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Category: Logarithms

Seja-53-log-1-e-x-11-1-9999999-1-Calcule-x-1-x-2-0-9-

Question Number 66396 by hmamarques1994@gmai.com last updated on 14/Aug/19 $$\: \\ $$$$\:\boldsymbol{\mathrm{Seja}}\:\:\mathrm{53}^{\boldsymbol{\mathrm{log}}_{\frac{\mathrm{1}}{\:\sqrt{\boldsymbol{{e}}^{\boldsymbol{\pi}} }}} \left[\sqrt[{\mathrm{9999999}}]{\left(\boldsymbol{{x}}+\mathrm{11}\right)!}\right]} \:=\:\mathrm{1}. \\ $$$$\: \\ $$$$\: \\ $$$$\: \\ $$$$\:\boldsymbol{\mathrm{Calcule}}\:\:\frac{\boldsymbol{\mathrm{x}}_{\mathrm{1}} }{\boldsymbol{\mathrm{x}}_{\mathrm{2}} }+\mathrm{0},\mathrm{9}.…

Value-of-x-satiesfied-y-log-4-x-2-1-4x-2-2x-1-negative-value-is-a-1-lt-x-lt-2-b-2-lt-x-lt-1-c-2-lt-x-lt-2-d-2-lt-x-lt-1-e-x-lt-2-

Question Number 66355 by gunawan last updated on 13/Aug/19 $${V}\mathrm{alue}\:\mathrm{of}\:{x}\:\mathrm{satiesfied}\:{y}=\frac{\mathrm{log}_{\mathrm{4}} \left({x}^{\mathrm{2}} −\mathrm{1}\right)}{\mathrm{4}{x}^{\mathrm{2}} +\mathrm{2}{x}+\mathrm{1}} \\ $$$${negative}\:{value}\:\mathrm{is}… \\ $$$$\mathrm{a}.\:−\mathrm{1}<{x}<\sqrt{\mathrm{2}} \\ $$$${b}.\:−\sqrt{\mathrm{2}}<{x}<\mathrm{1} \\ $$$${c}.\:−\sqrt{\mathrm{2}}<{x}<\sqrt{\mathrm{2}} \\ $$$${d}.\:−\sqrt{\mathrm{2}}<{x}<−\mathrm{1} \\ $$$${e}.\:{x}<−\mathrm{2}…

If-2x-y-8-and-x-y-3-2-log-10-2-log-8-36-then-x-2-3y-a-28-b-22-c-20-d-16-e-12-

Question Number 66354 by gunawan last updated on 13/Aug/19 $$\mathrm{If}\:\:\mathrm{2}{x}+{y}=\mathrm{8}\:\mathrm{and} \\ $$$$\left({x}+{y}\right)=\frac{\mathrm{3}}{\mathrm{2}}\mathrm{log}_{\mathrm{10}} \:\mathrm{2}.\mathrm{log}_{\mathrm{8}} \mathrm{36} \\ $$$$\mathrm{then}\:\mathrm{x}^{\mathrm{2}} +\mathrm{3y}=… \\ $$$$\mathrm{a}.\:\mathrm{28} \\ $$$$\mathrm{b}.\:\mathrm{22} \\ $$$$\mathrm{c}.\:\mathrm{20} \\ $$$$\mathrm{d}.\:\mathrm{16}…

Value-of-maximum-f-x-2-log-x-5-2-log-3-x-is-a-4-b-8-c-12-d-15-e-16-

Question Number 66279 by gunawan last updated on 12/Aug/19 $$\mathrm{Value}\:\mathrm{of}\:\mathrm{maximum} \\ $$$${f}\left({x}\right)=^{\mathrm{2}} \mathrm{log}\left({x}+\mathrm{5}\right)+^{\mathrm{2}} \mathrm{log}\left(\mathrm{3}−{x}\right) \\ $$$$\mathrm{is}… \\ $$$$\mathrm{a}.\mathrm{4} \\ $$$$\mathrm{b}.\mathrm{8} \\ $$$$\mathrm{c}.\:\mathrm{12} \\ $$$$\mathrm{d}.\:\mathrm{15} \\…

log-2-sin-x-1-cos-x-2-2pi-3-x-pi-3-

Question Number 131661 by benjo_mathlover last updated on 07/Feb/21 $$\:\:\:\mathrm{log}\:_{\sqrt{\mathrm{2}}\:\mathrm{sin}\:\mathrm{x}} \left(\mathrm{1}+\mathrm{cos}\:\mathrm{x}\right)\:=\:\mathrm{2} \\ $$$$\:−\frac{\mathrm{2}\pi}{\mathrm{3}}\leqslant\mathrm{x}\leqslant\frac{\pi}{\mathrm{3}} \\ $$ Answered by liberty last updated on 07/Feb/21 $$\:\begin{cases}{\sqrt{\mathrm{2}}\:\mathrm{sin}\:\mathrm{x}\:>\mathrm{0}\:;\:\mathrm{x}\:\mathrm{in}\:\mathrm{I}\:\mathrm{or}\:\mathrm{II}\:\mathrm{quadrant}}\\{\sqrt{\mathrm{2}}\:\mathrm{sin}\:\mathrm{x}\:\neq\:\mathrm{1}\Rightarrow\mathrm{sin}\:\mathrm{x}\neq\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}}}\end{cases} \\ $$$$\Leftrightarrow\:\mathrm{1}+\mathrm{cos}\:\mathrm{x}\:=\:\left(\sqrt{\mathrm{2}}\:\mathrm{sin}\:\mathrm{x}\right)^{\mathrm{2}}…

If-log-2-a-log-3-b-m-and-log-3-a-log-2-b-n-a-gt-1-and-b-gt-1-then-m-n-a-log-2-3-b-log-3-2-c-log-4-9-d-log-2-3-2-e-log-3-2-2-

Question Number 65972 by gunawan last updated on 07/Aug/19 $$\mathrm{If}\:\frac{\mathrm{log}_{\mathrm{2}} \:{a}}{\mathrm{log}_{\mathrm{3}} \:{b}}={m}\:\mathrm{and}\:\frac{\mathrm{log}_{\mathrm{3}} \:{a}}{\mathrm{log}_{\mathrm{2}} \:{b}}={n} \\ $$$${a}>\mathrm{1}\:\mathrm{and}\:{b}>\mathrm{1} \\ $$$$\mathrm{then}\:\frac{{m}}{{n}}=… \\ $$$${a}.\mathrm{log}_{\mathrm{2}} \:\mathrm{3} \\ $$$${b}.\:\mathrm{log}_{\mathrm{3}} \:\mathrm{2} \\…

log-5-27-log-9-125-log-16-12-a-61-36-b-9-4-c-61-20-d-41-12-e-7-2-

Question Number 65970 by gunawan last updated on 07/Aug/19 $$\mathrm{log}_{\mathrm{5}} \sqrt{\mathrm{27}}×\mathrm{log}_{\mathrm{9}} \mathrm{125}+\mathrm{log}_{\mathrm{16}} \mathrm{12}=… \\ $$$${a}.\:\frac{\mathrm{61}}{\mathrm{36}} \\ $$$${b}.\:\frac{\mathrm{9}}{\mathrm{4}} \\ $$$${c}.\:\frac{\mathrm{61}}{\mathrm{20}} \\ $$$${d}.\:\frac{\mathrm{41}}{\mathrm{12}} \\ $$$${e}.\:\frac{\mathrm{7}}{\mathrm{2}} \\ $$…