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Category: Logarithms

Question-4816

Question Number 4816 by Kelvin last updated on 15/Mar/16 Commented by prakash jain last updated on 15/Mar/16 log.006log.0012=log.006.0012=log6012=log5log.007log.00243=log.007.00243=log700243log.008+log4000=log(.008×4000)=log32=5log2$$\mathrm{log}\:.\mathrm{0128}=\mathrm{7log}\:\mathrm{2}−\mathrm{log}\:\mathrm{10000}=\mathrm{7log}\:\mathrm{2}−\mathrm{4} \