Question Number 13891 by Tinkutara last updated on 24/May/17 $$\mathrm{Consider}\:{n}\:\mathrm{red}\:\mathrm{and}\:{n}\:\mathrm{blue}\:\mathrm{points}\:\mathrm{in} \\ $$$$\mathrm{the}\:\mathrm{plane},\:\mathrm{no}\:\mathrm{three}\:\mathrm{of}\:\mathrm{them}\:\mathrm{being}\:\mathrm{collinear}. \\ $$$$\mathrm{Prove}\:\mathrm{that}\:\mathrm{one}\:\mathrm{can}\:\mathrm{connect}\:\mathrm{each}\:\mathrm{red} \\ $$$$\mathrm{point}\:\mathrm{to}\:\mathrm{a}\:\mathrm{blue}\:\mathrm{one}\:\mathrm{with}\:\mathrm{a}\:\mathrm{segment} \\ $$$$\mathrm{such}\:\mathrm{that}\:\mathrm{no}\:\mathrm{two}\:\mathrm{segments}\:\mathrm{intersect}. \\ $$ Commented by mrW1 last updated…
Question Number 144479 by byaw last updated on 25/Jun/21 $$ \\ $$$$\mathrm{Consider}\:\mathrm{the}\:\mathrm{followinge} \\ $$$$\mathrm{statments} \\ $$$$\mathrm{P}:\:\mathrm{All}\:\mathrm{students}\:\mathrm{with}\:\mathrm{measles} \\ $$$$\:\mathrm{stay}\:\mathrm{in}\:\mathrm{the}\:\mathrm{sick}\:\mathrm{bay}. \\ $$$$\mathrm{T}:\:\mathrm{All}\:\mathrm{students}\:\mathrm{in}\:\mathrm{the}\:\mathrm{sick} \\ $$$$\:\mathrm{bay}\:\mathrm{do}\:\mathrm{not}\:\mathrm{do}\:\mathrm{homework}. \\ $$$$\mathrm{Which}\:\mathrm{of}\:\mathrm{the}\:\mathrm{following} \\…
Question Number 78671 by berket last updated on 19/Jan/20 $${prove}\:{p}\Rightarrow{q}\:{and}\:{negetion}\:{of}\:{q}\Rightarrow{negation}\:{of}\:{p} \\ $$ Answered by Rio Michael last updated on 19/Jan/20 $${to}\:{prove}\:{that}\:{p}\Rightarrow{q}\:\equiv\:{q}\:\Rightarrow\sim{p} \\ $$$$\:\:\mathrm{1}\:\:\boldsymbol{{set}}\:\boldsymbol{{up}}\:\boldsymbol{{a}}\:\boldsymbol{{truth}}\:\boldsymbol{{table}} \\ $$$${p}\:\:\:\:\:\:\:\:\:{q}\:\:\:\:\:\:\:\:\sim{p}\:\:\:\:\:\:\:\:\:\sim{q}\:\:\:\:\:\:\:\:{p}\Rightarrow{q}\:\:\:\:\:\:\:\sim{q}\:\Rightarrow\sim{p}…
Question Number 247 by 123456 last updated on 25/Jan/15 $$\mathrm{A}:\mathrm{C}\:\mathrm{is}\:\mathrm{false} \\ $$$$\mathrm{B}:\mathrm{C}\vee\mathrm{A}\:\mathrm{is}\:\mathrm{false} \\ $$$$\mathrm{C}:\mathrm{B}\:\mathrm{is}\:\mathrm{truth} \\ $$$$\mathrm{then}\:\mathrm{if}\:\mathrm{possible}\:\mathrm{F}\:\mathrm{is}\:\mathrm{truth}\:\mathrm{or}\:\mathrm{false}? \\ $$$$\mathrm{F}:\left(\mathrm{A}\wedge\mathrm{B}\right)\vee\left(\mathrm{A}\wedge\mathrm{C}\right)\vee\left(\mathrm{B}\wedge\mathrm{C}\right)\: \\ $$ Answered by prakash jain last…
Question Number 11801 by 786786AM last updated on 01/Apr/17 $$\mathrm{pl}\:\mathrm{show}\:\mathrm{me}\:\mathrm{app}? \\ $$ Commented by FilupS last updated on 01/Apr/17 $$? \\ $$ Terms of Service…
Question Number 11145 by FilupS last updated on 14/Mar/17 $$\mathrm{let}\:\mathrm{set}\:{S}=\mathbb{R} \\ $$$$\mathrm{let}\:{nS}=\left\{\underset{{n}\:\mathrm{sets}\:\mathrm{of}\:\mathbb{R}} {\mathbb{R},\:\mathbb{R},\:…,\:\mathbb{R}}\right\}\:\:\:\:\:\:\:\:\:{n}\in\mathbb{Z}^{+} \\ $$$$\mathrm{is}\:\mid{S}\mid<\mid{nS}\mid? \\ $$$$\: \\ $$$$\mathrm{what}\:\mathrm{if}\:{n}=\mid{S}\mid? \\ $$ Commented by prakash jain…
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Question Number 141087 by greg_ed last updated on 15/May/21 $$\boldsymbol{\mathrm{hi}},\:\boldsymbol{\mathrm{masters}}\:! \\ $$$$\boldsymbol{\mathrm{look}}\:\boldsymbol{\mathrm{at}}\:\boldsymbol{\mathrm{this}}\:\boldsymbol{\mathrm{thing}}\:\boldsymbol{\mathrm{carefully}}\:: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{1} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{2}\:\mathrm{3}\:\mathrm{4} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{5}\:\mathrm{6}\:\mathrm{7}\:\mathrm{8}\:\mathrm{9} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{10}\:\mathrm{11}\:\mathrm{12}\:\mathrm{13}\:\mathrm{14}\:\mathrm{15}\:\mathrm{16} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{17}\:\mathrm{18}\:\mathrm{19}\:\mathrm{20}\:…………….. \\ $$$$\:\:\:\boldsymbol{\mathrm{find}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{line}}\:\boldsymbol{\mathrm{and}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{column}}\:\boldsymbol{\mathrm{where}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{number}}\:\mathrm{795471}\:\boldsymbol{\mathrm{will}}\:\boldsymbol{\mathrm{appear}}\:! \\…
Question Number 75257 by must1987 last updated on 09/Dec/19 $${Let}\:{A}=\left\{\mathrm{2},\mathrm{4},\mathrm{6},\mathrm{7},\mathrm{8},\mathrm{9}\right\} \\ $$$${B}=\left\{\mathrm{1},\mathrm{3},\mathrm{5},\mathrm{6},\mathrm{10}\right\}\:{and} \\ $$$${C}=\left\{{x}:\mathrm{3}{x}+\mathrm{6}=\mathrm{0}\:{or}\:\mathrm{2}{x}+\mathrm{6}=\mathrm{0}\right\}.{Find} \\ $$$${a}.\:{A}\cup{B}. \\ $$$${b}.\:{is}\left({A}\cup{B}\right)\cup{C}={A}\cup\left({B}\cup{C}\right)? \\ $$ Answered by 21042004 last updated…
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