x-lt-1-or-x-gt-3-

Question Number 65930 by gunawan last updated on 06/Aug/19 $$\mathrm{If}\:{t}=\frac{{x}^{\mathrm{2}} −\mathrm{3}}{\mathrm{3}{x}+\mathrm{7}}\:\mathrm{then} \\ $$$$\mathrm{log}\left(\mathrm{1}−\mid{t}\mid\right)\:\mathrm{can}\:\mathrm{to}\:\mathrm{find}\:\mathrm{for} \\ $$$$\mathrm{a}.\:\mathrm{2}<{x}<\mathrm{6} \\ $$$${b}.−\:\mathrm{2}<{x}<\mathrm{5} \\ $$$${c}.−\:\mathrm{2}\leqslant{x}\leqslant\mathrm{6} \\ $$$$\mathrm{d}.\:{x}\leqslant−\mathrm{2}\:\mathrm{or}\:{x}>\mathrm{6} \\ $$$${e}.\:{x}<−\mathrm{1}\:{or}\:{x}>\mathrm{3} \\ $$…

log-6-36-2-log-3-4-2-log-3-12-

Question Number 65931 by gunawan last updated on 06/Aug/19 $$\frac{\left(\mathrm{log}_{\mathrm{6}} \mathrm{36}\right)^{\mathrm{2}} −\left(\mathrm{log}_{\mathrm{3}} \mathrm{4}\right)^{\mathrm{2}} }{\mathrm{log}_{\mathrm{3}} \left(\sqrt{\mathrm{12}}\right)}=… \\ $$ Answered by $@ty@m123 last updated on 06/Aug/19 $$=\frac{\left(\mathrm{log}\:_{\mathrm{6}}…