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Category: Logarithms

0-5-log-10-x-2-55x-90-log-10-x-36-log-10-2-Find-the-value-s-of-x-and-determine-the-domain-of-x-

Question Number 4457 by love math last updated on 29/Jan/16 $$\mathrm{0}.\mathrm{5}\:\left({log}_{\mathrm{10}} \left({x}^{\mathrm{2}} −\mathrm{55}{x}+\mathrm{90}\right)\:−\:{log}_{\mathrm{10}} \left({x}−\mathrm{36}\right)\right)=\:{log}_{\mathrm{10}} \sqrt{\mathrm{2}} \\ $$$${Find}\:{the}\:{value}\left({s}\right)\:{of}\:{x}\:{and}\:{determine}\:{the}\:{domain}\:{of}\:{x}. \\ $$ Commented by Yozzii last updated on…

Identify-domain-and-range-of-this-function-that-f-x-ln-4-x-4-x-

Question Number 69974 by Shamim last updated on 29/Sep/19 $$\mathrm{Identify}\:\mathrm{domain}\:\mathrm{and}\:\mathrm{range}\:\mathrm{of}\:\mathrm{this}\: \\ $$$$\mathrm{function}\:\mathrm{that}\:\mathrm{f}\left(\mathrm{x}\right)=\:\mathrm{ln}\frac{\mathrm{4}−\mathrm{x}}{\mathrm{4}+\mathrm{x}}. \\ $$ Commented by kaivan.ahmadi last updated on 29/Sep/19 $$\frac{\mathrm{4}−{x}}{\mathrm{4}+{x}}>\mathrm{0}\Rightarrow−\mathrm{4}<{x}<\mathrm{4} \\ $$$$\Rightarrow{D}_{{f}} =\left(−\mathrm{4},\mathrm{4}\right)…

Question-69018

Question Number 69018 by Maclaurin Stickker last updated on 17/Sep/19 Commented by Prithwish sen last updated on 18/Sep/19 $$\mathrm{It}\:\mathrm{is}\:\mathrm{only}\:\mathrm{possible}\:\mathrm{when} \\ $$$$\mathrm{4}\boldsymbol{\mathrm{a}}+\mathrm{5}\boldsymbol{\mathrm{b}}+\mathrm{1}=\mathrm{8}\boldsymbol{\mathrm{ab}}+\mathrm{1} \\ $$$$\Rightarrow\mathrm{4}\boldsymbol{\mathrm{a}}+\mathrm{5}\boldsymbol{\mathrm{b}}=\mathrm{8}\boldsymbol{\mathrm{ab}}…………\left(\boldsymbol{\mathrm{i}}\right) \\ $$$$\boldsymbol{\mathrm{and}}…

I-don-t-know-the-value-of-Log-1-but-I-calculate-it-in-the-following-way-1-2-1-Log-1-2-Log-1-2-Log-1-0-Log-1-0-2-0-Am-I-correct-If-no-why-

Question Number 3239 by Rasheed Soomro last updated on 08/Dec/15 $$\mathcal{I}\:{don}'{t}\:{know}\:{the}\:{value}\:{of}\:\:{Log}\left(−\mathrm{1}\right)\:{but}\:{I}\:{calculate} \\ $$$${it}\:{in}\:{the}\:{following}\:{way}\:: \\ $$$$\:\:\:\:\:\:\:\:\:\:\left(−\mathrm{1}\right)^{\mathrm{2}} =\mathrm{1} \\ $$$$\:\:\:\:\:\Rightarrow\:\:{Log}\left(−\mathrm{1}\right)^{\mathrm{2}} ={Log}\left(\mathrm{1}\right) \\ $$$$\:\:\:\:\:\Rightarrow\:\:\mathrm{2}×{Log}\left(−\mathrm{1}\right)=\mathrm{0} \\ $$$$\:\:\:\:\:\Rightarrow\:{Log}\left(−\mathrm{1}\right)=\frac{\mathrm{0}}{\mathrm{2}}=\mathrm{0} \\ $$$${Am}\:\mathcal{I}\:{correct}?\:\mathcal{I}{f}\:{no},{why}?…