Question Number 4816 by Kelvin last updated on 15/Mar/16 Commented by prakash jain last updated on 15/Mar/16 $$\mathrm{log}\:.\mathrm{006}−\mathrm{log}\:.\mathrm{0012}=\mathrm{log}\:\frac{.\mathrm{006}}{.\mathrm{0012}}=\mathrm{log}\:\frac{\mathrm{60}}{\mathrm{12}}=\mathrm{log}\:\mathrm{5} \\ $$$$\mathrm{log}\:.\mathrm{007}−\mathrm{log}\:.\mathrm{00243}=\mathrm{log}\:\frac{.\mathrm{007}}{.\mathrm{00243}}=\mathrm{log}\:\frac{\mathrm{700}}{\mathrm{243}} \\ $$$$\mathrm{log}\:.\mathrm{008}+\mathrm{log}\:\mathrm{4000}=\mathrm{log}\:\left(.\mathrm{008}×\mathrm{4000}\right)=\mathrm{log}\:\mathrm{32}=\mathrm{5log}\:\mathrm{2} \\ $$$$\mathrm{log}\:.\mathrm{0128}=\mathrm{7log}\:\mathrm{2}−\mathrm{log}\:\mathrm{10000}=\mathrm{7log}\:\mathrm{2}−\mathrm{4} \\…
Question Number 70270 by Shamim last updated on 02/Oct/19 $$\mathrm{If}\:\mathrm{log}_{\mathrm{x}} \mathrm{y}\:=\:\mathrm{6}\:\&\:\mathrm{log}_{\mathrm{14x}} \mathrm{8y}\:=\:\mathrm{3}\:\mathrm{then}\:\mathrm{find}\:\mathrm{the} \\ $$$$\mathrm{value}\:\mathrm{of}\:\mathrm{x}\:\&\:\mathrm{y}. \\ $$ Answered by Rio Michael last updated on 02/Oct/19 $${log}_{{x}}…
Question Number 70252 by Shamim last updated on 02/Oct/19 $$\mathrm{If},\:\mathrm{log}\:\mathrm{x}^{\mathrm{y}} \:=\:\mathrm{6}\:\mathrm{and}\:\mathrm{log}\:\mathrm{14x}^{\mathrm{8y}} \:=\:\mathrm{3}\:\mathrm{then}\:\mathrm{find} \\ $$$$\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\mathrm{x},\:\mathrm{y}. \\ $$ Answered by MJS last updated on 02/Oct/19 $$\mathrm{log}\:{x}^{{y}} =\mathrm{6}\:\Rightarrow\:{y}\mathrm{log}\:{x}\:=\mathrm{6}…
Question Number 4696 by love math last updated on 22/Feb/16 $$\mathrm{5}×\mathrm{4}^{{x}} +\mathrm{2}×\mathrm{25}^{{x}} <\mathrm{7}×\mathrm{10}^{{x}} \\ $$ Commented by prakash jain last updated on 22/Feb/16 $$\mathrm{5}×\mathrm{2}^{\mathrm{2}{x}} +\mathrm{2}×\mathrm{5}^{\mathrm{2}{x}}…
Question Number 4615 by love math last updated on 14/Feb/16 $$\mathrm{2}^{{log}_{\mathrm{0}.\mathrm{5}} ^{\mathrm{2}} {x}} +{x}^{{log}_{\mathrm{0}.\mathrm{5}} {x}} >\mathrm{2}.\mathrm{5} \\ $$ Answered by Yozzii last updated on 14/Feb/16…
Question Number 4614 by love math last updated on 14/Feb/16 $$\sqrt{{x}^{{log}_{\mathrm{2}} \sqrt{{x}}} }>\mathrm{2} \\ $$ Commented by Yozzii last updated on 14/Feb/16 $${Squaring}\:{both}\:{sides}\:{of}\:{the}\:{given}\: \\ $$$${inequality}\:{yields}\:{the}\:{following}.…
Question Number 4592 by love math last updated on 09/Feb/16 $$\frac{\mathrm{1}}{\mathrm{2}}+{log}_{\mathrm{9}} {x}−{log}_{\mathrm{3}} \mathrm{5}{x}>{log}_{\frac{\mathrm{1}}{\mathrm{3}}} \left({x}+\mathrm{1}\right) \\ $$ Answered by Rasheed Soomro last updated on 10/Feb/16 $$\frac{\mathrm{1}}{\mathrm{2}}+{log}_{\mathrm{9}}…
Question Number 4559 by love math last updated on 07/Feb/16 $$\left(\mathrm{0};\left(\mathrm{4}\right)\right)^{{x}^{\mathrm{2}} −\mathrm{1}} >\left(\mathrm{0},\left(\mathrm{6}\right)\right)^{{x}^{\mathrm{2}} +\mathrm{6}} \\ $$ Commented by Yozzii last updated on 07/Feb/16 $${What}\:{is}\:\left(\mathrm{0},\left(\mathrm{6}\right)\right)\:{and}\:\left(\mathrm{0};\left(\mathrm{4}\right)\right)? \\…
Question Number 4515 by love math last updated on 04/Feb/16 $$\mathrm{3}^{\mathrm{2}+{log}_{\mathrm{9}} \mathrm{25}} =\mathrm{5}×\mathrm{9}^{\frac{\mathrm{2}}{{x}}} \\ $$ Commented by love math last updated on 05/Feb/16 $${Is}\:{there}\:{any}\:{way}\:{to}\:{prove}\:\mathrm{3}^{\mathrm{2}+{log}_{\mathrm{9}} \mathrm{25}}…
Question Number 4477 by love math last updated on 30/Jan/16 $$\mathrm{2}\:{log}\:\left({x}−\mathrm{2}\right)+{log}\:\left({x}−\mathrm{4}\right)^{\mathrm{2}} =\mathrm{0} \\ $$$$ \\ $$$${Determine}\:{the}\:{domain}\:{of}\:{x}\:{and}\:{find}\:{the}\:{value}\:{of}\:{x}. \\ $$ Answered by Rasheed Soomro last updated on…