Category: Logarithms

Question Number 145829 by bramlexs22 last updated on 08/Jul/21 Answered by EDWIN88 last updated on 08/Jul/21 $$\left(1\right)\sqrt{x+\frac{15}{4}}\ne 1;x\ne -\frac{11}{4}$$$$andx>-\frac{15}{4}$$$$\left(2\right)(x^2-\frac{8}{3}x)>0\Rightarrow x(x-\frac{8}{3})>0$$$$\Rightarrow{x}<\mathrm{0}\:\cup\:{x}>\frac{\mathrm{8}}{\mathrm{3}} \…

Question Number 14701 by tawa tawa last updated on 03/Jun/17 Commented by mrW1 last updated on 03/Jun/17 $$Ithinknoneoftheanswersisright.$$$$xy={20}^1=20$$$${x}+{y}=\mathrm{5}^{\mathrm{2}} =\mathrm{25} \…

Question Number 14404 by Nysiroke last updated on 31/May/17 $$solveforxandyin$$$$$$$$x^{y^y}=log8$$$$x^{x^x}=log3$$ Commented by prakash…

Question Number 145108 by imjagoll last updated on 02/Jul/21 Answered by liberty last updated on 02/Jul/21 $$\sqrt[1/4]{\sqrt[1/5]{\frac{2^{x+1}}{{32}^{2x-2}}}}=64$$$$\Rightarrow\:\sqrt[{\mathrm{1}/\mathrm{4}}]{\:\left(\frac{\mathrm{2}^{{x}+\mathrm{1}} }{\mathrm{2}^{\mathrm{10}{x}−\mathrm{10}} }\right)^{\mathrm{5}} }=\:\mathrm{2}^{\mathrm{6}} \…

Question Number 145067 by imjagoll last updated on 02/Jul/21 $$\log {}_3(x+1)=\log {}_4(x+8)$$$$x=?$$ Answered by bobhans last updated on 02/Jul/21 $$\:\mathrm{x}=\mathrm{8}\:\Rightarrow\mathrm{log}\:_{\mathrm{3}} \left(\mathrm{8}+\mathrm{1}\right)=\mathrm{log}\:_{\mathrm{4}}…