Category: Logarithms

Question Number 55806 by Tawa1 last updated on 04/Mar/19 $$\mathrm{Solve}\mathrm{for}\mathrm{x}:{\mathrm{x}}^{{\log }_{3}2}=\sqrt{\mathrm{x}}+1$$ Answered by MJS last updated on 04/Mar/19 $$\mathrm{ln}\:{x}^{\mathrm{log}_{\mathrm{3}} \:\mathrm{2}} =\mathrm{ln}\:{x}^{\frac{\mathrm{ln}\:\mathrm{2}}{\mathrm{ln}\:\mathrm{3}}} =\frac{\mathrm{ln}\:\mathrm{2}}{\mathrm{ln}\:\mathrm{3}}\mathrm{ln}\:{x}\:=…

Question Number 121201 by Ar Brandon last updated on 05/Nov/20 Commented by Ar Brandon last updated on 06/Nov/20 Commented by MJS_new last updated on 06/Nov/20…

Question Number 121138 by Ar Brandon last updated on 05/Nov/20 Answered by TANMAY PANACEA last updated on 05/Nov/20 $$x^{x-x^{-\frac{1}{2}}}={\left(x^{-\frac{1}{2}}\right)}^{x+x^{\frac{-1}{2}}}$$$${x}−{x}^{−\frac{\mathrm{1}}{\mathrm{2}}}…

Question Number 121045 by Ar Brandon last updated on 05/Nov/20 Terms of Service Privacy Policy Contact: info@tinkutara.com

Question Number 120927 by Ar Brandon last updated on 04/Nov/20 Answered by 675480065 last updated on 04/Nov/20 $$\mathrm{domain}:2\mathrm{x}-3/4>0\cap \mathrm{x}>0\cap \mathrm{x}>1$$$$\Rightarrow \mathrm{x}>3/8\cap \mathrm{x}>0$$$$\mathrm{hence}2\mathrm{x}-3/4>{\mathrm{x}}^2$$$$\Rightarrow\:\mathrm{x}^{\mathrm{2}} −\mathrm{2x}+\mathrm{3}/\mathrm{4}\:<\mathrm{0}…