Question Number 106628 by deep last updated on 06/Aug/20 $$\frac{\left(\boldsymbol{{p}}−\mathrm{1}\right)}{\boldsymbol{{p}}}\:\:\:\:\:\:\boldsymbol{{where}}\:\boldsymbol{{p}}=\boldsymbol{{prime}}\:\boldsymbol{{no}}. \\ $$$$\boldsymbol{{R}}{emainder}\:{will}\:{always}\:{be}\:\left({p}−\mathrm{1}\right)\:{or}\:−\mathrm{1} \\ $$$$ \\ $$$$ \\ $$$${Que}.\:{find}\:{Remainder} \\ $$$$\frac{\mathrm{1}!+\mathrm{2}!+\mathrm{3}!+……………………\mathrm{1000}!}{\mathrm{10}} \\ $$$${Que}. \\ $$$$\frac{\mathrm{1}!+\mathrm{2}!+\mathrm{3}!+……………………\mathrm{1000}!}{\mathrm{12}} \\…
Question Number 171829 by Mikenice last updated on 21/Jun/22 $${please}\:{i}\:{need}\:{cubic}\:{formula} \\ $$$$ \\ $$ Answered by MathematicalUser2357 last updated on 05/Jan/24 $${x}_{\mathrm{1}} =−\frac{{b}}{\mathrm{3}{a}}−\frac{\mathrm{1}}{\mathrm{3}{a}}\sqrt[{\mathrm{3}}]{\frac{\mathrm{2}{b}^{\mathrm{3}} −\mathrm{9}{abc}+\mathrm{27}{a}^{\mathrm{2}} {d}+\sqrt{\left(\mathrm{2}{b}^{\mathrm{3}}…
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Question Number 168534 by ali009 last updated on 12/Apr/22 $$\begin{array}{|c|c|c|c|c|c|c|c|c|}{{a}}&\hline{{b}}&\hline{{c}}&\hline{{v}_{{o}} }\\{\mathrm{0}}&\hline{\mathrm{0}}&\hline{\mathrm{0}}&\hline{\mathrm{1}}\\{\mathrm{0}}&\hline{\mathrm{0}}&\hline{\mathrm{1}}&\hline{\mathrm{1}}\\{\mathrm{0}}&\hline{\mathrm{1}}&\hline{\mathrm{0}}&\hline{\mathrm{1}}\\{\mathrm{0}}&\hline{\mathrm{1}}&\hline{\mathrm{1}}&\hline{\mathrm{0}}\\{\mathrm{1}}&\hline{\mathrm{0}}&\hline{\mathrm{0}}&\hline{\mathrm{0}}\\{\mathrm{1}}&\hline{\mathrm{0}}&\hline{\mathrm{1}}&\hline{\mathrm{0}}\\{\mathrm{1}}&\hline{\mathrm{1}}&\hline{\mathrm{0}}&\hline{\mathrm{0}}\\{\mathrm{1}}&\hline{\mathrm{1}}&\hline{\mathrm{1}}&\hline{\mathrm{0}}\\\hline\end{array} \\ $$$${what}\:{is}\:{the}\:{logic}\:{gate}\:{type}\:{of}\:{this}\:{truth} \\ $$$${table}?? \\ $$ Answered by nikif99 last updated on 13/Apr/22 $${in}\:{boolean}\:{algebra}:…
Question Number 102480 by bemath last updated on 09/Jul/20 $${n}\:{positive}\:{integer}.\:{when} \\ $$$${dividen}\:{by}\:\mathrm{7}\:{give}\:{remainder}\:\mathrm{4} \\ $$$${and}\:{when}\:{divided}\:{by}\:\mathrm{4}\:{give} \\ $$$${remainder}\:\mathrm{2}.\:{find}\:{the}\:{value} \\ $$$${of}\:{n}\: \\ $$ Answered by nimnim last updated…
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Question Number 36450 by Raj Singh last updated on 02/Jun/18 Commented by tanmay.chaudhury50@gmail.com last updated on 02/Jun/18 Commented by ajfour last updated on 03/Jun/18 $${right}!…
Question Number 166982 by null last updated on 04/Mar/22 $$\mathrm{hi}! \\ $$$$\mathrm{help}\:\mathrm{me}! \\ $$$$\underset{{x}\rightarrow\infty} {\mathrm{lim}}\int_{\mathrm{0}} ^{\infty} \mathrm{e}^{\mathrm{2}} \mathrm{c}\sqrt{{x}}\int_{\mathrm{0}} ^{\infty} =? \\ $$ Commented by null…
Question Number 35562 by dgdg123 last updated on 20/May/18 $$\mathrm{Is}\:\mathrm{there}\:\mathrm{a}\:\mathrm{backwards}\:“\Rightarrow''? \\ $$ Commented by Rasheed.Sindhi last updated on 20/May/18 $$\mathrm{click}\:\mathrm{on}“\int\:'',\mathrm{then}\:\mathrm{click}\:\mathrm{on}\:“\trianglerighteq''\mathrm{there} \\ $$$$\mathrm{you}\:\mathrm{can}\:\mathrm{see}\:“\Leftarrow'' \\ $$$$\int\:\:\trianglerighteq\:\Leftarrow \\…
Question Number 100696 by EquationMaker2305 last updated on 28/Jun/20 $$\mathrm{1}.\:\:\:\:\mathrm{25}\neq\mathrm{66}\:=\:\mathrm{True}\:\mathrm{or}\:\mathrm{False}? \\ $$$$\mathrm{2}.\:\:\:\:\mathrm{44}=\mathrm{44}\:=\mathrm{True}\:\mathrm{or}\:\mathrm{false}? \\ $$$$\mathrm{3}.\:\:\:\:\:\mathrm{39}>\mathrm{169}=\mathrm{True}\:\mathrm{or}\:\mathrm{False}? \\ $$$$\mathrm{4}.\:\:\:\:\mathrm{15}<\mathrm{61}\:=\:\mathrm{True}\:\mathrm{or}\:\mathrm{false}? \\ $$$$\: \\ $$$$\mathrm{Make}\:\mathrm{sure}\:\mathrm{you}\:\mathrm{have}\:\mathrm{to} \\ $$$$\mathrm{answer}\:\mathrm{correctly} \\ $$ Commented…