Question Number 5579 by Rasheed Soomro last updated on 21/May/16 $$\mathrm{Without}\:\mathrm{using}\:\mathrm{a}\:\mathrm{calculator},\:\mathrm{evaluate} \\ $$$$\left(\mathrm{log}\:\mathrm{5}\right)^{\mathrm{2}} +\mathrm{log}\:\mathrm{2}\:\mathrm{log}\:\mathrm{50} \\ $$ Answered by FilupSmith last updated on 21/May/16 $$\mathrm{log}\:{x}\:=\:\mathrm{log}_{\mathrm{10}} {x}…
Question Number 5569 by Rasheed Soomro last updated on 20/May/16 $$\mathrm{The}\:\mathrm{result}\:“\mathrm{log}\:\mathrm{xy}=\mathrm{log}\:\mathrm{x}+\mathrm{log}\:\mathrm{y}''\:\mathrm{is}\:\mathrm{not} \\ $$$$\mathrm{always}\:\mathrm{true}!\:\mathrm{Give}\:\mathrm{a}\:\mathrm{pair}\:\mathrm{of}\:\mathrm{values}\:\mathrm{of} \\ $$$$\mathrm{x}\:\mathrm{and}\:\mathrm{y}\:\mathrm{such}\:\mathrm{that}\:\mathrm{the}\:\mathrm{result}\:\mathrm{will}\:\mathrm{not}\:\mathrm{hold}. \\ $$ Commented by Yozzii last updated on 20/May/16 $$\left({x},{y}\right)=\left(−\mathrm{1},\mathrm{2}\right)…
Question Number 71016 by mr W last updated on 10/Oct/19 $$\boldsymbol{\mathrm{ln}}\:\left(\boldsymbol{{e}}+\boldsymbol{\mathrm{ln}}\:\left(\boldsymbol{{e}}+\boldsymbol{\mathrm{ln}}\:\left(\boldsymbol{{e}}+…\right)\right)\right)=? \\ $$ Answered by mr W last updated on 11/Oct/19 $$\boldsymbol{\mathrm{ln}}\:\left(\boldsymbol{{e}}+\boldsymbol{\mathrm{ln}}\:\left(\boldsymbol{{e}}+\boldsymbol{\mathrm{ln}}\:\left(\boldsymbol{{e}}+…\right)\right)\right)={x} \\ $$$$\boldsymbol{\mathrm{ln}}\:\left(\boldsymbol{{e}}+{x}\right)={x} \\…
Question Number 5464 by 3 last updated on 15/May/16 $$+\boxtimes\boldsymbol{\div}\:\fallingdotseq \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 136256 by EDWIN88 last updated on 20/Mar/21 $$\mathrm{log}\:_{\left(\mathrm{x}−\mathrm{2}\right)} \left(\mathrm{10}−\mathrm{3x}\right)\:<\:\mathrm{2} \\ $$ Answered by liberty last updated on 20/Mar/21 $$\left(\mathrm{1}\right)\:\mathrm{10}−\mathrm{3}{x}\:>\:\mathrm{0}\:;\:\mathrm{3}{x}−\mathrm{10}<\mathrm{0} \\ $$$$\:\:\:\:\:\:\:\:{x}\:<\:\frac{\mathrm{10}}{\mathrm{3}} \\ $$$$\left(\mathrm{2}\right)\:\mathrm{log}\:_{\left({x}−\mathrm{2}\right)}…
Question Number 5056 by Rasheed Soomro last updated on 06/Apr/16 $${x}\neq{y}\:\wedge\:{y}\neq\mathrm{0}\:\wedge\:\mathrm{log}_{\frac{\mathrm{x}}{\mathrm{y}}} \left(\frac{\mathrm{x}^{\mathrm{2}} }{\mathrm{y}^{\mathrm{3}} }\right)=? \\ $$ Commented by Yozzii last updated on 06/Apr/16 $${log}_{{x}/{y}} {x}^{\mathrm{2}}…
Question Number 5039 by Rasheed Soomro last updated on 05/Apr/16 $$\mathrm{log}_{\left(\frac{\mathrm{x}}{\mathrm{y}}\right)} \left(\frac{\mathrm{y}}{\mathrm{x}}\right)=? \\ $$ Answered by LMTV last updated on 05/Apr/16 $$\left(\frac{{x}}{{y}}\right)^{?} =\frac{{y}}{{x}} \\ $$$$?=−\mathrm{1}…
Question Number 136064 by bramlexs22 last updated on 18/Mar/21 $$\:\:\:\:\:\mathrm{3}^{\mathrm{log}\:_{\mathrm{2}} \left(\mathrm{3}^{{x}} −\mathrm{1}\right)} \:=\:\mathrm{2}^{\mathrm{log}\:_{\mathrm{3}} \left(\mathrm{2}^{{x}} +\mathrm{1}\right)} +\:\mathrm{1} \\ $$ Answered by Kintinu last updated on 18/Mar/21…
Question Number 4816 by Kelvin last updated on 15/Mar/16 Commented by prakash jain last updated on 15/Mar/16 $$\mathrm{log}\:.\mathrm{006}−\mathrm{log}\:.\mathrm{0012}=\mathrm{log}\:\frac{.\mathrm{006}}{.\mathrm{0012}}=\mathrm{log}\:\frac{\mathrm{60}}{\mathrm{12}}=\mathrm{log}\:\mathrm{5} \\ $$$$\mathrm{log}\:.\mathrm{007}−\mathrm{log}\:.\mathrm{00243}=\mathrm{log}\:\frac{.\mathrm{007}}{.\mathrm{00243}}=\mathrm{log}\:\frac{\mathrm{700}}{\mathrm{243}} \\ $$$$\mathrm{log}\:.\mathrm{008}+\mathrm{log}\:\mathrm{4000}=\mathrm{log}\:\left(.\mathrm{008}×\mathrm{4000}\right)=\mathrm{log}\:\mathrm{32}=\mathrm{5log}\:\mathrm{2} \\ $$$$\mathrm{log}\:.\mathrm{0128}=\mathrm{7log}\:\mathrm{2}−\mathrm{log}\:\mathrm{10000}=\mathrm{7log}\:\mathrm{2}−\mathrm{4} \\…
Question Number 70270 by Shamim last updated on 02/Oct/19 $$\mathrm{If}\:\mathrm{log}_{\mathrm{x}} \mathrm{y}\:=\:\mathrm{6}\:\&\:\mathrm{log}_{\mathrm{14x}} \mathrm{8y}\:=\:\mathrm{3}\:\mathrm{then}\:\mathrm{find}\:\mathrm{the} \\ $$$$\mathrm{value}\:\mathrm{of}\:\mathrm{x}\:\&\:\mathrm{y}. \\ $$ Answered by Rio Michael last updated on 02/Oct/19 $${log}_{{x}}…